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The rate constant for the second-order reaction $$ 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) $$ is \(0.54 / M \cdot \mathrm{s}\) at \(300^{\circ} \mathrm{C}\). How long (in seconds) would it take for the concentration of \(\mathrm{NO}_{2}\) to decrease from \(0.62 M\) to \(0.28 M ?\)

Short Answer

Expert verified
The time it would take for the concentration of NO2 to decrease from 0.62 M to 0.28 M is approximately 1.8 seconds.

Step by step solution

01

Identify Given Variables

Identify the given variables from the problem. Here, the initial concentration of NO2, \([A_0]\), is 0.62M, the final concentration, \([A]\), is 0.28M, and the rate constant, k, is 0.54/Mâ‹…s.
02

Write down the formula

The formula for the second-order reaction rate constant is \(k = 1/((1/[A]) - (1/[A_0]))*t\)
03

Substitute the Known Values

Substitute the given values into the formula to find the time. Rearrange the formula to find time: \(t = 1/(k*(1/[A]) - (1/[A_0]))\)
04

Calculation

Substituting 0.28 M for \([A]\), 0.62 M for \([A_0]\), and 0.54 M-1s-1 for k, we get \(t = 1/(0.54((1/0.28) - (1/0.62)))\)
05

Solve

After solving the equation, the time will be equal to 1.8 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the branch of physical chemistry that studies the rates at which chemical reactions occur and the factors that influence these rates. The goal of kinetics is to understand the sequence of steps, known as the reaction mechanism, through which the overall chemical change occurs.

In the realm of chemical kinetics, the speed of a reaction is quantified by the reaction rate. This rate measures how fast the reactants are converted into products over time. Factors such as temperature, concentration of reactants, surface area, catalysts, and the presence of light can significantly affect reaction rates.

Importance in Real-World Applications

Understanding kinetics has practical importance in various areas, like the design of chemical reactors in industrial processes, understanding metabolic pathways in biochemistry, developing pharmaceuticals, and even in environmental contexts such as the breakdown of pollutants.
Reaction Rates
Reaction rates refer to the speed at which reactants transform into products in a chemical reaction. Expressed in terms of concentration changes over time, the rate can be measured for either the disappearance of reactants or the appearance of products. The units typically used are moles per liter per second (M/s).

Mathematically, the reaction rate for a substance A changing into substance B can be expressed as: \[ \text{Reaction rate} = - \frac{d[A]}{dt} = \frac{d[B]}{dt} \] where \([A]\) is the concentration of A, and \(t\) represents time. The negative sign indicates that the concentration of A decreases over time.

Rate Laws and Order of Reactions

Chemists use rate laws to relate the reaction rate to the concentration of reactants. The rate law for a reaction states how the rate depends on the concentration of each reactant. In a second-order reaction, like our textbook exercise, the rate is proportional to the square of the concentration of one reactant or to the product of the concentrations of two different reactants.
Concentration of Reactants
The concentration of reactants plays a pivotal role in the rate of a chemical reaction. In general, a higher concentration of reactants leads to more collisions per unit time, which increases the likelihood of a successful reaction occurring, thus accelerating the rate.

In the context of the second-order reaction demonstrated in the textbook exercise, the rate of reaction is dependent upon the concentrations of the reactants raised to the second power. As a result, second-order reactions are sensitive to changes in reactant concentrations, and quantifying these effects is critical in calculating the time it takes for reactants to convert to products.

Second-Order Reaction Example

For the specific reaction provided, where the rate constant, \( k \) is \( 0.54 / M \cdot s \) at a given temperature, and the concentrations are initially \( 0.62 M \) and decrease to \( 0.28 M \) over time, the rate at which \( \mathrm{NO}_2 \) decreases is quintessential for determining the time span of the reaction.

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Most popular questions from this chapter

For a first-order reaction, how long will it take for the concentration of reactant to fall to one-eighth its original value? Express your answer in terms of the half-life \(\left(t_{1}\right)\) and in terms of the rate constant \(k\).

An instructor performed a lecture demonstration of the thermite reaction (see Example 6.10 ). He mixed aluminum with iron(III) oxide in a metal bucket placed on a block of ice. After the extremely exothermic reaction started, there was an enormous bang, which was not characteristic of thermite reactions. Give a plausible chemical explanation for the unexpected sound effect. The bucket was open to air.

For the reaction $$ \mathrm{NO}(g)+\mathrm{O}_{3}(g) \longrightarrow \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g) $$ the frequency factor \(A\) is \(8.7 \times 10^{12} \mathrm{~s}^{-1}\) and the activation energy is \(63 \mathrm{~kJ} / \mathrm{mol} .\) What is the rate constant for the reaction at \(75^{\circ} \mathrm{C} ?\)

Polyethylene is used in many items, including water pipes, bottles, electrical insulation, toys, and mailer envelopes. It is a polymer, a molecule with a very high molar mass made by joining many ethylene molecules together. (Ethylene is the basic unit, or monomer for polyethylene.) The initiation step is $$ \mathrm{R}_{2} \stackrel{k_{1}}{\longrightarrow} 2 \mathrm{R} \cdot \quad \text { initiation } $$ The \(\mathrm{R} \cdot\) species (called a radical) reacts with an ethylene molecule (M) to generate another radical $$ \mathrm{R} \cdot+\mathrm{M} \longrightarrow \mathrm{M}_{1} $$ Reaction of \(\mathrm{M}_{1} \cdot\) with another monomer leads to the growth or propagation of the polymer chain $$ \mathrm{M}_{1} \cdot+\mathrm{M} \stackrel{k_{\mathrm{p}}}{\longrightarrow} M_{2} \cdot \quad \text { propagation } $$ This step can be repeated with hundreds of monomer units. The propagation terminates when two radicals combine \(\mathrm{M}^{\prime}+\mathrm{M}^{\prime \prime} \cdot \stackrel{k_{1}}{\longrightarrow} \mathrm{M}^{\prime}-\mathrm{M}^{\prime \prime} \quad\) termination The initiator frequently used in the polymerization of ethylene is benzoyl peroxide \(\left[\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2}\right]:\) $$ \left[\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2}\right] \longrightarrow 2 \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO} $$ This is a first-order reaction. The half-life of benzoyl peroxide at \(100^{\circ} \mathrm{C}\) is 19.8 min. (a) Calculate the rate constant (in \(\min ^{-1}\) ) of the reaction. (b) If the half-life of benzoyl peroxide is \(7.30 \mathrm{~h},\) or \(438 \mathrm{~min},\) at \(70^{\circ} \mathrm{C},\) what is the activation energy (in \(\mathrm{kJ} / \mathrm{mol}\) ) for the decomposition of benzoyl peroxide? (c) Write the rate laws for the elementary steps in the above polymerization process, and identify the reactant, product, and intermediates. (d) What condition would favor the growth of long, highmolar-mass polyethylenes?

A certain first-order reaction is 35.5 percent complete in 4.90 min at \(25^{\circ} \mathrm{C}\). What is its rate constant?

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