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Chemical tests of four metals \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) show the following results. (a) Only \(\mathrm{B}\) and \(\mathrm{C}\) react with \(0.5 \mathrm{M} \mathrm{HCl}\) to give \(\mathrm{H}_{2}\) gas. (b) When \(\mathrm{B}\) is added to a solution containing the ions of the other metals, metallic \(\mathrm{A}, \mathrm{C},\) and \(\mathrm{D}\) are formed. (c) A reacts with \(6 M \mathrm{HNO}_{3}\) but \(\mathrm{D}\) does not. Arrange the metals in the increasing order as reducing agents. Suggest four metals that fit these descriptions.

Short Answer

Expert verified
The arrangement of the metals as reducing agents in order of increasing reactivity would be: D < A < C < B. One possible identification for the metals would be Gold as D, Aluminium as A, Magnesium as C, and Sodium as B.

Step by step solution

01

– Identification of the most reactive metal

From information given when component B is added to a solution containing the ions of all other metals, metals A, C and D are formed. It suggests that B has displaced A, C and D from their solutions, therefore, B is the most reactive metal.
02

– Least reactive metal identification

From the given information, metal A reacts with \(6 M HNO_{3}\) while D does not. Therefore, D is the least reactive as it did not react with the nitric acid solution.
03

– Ranking the remaining metals

If we reference the properties of known metallic elements, only metals B and C react with \(0.5 M HCl\) to give \(H_{2}\) gas. The fact that A doesn't react with \(HCl\) reveals that it is less reactive than B and C. Therefore, the order of reactivity is B > C > A > D.
04

– Assigning metals to fit these descriptions

There are several possible answers based on the reactivity series of metals. Here's one possibility: we can label Sodium (Na) as B (most reactive), Magnesium (Mg) as C, Aluminium (Al) as A, and Gold (Au) as D (least reactive). Sodium and Magnesium react with weak \(HCl\) solution, Aluminium reacts with \(HNO_{3}\) while gold does not react with any of these solutions, conforming to the descriptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactivity
Understanding chemical reactivity is crucial for predicting how different substances will interact. At its most basic, chemical reactivity refers to the tendency of a substance to engage in chemical reactions. Reactivity is influenced by various factors such as electron configurations, the presence of certain functional groups, and the position of an element in the periodic table.

In the context of metals, which are typically found on the left side of the periodic table, reactivity can be understood in terms of how readily a metal can lose electrons to form positive ions (cations) and combine with other elements. Reactive metals, like those in Group 1 (the alkali metals), have a strong tendency to donate their outermost electrons.

Conversely, metals like gold, which are found closer to the bottom of the group 11 elements, have a much lower reactivity. They are less willing to lose electrons and react with other substances. This property of gold makes it an excellent choice for jewelry and electronic components, as it doesn't tarnish or corrode easily.
Displacement Reactions
Displacement reactions are a type of chemical reaction where an element in a compound is replaced by another element that is more reactive. In the exercise at hand, the reactivity of metals determines which ones can displace others from their compounds.

Think of it as a game of musical chairs where more reactive metals can 'push out' less reactive ones from a solution. For instance, when metal B is added to a solution containing ions of metals A, C, and D, only the more reactive metal (in this case, B) can replace the others, forming free metallic A, C, and D.

These reactions are wonderfully predictive; once you know the reactivity series, you can determine the outcome of such mixtures without even performing the experiment. Understanding displacement reactions empowers students and chemists alike to anticipate the behavior of various metals when combined, which is invaluable in laboratory and industrial processes.
Activity Series
The activity series, sometimes called the reactivity series, is a chart that lists elements in order of decreasing reactivity. For metals, this series is instrumental in predicting which metal will displace another in a single displacement reaction.

An easy way to remember this is the higher up on the series, the more 'pushy' the metal is, meaning it can displace metals below it from their compounds. In our exercise, we established an activity series with B as the most reactive and D as the least based on their reactions with acid solutions.

The activity series is not just theoretical; it's widely used in practical chemistry. For example, it can help predict which metal to use in a galvanic cell for battery production, or which metals should be used in construction to prevent corrosion. Knowing where a metal stands in this series can also inform environmental measures, like removing heavy metals from water systems since more reactive metals can displace less reactive, potentially toxic ones from solutions.

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Most popular questions from this chapter

The recommended procedure for preparing a very dilute solution is not to weigh out a very small mass or measure a very small volume of a stock solution. Instead, it is done by a series of dilutions. A sample of \(0.8214 \mathrm{~g}\) of \(\mathrm{KMnO}_{4}\) was dissolved in water and made up to the volume in a 500-mL volumetric flask. A \(2.000-\mathrm{mL}\) sample of this solution was transferred to a \(1000-\mathrm{mL}\) volumetric flask and diluted to the mark with water. Next, \(10.00 \mathrm{~mL}\) of the diluted solution were transferred to a \(250-\mathrm{mL}\) flask and diluted to the mark with water. (a) Calculate the concentration (in molarity) of the final solution. (b) Calculate the mass of \(\mathrm{KMnO}_{4}\) needed to directly prepare the final solution.

(a) Describe a preparation for magnesium hydroxide \(\left[\mathrm{Mg}(\mathrm{OH})_{2}\right]\) and predict its solubility. (b) Milk of magnesia contains mostly \(\mathrm{Mg}(\mathrm{OH})_{2}\) and is effective in treating acid (mostly hydrochloric acid) indigestion. Calculate the volume of a \(0.035 \mathrm{M} \mathrm{HCl}\) solution (a typical acid concentration in an upset stomach) needed to react with two spoonfuls (approximately \(10 \mathrm{~mL}\) ) of milk of magnesia [at \(0.080 \mathrm{~g}\) \(\left.\mathrm{Mg}(\mathrm{OH})_{2} / \mathrm{mL}\right]\).

On the basis of oxidation number considerations, one of the following oxides would not react with molecular oxygen: \(\mathrm{NO}, \mathrm{N}_{2} \mathrm{O}, \mathrm{SO}_{2}, \mathrm{SO}_{3}, \mathrm{P}_{4} \mathrm{O}_{6}\) Which one is it? Why?

Give the oxidation number of the underlined atoms in the following molecules and ions: (a) \(\mathrm{Mg}_{3} \underline{\mathrm{N}}_{2}\) (b) \(\mathrm{CsO}_{2},\) (c) \(\mathrm{CaC}_{2}\), (d) \(\underline{\mathrm{CO}}_{3}^{2-}\), (e) \(\underline{\mathrm{C}}_{2} \mathrm{O}_{4}^{2-}\) (f) \(\mathrm{Zn} \underline{\mathrm{O}}_{2}^{2-}\) \((\mathrm{g}) \mathrm{NaBH}_{4},(\mathrm{~h}) \underline{\mathrm{W}} \mathrm{O}_{4}^{2-}\)

Hydrochloric acid is not an oxidizing agent in the sense that sulfuric acid and nitric acid are. Explain why the chloride ion is not a strong oxidizing agent like \(\mathrm{SO}_{4}^{2-}\) and \(\mathrm{NO}_{3}^{-}\).

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