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Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of products: (a) \(\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \longrightarrow 2 \mathrm{HI}(g)\) (b) \(5 \mathrm{Br}^{-}(a q)+\mathrm{BrO}_{3}^{-}(a q)+6 \mathrm{H}^{+}(a q) \longrightarrow\) $$ 3 \mathrm{Br}_{2}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) $$

Short Answer

Expert verified
The rate of reaction (a) in terms of the disappearance of H2 and I2 or the appearance of HI is given as \( -\frac{1}{2}\frac{d[\mathrm{H}_{2}]}{dt} = -\frac{1}{2}\frac{d[\mathrm{I}_{2}]}{dt} = \frac{d[\mathrm{HI}]}{dt} \) and the rate of reaction (b) in terms of disappearance of the reactants Br-, BrO3- and H+ and formation of the products Br2 and H2O is given as \(-\frac{1}{5}\frac{d[\mathrm{Br}^-]}{dt} = -\frac{d[\mathrm{BrO}_{3}^-]}{dt} = -\frac{1}{6}\frac{d[\mathrm{H}^+]}{dt} = \frac{1}{3}\frac{d[\mathrm{Br}_2]}{dt} = \frac{1}{3}\frac{d[\mathrm{H}_2\mathrm{O}]}{dt}\)

Step by step solution

01

Write the rate expression for reaction (a)

In reaction (a) we have to divide the change in concentration of a reactant or product by the stoichiometric coefficient. In this case, the rate of reaction can be written in terms of the disappearance of H2 and I2 or the appearance of HI. If the reaction is proceeding in the direction as written, the rate can be expressed as follows: \( -\frac{1}{2}\frac{d[\mathrm{H}_{2}]}{dt} = -\frac{1}{2}\frac{d[\mathrm{I}_{2}]}{dt} = \frac{d[\mathrm{HI}]}{dt} \)
02

Write the rate expression for reaction (b)

Similarly, for reaction (b), we divide the change in concentration of each reactant or product by its stoichiometric coefficient. The rate can be expressed in terms of disappearance of the reactants Br-, BrO3- and H+ or the appearance of the products Br2 and H2O. If the reaction is proceeding in the direction as written, the rate can be expressed as follows: \(-\frac{1}{5}\frac{d[\mathrm{Br}^-]}{dt} = -\frac{d[\mathrm{BrO}_{3}^-]}{dt} = -\frac{1}{6}\frac{d[\mathrm{H}^+]}{dt} = \frac{1}{3}\frac{d[\mathrm{Br}_2]}{dt} = \frac{1}{3}\frac{d[\mathrm{H}_2\mathrm{O}]}{dt}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Reaction
In chemistry, the **rate of reaction** refers to how quickly or slowly reactants transform into products during a chemical reaction. It's an important concept because it allows us to understand how different conditions, like temperature or concentration, affect the speed of a reaction. The rate is typically expressed as the change in concentration of a reactant or product per unit time. For a reaction involving substances A and B forming product C, the rate expression can be given by \( \frac{d[C]}{dt} = - \frac{d[A]}{dt} = - \frac{d[B]}{dt} \).
You see, the rate of reaction is a measure of either the appearance of products or the disappearance of reactants. Each part of this equation can help scientists and students predict and control how fast a reaction occurs, which is crucial for many practical applications.
Stoichiometric Coefficients
**Stoichiometric coefficients** are the numbers written in front of molecules in a balanced chemical equation. They play a key role because they indicate the proportion in which reactants combine and products form. For example, in the equation \(\mathrm{H}_{2} + \mathrm{I}_{2} \longrightarrow 2 \mathrm{HI}\), the stoichiometric coefficients are 1 for \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\), and 2 for \(\mathrm{HI}\).
These coefficients tell us that one molecule of \(\mathrm{H}_{2}\) reacts with one molecule of \(\mathrm{I}_{2}\) to produce two molecules of \(\mathrm{HI}\). To write the rate expression, you divide the rate of change in concentration by these coefficients. This ensures consistency and accuracy, allowing the rate to reflect the proportional changes among all species in the reaction. This is why the rate expressions involve dividing by stoichiometric coefficients, ensuring that they accurately represent the dynamics of the reaction.
Disappearance and Appearance in Reactions
In any chemical reaction, some substances **disappear** as reactants while others **appear** as products. This process is a central aspect of how chemical reactions are described and analyzed. The reaction rate can be explained in terms of either the disappearance of reactants or the appearance of products.
Take the reaction \(\mathrm{H}_{2}(g) + \mathrm{I}_{2}(g) \longrightarrow 2 \mathrm{HI}(g)\). Here, \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) are disappearing as they are consumed, while \(\mathrm{HI}\) is appearing as it forms. The rate expressions relate these changes using the stoichiometric coefficients, such as \( -\frac{1}{2}\frac{d[\mathrm{H}_{2}]}{dt} = \frac{d[\mathrm{HI}]}{dt} \).
This means for every two molecules of \(\mathrm{HI}\) that appear, one molecule of \(\mathrm{H}_{2}\) disappears. Understanding these expressions helps clarify how much of each reactant is used up and how much of each product is created, offering a clear pathway to comprehend the full picture of a chemical reaction.

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Most popular questions from this chapter

Specify which of the following species cannot be isolated in a reaction: activated complex, product, intermediate.

Some reactions are described as parallel in that the reactant simultaneously forms different products with different rate constants. An example is and $$ \begin{array}{l} \mathrm{A} \stackrel{k_{1}}{k_{2}} \mathrm{~B} \\ \mathrm{~A} \stackrel{\longrightarrow}{\longrightarrow} \mathrm{C} \end{array} $$ The activation energies are \(45.3 \mathrm{~kJ} / \mathrm{mol}\) for \(k_{1}\) and \(69.8 \mathrm{~kJ} / \mathrm{mol}\) for \(k_{2}\). If the rate constants are equal at \(320 \mathrm{~K},\) at what temperature will \(k_{1} / k_{2}=2.00 ?\)

The rate constants of some reactions double with every 10 -degree rise in temperature. Assume that a reaction takes place at \(295 \mathrm{~K}\) and \(305 \mathrm{~K}\). What must the activation energy be for the rate constant to double as described?

Write the Arrhenius equation and define all terms.

The following data were collected for the reaction between hydrogen and nitric oxide at \(700^{\circ} \mathrm{C}\) : $$ 2 \mathrm{H}_{2}(g)+2 \mathrm{NO}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{N}_{2}(g) $$ $$ \begin{array}{clll} \hline \text { Experiment } & {\left[\mathrm{H}_{2}\right]} & {[\mathrm{NO}]} & \text { Initial Rate }(M / \mathrm{s}) \\ \hline 1 & 0.010 & 0.025 & 2.4 \times 10^{-6} \\ 2 & 0.0050 & 0.025 & 1.2 \times 10^{-6} \\ 3 & 0.010 & 0.0125 & 0.60 \times 10^{-6} \\ \hline \end{array} $$ (a) Determine the order of the reaction. (b) Calculate the rate constant. (c) Suggest a plausible mechanism that is consistent with the rate law. (Hint: Assume that the oxygen atom is the intermediate.)

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