/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 Explain why potassium permangana... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why potassium permanganate \(\left(\mathrm{KMnO}_{4}\right)\) and potassium dichromate \(\left(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\right)\) can serve as internal indicators in redox titrations.

Short Answer

Expert verified
Potassium permanganate (KMnO4) and potassium dichromate (K2Cr2O7) can serve as internal indicators in redox titrations due to their inherent color change at the equivalence point of the reaction. KMnO4 changes from deep purple to colorless/colorless to light pink when reduced, while K2Cr2O7 changes from orange to green when reduced. This color change denotes the end point of the titration, rendering external indicators unnecessary.

Step by step solution

01

Understanding Redox Titration

Redox titration refers to a type of titration based on a redox reaction between the analyte and titrant. It commonly involves the process of oxidation (losing electrons) and reduction (gaining electrons).
02

Understanding Indicators in Titration

In titration, indicators serve the purpose of showing the completion point of the reaction (end point), usually through a color change. The suitable indicator is one that will change color at the equivalence point of the reaction.
03

Role of Potassium Permanganate (KMnO4) as an Internal Indicator

Potassium permanganate is a strong oxidizing agent, with a deep purple color. In the titration, when it acts as an oxidizing agent, it gets reduced to colorless manganese ions (Mn2+). The end point is detected when the solution changes from colorless to a light pink color, indicating the presence of excess potassium permanganate. So, potassium permanganate itself acts as an internal indicator, eliminating the need for an external indicator.
04

Role of Potassium Dichromate (K2Cr2O7) as an Internal Indicator

Similarly, potassium dichromate is also a strong oxidizing agent, with an orange color. In the reaction, it gets reduced to green chromium ions (Cr3+). The color change from orange to green denotes the end point of the titration. Just like KMnO4, potassium dichromate also serves as its own indicator, annuling the need for external ones.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Titration Indicators
In titrations, which are laboratory methods for figuring out the concentration of an unknown solution, indicators are crucial. They visibly signal the completion of the reaction by changing color, allowing chemists to determine when the titration has reached its equivalence point—the point at which the amount of titrant equals the amount of substance in the sample being analyzed.

Indicators are carefully chosen to have a clear and distinct color change at the equivalence point. This change occurs because of a shift in pH or, in the case of redox titrations, an excess of the titrant. The appropriate indicator for any given titration depends on the reaction conditions and the specific chemicals involved.
Potassium Permanganate as an Internal Indicator
Potassium permanganate ((KMnO_4)) is a potent oxidizer famous for its intense purple hue. In redox titrations, it is often the titrant when analyzing substances like iron or hydrogen peroxide. During the titration, (KMnO_4) acts as an oxidizing agent and gets reduced to colorless (Mn^{2+}) ions when it reacts with the analyte.

As soon as there is a slight excess of (KMnO_4) in the solution, a faint pink color persists, which does not disappear upon stirring. This permanent pink color indicates that the analyte has been fully oxidized, marking the endpoint. Thus, (KMnO_4) itself is an internal indicator, simplifying the process by eliminating the need for an additional external indicator.
Potassium Dichromate as an Internal Indicator
Potassium dichromate ((K_2Cr_2O_7)) is another strong oxidizing agent used in redox titrations, known for its vivid orange color. In its role as an internal indicator, it undergoes a reduction during the titration, transitioning from orange-colored dichromate ions ((Cr_2O_7^{2-})) to green chromium ions ((Cr^{3+})).

This color change is highly visible and thus provides a clear indication of the endpoint. The shift from orange to green indicates the analyte has been fully reduced by the dichromate. Similar to (KMnO_4), (K_2Cr_2O_7) eliminates the need for an external indicator, since the solution's color change is ample evidence of the titration's completion.
Oxidation and Reduction in Titration
In redox titrations, the concepts of oxidation and reduction are fundamental. Oxidation refers to the loss of electrons by a substance, while reduction refers to the gain of electrons. These processes occur simultaneously during a redox reaction; one species is oxidized while another is reduced. This is also described as an electron transfer process.

In the context of titration, the titrant causes either oxidation or reduction of the analyte until the end point is reached, signaling that the stoichiometrically correct amount of titrant has been added. A successful redox titration requires that the oxidation reaction is complete and that there is a clear change—either in the electrical potential for potentiometric titrations or a color change for visual ones—to signal the end point.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

On standing, a concentrated nitric acid gradually turns yellow. Explain. (Hint: Nitric acid slowly decomposes. Nitrogen dioxide is a colored gas.)

What volume of a \(0.500 M\) HCl solution is needed to neutralize each of the following? (a) \(10.0 \mathrm{~mL}\) of a \(0.300 \mathrm{M} \mathrm{NaOH}\) solution (b) \(10.0 \mathrm{~mL}\) of a \(0.200 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) solution

Give a chemical explanation for each of the following: (a) When calcium metal is added to a sulfuric acid solution, hydrogen gas is generated. After a few minutes, the reaction slows down and eventually stops even though none of the reactants is used up. (b) In the activity series, aluminum is above hydrogen, yet the metal appears to be unreactive toward steam and hydrochloric acid. (c) Sodium and potassium lie above copper in the activity series. In your explanation, discuss why \(\mathrm{Cu}^{2+}\) ions in a \(\mathrm{CuSO}_{4}\) solution are not converted to metallic copper upon the addition of these metals. (d) A metal M reacts slowly with steam. There is no visible change when it is placed in a pale green iron(II) sulfate solution. Where should we place \(\mathrm{M}\) in the activity series? (e) Before aluminum metal was obtained by electrolysis, it was produced by reducing its chloride \(\left(\mathrm{AlCl}_{3}\right)\) with an active metal. What metals would you use to produce aluminum in that way?

Describe the steps involved in preparing a solution of known molar concentration using a volumetric flask.

Describe how you would prepare \(250 \mathrm{~mL}\) of a \(0.707 M \mathrm{NaNO}_{3}\) solution.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.