Chapter 14: Problem 42
At \(1000 \mathrm{~K},\) a sample of pure \(\mathrm{NO}_{2}\) gas decomposes: $$2 \mathrm{NO}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)$$ The equilibrium constant \(K_{P}\) is \(158 .\) Analysis shows that the partial pressure of \(\mathrm{O}_{2}\) is 0.25 atm at equilibrium. Calculate the pressure of \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) in the mixture.
Short Answer
Step by step solution
Initial guess of partial pressures
Calculate the pressure of \(NO_2\) at equilibrium
Apply the definition of the equilibrium constant \(K_P\)
Solve for \(P\)
Calculate the pressure of \(NO\) at equilibrium
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Pressure in Reactions
Understanding Chemical Equilibrium
Gas Reactions and Equilibrium Constants
- The equation takes the partial pressures and raises them to the power of their coefficients in the balanced equation.
- Substituting known pressures in \(2 \mathrm{NO}_2(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{O}_2(g)\), we determine the pressures at equilibrium.
The Decomposition of NO2
- This balance depends heavily on factors like pressure and temperature.
- The initial pressure \(P\) influences how much \(NO_2\) breaks down.