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Characterize the following compounds as soluble or insoluble in water: (a) \(\mathrm{CaCO}_{3}\), (b) \(\mathrm{ZnSO}_{4}\), (c) \(\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2},\) (d) \(\mathrm{HgSO}_{4}\), (e) \(\mathrm{NH}_{4} \mathrm{ClO}_{4}\).

Short Answer

Expert verified
\(\mathrm{CaCO}_{3}\) and \(\mathrm{HgSO}_{4}\) are insoluble in water, while \(\mathrm{ZnSO}_{4}\), \(\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2}\) and \(\mathrm{NH}_{4} \mathrm{ClO}_{4}\) are soluble.

Step by step solution

01

Revisiting Solubility Rules

Let us recall few general rules of solubility: \n1. All Nitrates \(\left(NO_{3}^{-}\right)\), Acetates \(\left(CH_{3}COO^{-}\right)\), and most Perchlorates \(\left(ClO_{4}^{-}\right)\) are soluble. \n2. All salts of alkali metals \(Li^{+}, Na^{+}, K^{+}, Cs^{+}, Rb^{+}\) and Ammonium ion \(NH_{4}^{+}\) are soluble. \n3. The halides, chlorides, bromides and iodides are all soluble except Silver (Ag), Lead (Pb), and Mercury (Hg). \n4. All Sulfates \(\left(SO_{4}^{2-}\right)\) are soluble, except those of Barium (Ba), Strontium (Sr), Lead (Pb), Calcium (Ca), and Mercury (Hg). \n5. Unless they are attached to an alkali metal or Ammonium ion, Carbonates \(\left(CO_{3}^{2-}\right)\), Phosphates, Oxalates, Chromates, and Silicates are insoluble.
02

Characterizing \(\mathrm{CaCO}_{3}\)

Applying rule 5, Calcium Carbonate \(\mathrm{CaCO}_{3}\) is insoluble because Carbonates are generally insoluble except when attached to an alkali metal or Ammonium ion.
03

Characterizing \(\mathrm{ZnSO}_{4}\)

Following rule 4, Zinc Sulfate \(\mathrm{ZnSO}_{4}\) is soluble because all Sulfates are soluble except for Barium, Strontium, Lead, Calcium, and Mercury, of which Zinc is not a part.
04

Characterizing \(\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2}\)

According to rule 1, Mercury(II) Nitrate \(\mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2}\) is soluble because all Nitrates are soluble.
05

Characterizing \(\mathrm{HgSO}_{4}\)

As per rule 4, Mercury(II) Sulfate \(\mathrm{HgSO}_{4}\) is insoluble because Mercury is in the exceptions for solubility of Sulfates.
06

Characterizing \(\mathrm{NH}_{4} \mathrm{ClO}_{4}\)

According to rule 2 and 1, Ammonium Perchlorate \(\mathrm{NH}_{4} \mathrm{ClO}_{4}\) is soluble because all salts of Ammonium ion and most Perchlorates are soluble.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility of Compounds
Understanding the solubility of compounds in water is essential for predicting their behavior in aqueous solutions. Solubility rules serve as a guide to determine whether a substance will dissolve or form a precipitate.

Solubility is not an all-or-nothing phenomenon but varies in degree. Essentially, a compound's solubility is the result of the interplay between the forces holding the compound's ions together and the attraction between these ions and water molecules. This concept becomes vital when making predictions in chemical reactions, as it impacts how molecules and ions interact.

When characterizing compounds like \textbf{CaCO}\(_3\)\textbf{ and }\textbf{HgSO}\(_4\)\textbf{, we can apply specific solubility rules. For instance, a rule states that carbonates (}\textbf{CO}\(_3^{2-}\)\textbf{) are usually insoluble, which is why calcium carbonate }\textbf{CaCO}\(_3\)\textbf{ does not dissolve in water. Similarly, despite sulfates (}\textbf{SO}\(_4^{2-}\)\textbf{) generally being soluble, there are exceptions like mercury(II) sulfate }\textbf{HgSO}\(_4\)\textbf{, which is insoluble due to the presence of mercury. These guidelines provide invaluable help to students and chemists alike when predicting the outcome of mixing various compounds with water.

By familiarizing themselves with these rules, students can quickly identify whether a substance will dissolve in water, shaping the pathway of chemical reactions and influencing experimental outcomes.
Chemical Properties of Substances
The chemical properties of substances are intrinsic characteristics that dictate how they react with other materials. These properties are fundamentally determined by the types and arrangements of atoms within a substance, and they give rise to behaviors observed during chemical reactions, such as reactivity with acids, bases, oxidation states, and solubility.

An understanding of these properties is crucial when we examine the solubility of compounds like \textbf{NH}\(_4\)\textbf{ClO}\(_4\)\textbf{ and }\textbf{ZnSO}\(_4\)\textbf{. The ammonium ion (}\textbf{NH}\(_4^+\)\textbf{) is a unique cation with a propensity for forming soluble compounds in water due to its ability to create strong interactions with water molecules. As a result, }\textbf{NH}\(_4\)\textbf{ClO}\(_4\)\textbf{, containing the ammonium ion, is soluble. Conversely, }\textbf{ZnSO}\(_4\)\textbf{ illustrates the rule that sulfates are typically soluble unless paired with certain cations like barium or mercury. These chemical properties guide the predictability and course of chemical reactions.

By learning about these properties, students gain deeper insight into how different chemical species will likely behave when mixed in water, leading to improved understanding of reaction outcomes and better experimental design.
Aqueous Solution Reactions
Aqueous solution reactions are processes in which the reactants are dissolved in water, leading to a range of outcomes, including precipitation, acid-base neutralization, or redox reactions. The solubility of compounds involved directly affects how these reactions progress.

For example, a precipitation reaction can occur when two soluble salts are mixed in water and produce an insoluble compound, which settles out of the solution as a precipitate. Understanding the solubility rules helps predict whether mixing solutions of \textbf{Hg(NO}\(_3\)\textbf{)}\(_2\)\textbf{ and }\textbf{NH}\(_4\)\textbf{ClO}\(_4\)\textbf{ will lead to a precipitate. Since both compounds are soluble, no precipitation will form in this instance. In contrast, if a solution containing }\textbf{Hg(NO}\(_3\)\textbf{)}\(_2\)\textbf{ were mixed with a salt that forms an insoluble mercury compound, a precipitate would be expected.

Grasping aqueous solution reactions is imperative for students because it forms the foundation of understanding real-world applications like water treatment, where precipitation is used to remove unwanted ions from water, or in medicinal chemistry, where the solubility of drugs in body fluids is a crucial property for their effectiveness.

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Most popular questions from this chapter

Give a chemical explanation for each of the following: (a) When calcium metal is added to a sulfuric acid solution, hydrogen gas is generated. After a few minutes, the reaction slows down and eventually stops even though none of the reactants is used up. (b) In the activity series, aluminum is above hydrogen, yet the metal appears to be unreactive toward steam and hydrochloric acid. (c) Sodium and potassium lie above copper in the activity series. In your explanation, discuss why \(\mathrm{Cu}^{2+}\) ions in a \(\mathrm{CuSO}_{4}\) solution are not converted to metallic copper upon the addition of these metals. (d) A metal M reacts slowly with steam. There is no visible change when it is placed in a pale green iron(II) sulfate solution. Where should we place \(\mathrm{M}\) in the activity series? (e) Before aluminum metal was obtained by electrolysis, it was produced by reducing its chloride \(\left(\mathrm{AlCl}_{3}\right)\) with an active metal. What metals would you use to produce aluminum in that way?

Water is added to \(25.0 \mathrm{~mL}\) of a \(0.866 \mathrm{M} \mathrm{KNO}_{3}\) solution until the volume of the solution is exactly \(500 \mathrm{~mL}\). What is the concentration of the final solution?

The concentration of sulfate in water can be determined by adding a solution of barium chloride to precipitate the sulfate ion. Write the net ionic equation for this reaction. Treating a 145-mL sample of water with excess \(\mathrm{BaCl}_{2}(a q)\) precipitated \(0.330 \mathrm{~g}\) of \(\mathrm{BaSO}_{4} .\) Determine the concentration of sulfate in the original water sample.

An ionic compound \(\mathrm{X}\) is only slightly soluble in water. What test would you employ to show that the compound does indeed dissolve in water to a certain extent?

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is present in many plants and vegetables. If \(24.0 \mathrm{~mL}\) of \(0.0100 \mathrm{M} \mathrm{KMnO}_{4}\) solution is needed to titrate \(1.00 \mathrm{~g}\) of a sample of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) to the equivalence point, what is the percent by mass of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) in the sample? The net ionic equation is \(2 \mathrm{MnO}_{4}^{-}+16 \mathrm{H}^{+}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow\) \(2 \mathrm{Mn}^{2+}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}\)

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