/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Bromine is a reddish-brown liqui... [FREE SOLUTION] | 91Ó°ÊÓ

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Bromine is a reddish-brown liquid. Calculate its density (in \(g / \mathrm{mL}\) ) if \(586 \mathrm{~g}\) of the substance occupies \(188 \mathrm{~mL}\)

Short Answer

Expert verified
The Density of Bromine is \(3.12 \mathrm{~g/mL}\)

Step by step solution

01

Identify given values

The exercise gives two key pieces of information: the mass of the bromine, which is \(586 \mathrm{~g}\), and the volume that bromine occupies, \(188 \mathrm{~mL}\)
02

Use the Density formula

The formula for density is \(Density = \frac{Mass}{Volume}\). Substitute the given values into this formula to calculate the density.
03

Perform Calculation

Substitute the mass \(586 \mathrm{~g}\) and the volume \(188 \mathrm{~mL}\), in the density formula. So, it will be \(Density = \frac{586 \mathrm{g}}{188 \mathrm{mL}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bromine
Bromine is a fascinating element that is known for its distinct reddish-brown color and liquid state at room temperature. It's part of the halogen group in the periodic table, which also includes elements like chlorine and fluorine. Bromine is unique because it’s one of the only elements that is a liquid in its natural state under normal conditions. It's important to handle bromine with care as it is caustic and can cause burns.

In the exercise provided, bromine is used as a substance whose density we are asked to calculate. Understanding bromine's properties can help in comprehending why it behaves the way it does when we talk about physical characteristics such as volume and mass. It’s crucial to use proper safety protocols when working in laboratories to ensure that bromine's reactive nature doesn’t pose any risks.
Mass
In physics and chemistry, mass is a measure of the amount of matter in an object, usually measured in grams (g) or kilograms (kg). It is not affected by gravity and, thus, remains constant regardless of where the object is located.

In the given exercise, the mass of bromine is 586 grams. Understanding what mass signifies in physical terms helps us appreciate how it differs from weight, which can change with varying gravitational forces. Mass is one of the essential parameters necessary for calculating density, emphasizing its integral role in solving real-world chemistry problems.
  • Mass is a measure of matter.
  • Mass remains constant regardless of location.
  • It's distinct from weight, which depends on gravity.
Volume
Volume is the amount of space that a substance or object occupies, and it is typically measured in cubic centimeters (cm³) or milliliters (mL) for liquids. In the context of the exercise, volume refers to the space occupied by the given mass of bromine, which is 188 milliliters.

Volume is crucial in calculations involving density, as it provides the context for how much space the mass of a substance is taking up. Recognizing the volume allows us to determine how coherent and compact a substance is, directly impacting the density result.
  • Volume is measured in mL or cm³ for liquids.
  • It indicates the space a substance occupies.
  • Essential for calculating density.
Density Formula
Density is a fundamental concept in physical sciences, defined as the mass per unit volume of a substance. The density formula is given by:\[Density = \frac{Mass}{Volume}\]Using this formula helps us understand how much matter is contained within a certain amount of space. For the exercise, substituting the given mass (586 g) and volume (188 mL) into the formula, we find that:\[Density = \frac{586 \text{ g}}{188 \text{ mL}} \approx 3.12 \text{ g/mL}\]This simple calculation gives us the density of bromine, which helps in various applications and scientific studies. It's vital to accurately plug in the values into the formula and to ensure the units are consistent for meaningful results.
  • Density shows how much mass is in a given volume.
  • The formula helps calculate the physical characteristic of a substance.
  • Accurate unit conversion and calculation are essential to get correct results.

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Most popular questions from this chapter

A human brain weighs about \(1 \mathrm{~kg}\) and contains about \(10^{11}\) cells. Assuming that each cell is com pletely filled with water (density \(=1 \mathrm{~g} / \mathrm{mL}\) ), calculate the length of one side of such a cell if it were a cube. If the cells are spread out in a thin layer that is a single cell thick, what is the surface area in square meters?

(a) Normally the human body can endure a temperature of \(105^{\circ} \mathrm{F}\) for only short periods of time without permanent damage to the brain and other vital organs. What is this temperature in degrees Celsius? (b) Ethylene glycol is a liquid organic compound that is used as an antifreeze in car radiators. It freezes at \(-11.5^{\circ} \mathrm{C}\). Calculate its freezing temperature in degrees Fahrenheit. (c) The temperature on the surface of the sun is about \(6300^{\circ} \mathrm{C}\). What is this temperature in degrees Fahrenheit? (d) The ignition temperature of paper is \(451^{\circ} \mathrm{F}\). What is the temperature in degrees Celsius?

Explain how the distances between particles typically change with different states of matter.

Carry out the following operations as if they were calculations of experimental results, and express each answer in the correct units with the correct number of significant figures: (a) \(7.310 \mathrm{~km} \div 5.70 \mathrm{~km}\) (b) \(\left(3.26 \times 10^{-3} \mathrm{mg}\right)-\left(7.88 \times 10^{-5} \mathrm{mg}\right)\) (c) \(\left(4.02 \times 10^{6} \mathrm{dm}\right)+\left(7.74 \times 10^{7} \mathrm{dm}\right)\) (d) \((7.8 \mathrm{~m}-0.34 \mathrm{~m}) /(1.15 \mathrm{~s}+0.82 \mathrm{~s})\)

In water conservation, chemists spread a thin film of a certain inert material over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that \(0.10 \mathrm{~mL}\) of oil could spread over the surface of water about \(40 \mathrm{~m}^{2}\) in area. Assuming that the oil forms a monolayer, that is, a layer that is only one molecule thick, estimate the length of each oil molecule in nanometers. $\left(1 \mathrm{nm}=1 \times 10^{-9} \mathrm{~m} .\right).

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