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Which of the following ions possess a dipole moment: (a) \(\mathrm{ClF}_{2}^{+},\) (b) \(\mathrm{ClF}_{2}^{-},\) (c) \(\mathrm{IF}_{4}^{+},\) (d) \(\mathrm{IF}_{4}^{-} ?\)

Short Answer

Expert verified
Among the give ions, only \(\mathrm{ClF}_{2}^{+}\), and \(\mathrm{ClF}_{2}^{-}\) possess a dipole moment, while \(\mathrm{IF}_{4}^{+}\), and \(\mathrm{IF}_{4}^{-}\) do not.

Step by step solution

01

Analyzing the geometry of \(\mathrm{ClF}_{2}^{+}\)

This ion has a bent shaped molecular geometry, like that of water. Because the two Fluorine atoms and the non-bonding pair of electron are not distributed symmetrically around the Chlorine atom, the molecule is polarized and thus has a dipole moment.
02

Analyzing the geometry of \(\mathrm{ClF}_{2}^{-}\)

This ion too has a bent shaped geometry. But due to the extra negative charge, it has one more non-bonding pair of electrons. But like \(\mathrm{ClF}_{2}^{+}\), the Fluorine atoms and the non-bonding pairs of electrons are not distributed symmetrically around the Chlorine atom, creating a dipole moment.
03

Analyzing the geometry of \(\mathrm{IF}_{4}^{+}\)

The electron configuration of Iodine in its ground state allows this ion to form a square planar geometry. In this configuration, the charge distribution is symmetric, cancelling the dipole moments, hence \(\mathrm{IF}_{4}^{+}\) has no dipole moment.
04

Analyzing the geometry of \(\mathrm{IF}_{4}^{-}\)

Like \(\mathrm{IF}_{4}^{+}\), \(\mathrm{IF}_{4}^{-}\) also forms a square planar geometry with symmetric charge distribution, cancelling the dipole moments. Thus, it does not possess a dipole moment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dipole Moment
A dipole moment is a measure of the separation of positive and negative charges within a molecule. It indicates the molecule's polarity. Molecules with a significant dipole moment typically have atoms with different electronegativities that do not share electrons equally. As a result, one end of the molecule carries a slight positive charge while the other end carries a slight negative charge. This creates a 'dipole.'
In the context of the ions provided, the dipole moment is affected by their molecular geometry and the symmetry of the charge distribution. The ions
  • \( \mathrm{ClF}_{2}^{+} \) and \( \mathrm{ClF}_{2}^{-} \) both have bent geometries which leads to a lack of symmetry in their charge distribution. This results in them having a dipole moment.
  • In contrast, \( \mathrm{IF}_{4}^{+} \) and \( \mathrm{IF}_{4}^{-} \) form symmetric square planar geometries, resulting in no net dipole moment because the opposing dipoles cancel each other out.
Bent Molecular Shape
A bent molecular shape arises when a central atom is bonded to two other atoms and has one or more lone pairs of electrons. This geometric configuration is not linear but rather angular due to the repulsion between the lone pairs and bonded pairs of electrons, following VSEPR (Valence Shell Electron Pair Repulsion) theory.
An example of a molecule with a bent shape is \( \mathrm{H}_2\mathrm{O} \) (water). Similarly, \( \mathrm{ClF}_2^{+} \) and \( \mathrm{ClF}_2^{-} \) also assume a bent configuration. The lone pairs push the bonded F fluorine atoms away, forming an angle less than the full 180 degrees of a straight line. This creates areas of positive and negative charge within the molecule, leading to the presence of a dipole moment.
Bent molecular shapes are often associated with polar molecules due to their asymmetrical charge distribution, making the presence or absence of lone pairs a critical factor.
Square Planar Geometry
Square planar geometry refers to a molecular shape where a molecule is arranged in a square on the same plane. This configuration often involves a central atom bonded to four surrounding atoms, with the bonds forming 90-degree angles with each other on the same plane. Many transition metal complexes show this type of arrangement.
The key feature of square planar molecules, such as \( \mathrm{IF}_{4}^{+} \) and \( \mathrm{IF}_{4}^{-} \) from the exercise, is the high level of symmetry. The identical arrangements of the bonded atoms and the even distribution of charge mean that any individual bond dipoles cancel out. Consequently, such molecules have no net dipole moment.
  • The lack of net dipole moment is crucial as it influences the overall chemical behavior. Without a dipole moment, these molecules do not attract polar solvents or molecules as strongly as their polar counterparts.
  • The symmetry of the square planar geometry is also essential in determining the electronic properties of these ions.

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Most popular questions from this chapter

Both ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\) and benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) contain the \(\mathrm{C}=\mathrm{C}\) bond. The reactivity of ethylene is greater than that of benzene. For example, ethylene readily reacts with molecular bromine, whereas benzene is normally quite inert toward molecular bromine and many other compounds. Explain this difference in reactivity.

Acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) has a tendency to lose two protons \(\left(\mathrm{H}^{+}\right)\) and form the carbide ion \(\left(\mathrm{C}_{2}^{2-}\right),\) which is present in a number of ionic compounds, such as \(\mathrm{CaC}_{2}\) and \(\mathrm{MgC}_{2}\). Describe the bonding scheme in the \(\mathrm{C}_{2}^{2-}\) ion in terms of molecular orbital theory. Compare the bond order in \(\mathrm{C}_{2}^{2-}\) with that in \(\mathrm{C}_{2}\).

Describe the geometry around each of the three central atoms in the \(\mathrm{CH}_{3} \mathrm{COOH}\) molecule.

Consider a \(\mathrm{N}_{2}\) molecule in its first excited electronic state, that is, when an electron in the highest occupied molecular orbital is promoted to the lowest empty molecular orbital. (a) Identify the molecular orbitals involved and sketch a diagram to show the transition. (b) Compare the bond order and bond length of \(\mathrm{N}_{2}^{*}\) with \(\mathrm{N}_{2},\) where the asterisk denotes the excited molecule. (c) Is \(\mathrm{N}_{2}{ }^{*}\) diamagnetic or paramagnetic? (d) When \(\mathrm{N}_{2}\) * loses its excess energy and converts to the ground state \(\mathrm{N}_{2}\), it emits a photon of wavelength \(470 \mathrm{nm},\) which makes up part of the auroras lights. Calculate the energy difference between these levels.

Explain why an atom cannot have a permanent dipole moment.

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