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The anticaking agent added to Morton salt is calcium silicate, CaSiO \(_{3}\). This compound can absorb up to 2.5 times its mass of water and still remain a free-flowing powder. Calculate the percent composition of \(\mathrm{CaSiO}_{3}\).

Short Answer

Expert verified
The percent composition of CaSiO\(_3\) is 34.50% Calcium (Ca), 24.18% Silicon (Si), and 41.32% Oxygen (O).

Step by step solution

01

Determine the Atomic Masses from the Periodic Table

The atomic masses of calcium (Ca), silicon (Si), and oxygen (O) are 40.08 g/mol, 28.09 g/mol, and 16.00 g/mol, respectively. Therefore, the molar mass of CaSiO\(_3\) is calculated by adding the atomic masses of all the atoms in the formula: (1 x 40.08) + (1 x 28.09) + (3 x 16.00) = 116.17 g/mol.
02

Calculate the Percent Composition of Each Element

Next, compute the percent composition of each element:- Percent composition of Ca = ((1 x 40.08) / 116.17) x 100% = 34.50%- Percent composition of Si = ((1 x 28.09) / 116.17) x 100% = 24.18%- Percent composition of O = ((3 x 16.00) / 116.17) x 100% = 41.32%
03

Summarize the Result

In the compound CaSiO\(_3\), the percent composition of Calcium (Ca) is 34.50%, Silicon (Si) is 24.18%, and Oxygen (O) is 41.32%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Mass
Atomic mass is a fundamental concept in chemistry and plays a key role in calculating the composition of compounds. It refers to the mass of an atom, typically measured in atomic mass units (amu). This mass is determined primarily by the protons and neutrons in the nucleus, as electrons have negligible mass.

Each element on the periodic table has an atomic mass, which can often be found under the symbol of the element. For instance:
  • Calcium (Ca) has an atomic mass of 40.08 g/mol.
  • Silicon (Si) has an atomic mass of 28.09 g/mol.
  • Oxygen (O) has an atomic mass of 16.00 g/mol.
These atomic masses are essential for calculating the molar mass of compounds, as they provide the necessary weights of each constituent atom. Understanding atomic mass allows chemists to determine the proportions of different elements within a compound and calculate other related properties, such as percent composition.
Calcium Silicate
Calcium silicate, known chemically as CaSiO\(_3\), is a compound frequently used in various applications due to its remarkable properties. One of its significant uses is as an anticaking agent, which helps in preventing clumping in powdered products such as salt.

One impressive feature of calcium silicate is its ability to absorb water up to 2.5 times its own mass while remaining a free-flowing powder. This property makes it invaluable in maintaining the texture and flowability of products subjected to moisture.
  • It consists of one calcium atom (Ca), one silicon atom (Si), and three oxygen atoms (O).
  • The absorption characteristic is particularly beneficial in food and other industrial applications where moisture control is crucial.
The structure of calcium silicate plays a vital role in its efficiency as an additive and its ability to maintain the quality of diverse products.
Molar Mass Calculation
Calculating the molar mass of a compound is a critical step in determining its percent composition. The molar mass is the mass of one mole of a given substance, usually expressed in grams per mole (g/mol).

To find the molar mass of calcium silicate (CaSiO\(_3\)), we sum up the atomic masses of all the atoms present in the compound:
  • Calcium: 1 atom x 40.08 g/mol = 40.08 g/mol
  • Silicon: 1 atom x 28.09 g/mol = 28.09 g/mol
  • Oxygen: 3 atoms x 16.00 g/mol = 48.00 g/mol
Adding these values yields a total molar mass of 116.17 g/mol for CaSiO\(_3\).

Understanding how to calculate the molar mass is essential, as it serves as a foundation for determining the percent composition of each element within a compound, helping scientists and students alike quantify the elements involved.

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Most popular questions from this chapter

Without doing any detailed calculations, arrange the following substances in the increasing order of number of moles: \(20.0 \mathrm{~g} \mathrm{Cl}, 35.0 \mathrm{~g} \mathrm{Br},\) and\(94.0 \mathrm{~g} \mathrm{I}\)

A sample containing \(\mathrm{NaCl}, \mathrm{Na}_{2} \mathrm{SO}_{4},\) and \(\mathrm{NaNO}_{3}\) gives the following elemental analysis: Na: 32.08 percent; O: 36.01 percent; Cl: 19.51 percent. Calculate the mass percent of each compound in the sample.

The formula of a hydrate of barium chloride is \(\mathrm{BaCl}_{2} \cdot x \mathrm{H}_{2} \mathrm{O} .\) If \(1.936 \mathrm{~g}\) of the compound gives\(1.864 \mathrm{~g}\) of anhydrous \(\mathrm{BaSO}_{4}\) upon treatment with sulfuric acid, calculate the value of \(x\).

Ammonia and sulfuric acid react to form ammonium sulfate. (a) Write an equation for the reaction. (b) Determine the starting mass (in grams) of each reactant if \(20.3 \mathrm{~g}\) of ammonium sulfate is produced and \(5.89 \mathrm{~g}\) of sulfuric acid remains unreacted.

Nitroglycerin \(\left(\mathrm{C}_{3} \mathrm{H}_{5} \mathrm{~N}_{3} \mathrm{O}_{9}\right)\) is a powerful explosive. Its decomposition may be represented by$$4 \mathrm{C}_{3} \mathrm{H}_{5} \mathrm{~N}_{3} \mathrm{O}_{9} \longrightarrow 6 \mathrm{~N}_{2}+12 \mathrm{CO}_{2}+10 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2} $$This reaction generates a large amount of heat and many gaseous products. It is the sudden formation of these gases, together with their rapid expansion, that produces the explosion. (a) What is the maximum amount of \(\mathrm{O}_{2}\) in grams that can be obtained from \(2.00 \times 10^{2} \mathrm{~g}\) of nitroglycerin? (b) Calculate the percent yield in this reaction if the amount of \(\mathrm{O}_{2}\) generated is found to be \(6.55 \mathrm{~g}\).

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