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Why must a chemical equation be balanced? What law is obeyed by a balanced chemical equation?

Short Answer

Expert verified
A chemical equation must be balanced to comply with the Law of Conservation of Mass, which states that matter cannot be created or destroyed in an isolated system. Therefore, the law that is obeyed by a balanced chemical equation is the Law of Conservation of Mass.

Step by step solution

01

Concept of Balanced Chemical Equations

A chemical equation demonstrates chemical reactions with reactants on the left (what goes into the reaction) and products on the right (what comes out of the reaction). For instance, a chemical reaction is given by: \(2H_2 + O_2 → 2H_2O\). Here, the reactants are \(H_2\) and \(O_2\), and the product is \(H_2O\). A balanced chemical equation would ensure that for every atom of reactant(s) that we start with, we end up with the same amount of atom(s) in the product(s).
02

Reason for Balancing Chemical Equations

The reason for balancing chemical equations is to comply with the Law of Conservation of Mass, which states that matter cannot be created or destroyed in an isolated system. A chemical reaction just changes the way atoms are arranged. So, the number of atoms for each element before the reaction must be the same after the reaction. Chemical equations demonstrate reaction stoichiometry, which is the quantitative relation between reactants and products in a chemical reaction.
03

Law Obeyed by a Balanced Chemical Equation

A balanced chemical equation obeys the Law of Conservation of Mass. In other words, the total mass of the reactants will equal the total mass of the products. This implies that in balanced chemical reactions, the number and type of atoms are preserved.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Conservation of Mass
The Law of Conservation of Mass is a fundamental principle in chemistry that states matter cannot be created or destroyed. This law is essential, especially when it comes to chemical reactions. During any chemical process, the quantity of matter remains the same, even though its form may change. This means that when substances are transformed in a chemical reaction, the total mass of the reactants (the starting substances) must equal the total mass of the products (the resulting substances).
This law implies a consistent matter distribution, ensuring that atom counts before and after a reaction remain equal. Balance in chemical equations reflects this balance of mass, making sure each element's atoms are equal in both reactants and products.
Understanding this law helps you appreciate why balancing equations is a must. It ensures that you're accurately portraying what happens to the matter during the reaction and adhering to the natural laws of physics and chemistry.
Chemical Reactions
Chemical reactions are processes that involve the rearrangement of the atoms of one or more substances to create new substances. These reactions are depicted using chemical equations, displaying the reactants and products.
In simple terms, reactants are what you start with, and products are what you end up with once the reaction is completed. For instance, in the reaction \(2H_2 + O_2 \rightarrow 2H_2O\), \(H_2\) and \(O_2\) are reactants, and \(H_2O\) is the product.
Different types of reactions exist, including synthesis, decomposition, single replacement, and double replacement, each with unique characteristics. What's common is that during these reactions, only the arrangement of atoms changes. No new atoms are created or existing ones destroyed, which circles back to the Law of Conservation of Mass.
Recognizing the type of reaction helps in predicting the products and writing balanced chemical equations, which visually enforce mass conservation.
Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It allows us to predict how much of each substance is needed or produced. This concept utilizes the balanced chemical equation to provide a quantitative relationship between substances involved in the reaction.
In a balanced equation, coefficients (numbers in front of molecules) tell us the proportion of each substance required. Using the example, \(2H_2 + O_2 \rightarrow 2H_2O\), the coefficients indicate you need twice as many moles of hydrogen as oxygen to fully react and produce water.
Stoichiometry is fundamental for ensuring reactions proceed correctly. It helps chemists scale reactions up or down while maintaining the correct ratios of reactants and products. Calculations often involve using molar masses and Avogadro's number, making precise measurements possible.
Through stoichiometry, we achieve a deeper comprehension of the chemical processes, making it invaluable for experiments and industrial applications.

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Most popular questions from this chapter

Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide \(\left(\mathrm{NO}_{2}\right)\), a dark-brown gas: $$2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)$$ In one experiment 0.886 mole of NO is mixed with 0.503 mole of \(\mathrm{O}_{2}\). Calculate which of the two reactants is the limiting reactant. Calculate also the number of moles of \(\mathrm{NO}_{2}\) produced.

When heated, lithium reacts with nitrogen to form lithium nitride: $$6 \mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{Li}_{3} \mathrm{~N}(s)$$What is the theoretical yield of \(\mathrm{Li}_{3} \mathrm{~N}\) in grams when \(12.3 \mathrm{~g}\) of \(\mathrm{Li}\) are heated with \(33.6 \mathrm{~g}\) of \(\mathrm{N}_{2} ?\) If the actual yield of \(\mathrm{Li}_{3} \mathrm{~N}\) is \(5.89 \mathrm{~g},\) what is the percent yield of the reaction?

Ethylene reacts with hydrogen chloride to form ethyl chloride: $$\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{HCl}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g) $$Calculate the mass of ethyl chloride formed if \(4.66 \mathrm{~g}\) of ethylene reacts with an 89.4 percent yield.

Allicin is the compound responsible for the characteristic smell of garlic. An analysis of the compound gives the following percent composition by mass: C: 44.4 percent, \(\mathrm{H}: 6.21\) percent, \(\mathrm{S}: 39.5\) percent, \(\mathrm{O}:\) 9.86 percent. Calculate its empirical formula. What is its molecular formula given that its molar mass is about \(162 \mathrm{~g}\) ?

Because of its detrimental effect on the environment, the lead compound described in Problem 3.148 has been replaced by methyl tert-butyl ether (a compound of \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O}\) ) to enhance the performance of gasoline. (This compound is also being phased out because of its contamination of drinking water.) When \(12.1 \mathrm{~g}\) of the compound are burned in an apparatus like the one shown in Figure \(3.6,30.2 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(14.8 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) are formed. What is the empirical formula of the compound?

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