/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Three apprentice tailors \((\mat... [FREE SOLUTION] | 91Ó°ÊÓ

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Three apprentice tailors \((\mathrm{X}, \mathrm{Y},\) and \(\mathrm{Z})\) are assigned the task of measuring the seam of a pair of trousers. Each one makes three measurements. The results in inches are \(\mathrm{X}(31.5,31.6,31.4) ; \mathrm{Y}(32.8,32.3,32.7)\) \(\mathrm{Z}(31.9,32.2,32.1) .\) The true length is \(32.0 \mathrm{in}\) Comment on the precision and the accuracy of each tailor's measurements.

Short Answer

Expert verified
Tailor X exhibits the greatest precision as his measurements are closest to each other. Tailor Z, on the other hand, is the most accurate as his average measurement is closest to the true length of 32 inches.

Step by step solution

01

Calculate the Mean of Each Set

Use the formula for arithmetic mean to determine the average measurement of each tailor, which is sum of measurements divided by the number of measurements. For tailor X, \((31.5 + 31.6 + 31.4) / 3 = 31.5 inches\). For tailor Y, \((32.8 + 32.3 + 32.7) / 3 = 32.6 inches\). For tailor Z, \((31.9 + 32.2 + 32.1) / 3 = 32.1 inches\)
02

Calculate the Range and Standard Deviation of Each Set

The range is the difference between the highest and lowest value in each set. Compute the standard deviation (SD) with the formula \[ SD = \sqrt{\frac{\Sigma (x_{i} - \bar{x})^{2}}{N}}\] where \(x_{i}\) is each measurement, \(\bar{x}\) is the mean of the measurements, and \(N\) is the number of measurements. After calculation, find that the range is 0.2 inches and SD is 0.1 inches for X, range is 0.5 inches and SD is 0.25 inches for Y, and range is 0.3 inches and SD is 0.15 inches for Z.
03

Evaluate the Accuracy and Precision

For precision, tailor X has the least difference among readings (smallest range and SD) and therefore the best precision. For accuracy, tailor Z has the mean closest to the true length, making him the most accurate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Understanding mean calculation is essential for analyzing data sets, as it represents the average value and provides a central point around which measurement variations can be assessed. In the context of the exercise involving three apprentice tailors measuring the seam of a pair of trousers, the mean of each tailor's measurements was determined by summing up their individual measurements and dividing by the total number of measurements taken.

This calculation is represented by the formula for an arithmetic mean: \( \bar{x} = \frac{\sum{x_{i}}}{N} \), where \( x_{i} \) represents each measurement and \( N \) is the count of measurements. For instance, tailor X's calculations were done by adding \( 31.5, 31.6, \) and \( 31.4 \) and then dividing by \( 3 \) to achieve a mean of \( 31.5 \) inches.

Employing the mean calculation helps in identifying the central tendency of measurements, but it is equally important to consider how spread out these measurements are, which can be understood through concepts like standard deviation and range.
Standard Deviation
Standard deviation is a statistic that tells us how measurements in a data set vary around the mean. It's a crucial concept in understanding the variability or spread of measurement values. The lower the standard deviation, the closer the data points are to the mean (or average), indicating higher consistency or precision.

To calculate the standard deviation (SD), we use the following formula: \[ SD = \sqrt{\frac{\Sigma (x_{i} - \bar{x})^{2}}{N}} \], where \( x_{i} \) is each individual measurement, \( \bar{x} \) is the mean of the measurements, and \( N \) is the total number of measurements. In our exercise, after the mean was calculated, the SD for tailor X was found to be 0.1 inches, indicating high precision in his measurements.

Importance of Standard Deviation in Measurement Analysis

Understanding the standard deviation enables students to evaluate the reliability of the data. For example, if a tailor's measurements have a high standard deviation, this suggests greater variability and possibly lower precision in measurements, which may not be ideal in tightly controlled scenarios like garment fitting.
Range of Measurements
The range of a set of measurements is the difference between the highest and lowest values, offering a quick insight into the spread of data points. It's one of the simplest forms of variability measurement and an important concept to grasp for anyone working with data.

In the given exercise, the range helps us evaluate the precision of each tailor's measurements. A smaller range suggests the measurements are more consistently grouped together, which is preferred for tasks requiring a high level of precision. The formula to calculate the range is quite straightforward: \( Range = Maximum value - Minimum value \). From the results of the exercise, tailor X had a range of 0.2 inches, showing that his measurements were quite consistent.

The Significance of Understanding Measurement Range

Students must comprehend that while the range provides quick information on the spread, it considers only the extremes and not all data values. This is why it's often used in conjunction with other statistics like the mean and standard deviation. Understanding the range is particularly useful for identifying any outliers or errors in the measurements, contributing to the overall analysis of data precision and accuracy.

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