Chapter 1: Problem 15
Using examples, explain the difference between a physical property and a chemical property.
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 1: Problem 15
Using examples, explain the difference between a physical property and a chemical property.
These are the key concepts you need to understand to accurately answer the question.
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Give an example of a homogeneous mixture and an example of a heterogeneous mixture.
How many significant figures are there in each of the following? (a) \(0.006 \mathrm{~L},\) (b) \(0.0605 \mathrm{dm},\) (c) \(60.5 \mathrm{mg}\), (d) \(605.5 \mathrm{~cm}^{2}\) (e) \(960 \times 10^{-3} \mathrm{~g},(\mathrm{f}) 6 \mathrm{~kg},(\mathrm{~g}) 60 \mathrm{~m}\)
An aluminum cylinder is \(10.0 \mathrm{~cm}\) in length and has a radius of \(0.25 \mathrm{~cm}\). If the mass of a single Al atom is \(4.48 \times 10^{-23} \mathrm{~g},\) calculate the number of \(\mathrm{Al}\) atoms present in the cylinder. The density of aluminum is $2.70 \mathrm{~g} / \mathrm{cm}^{3}.
A graduated cylinder is tilled to the \(40.00-\mathrm{mL}\) mark with a mineral oil. The masses of the cylinder before and after the addition of the mineral oil are \(124.966 \mathrm{~g}\) and \(159.446 \mathrm{~g},\) respectively. In a separate experiment, a metal ball bearing of mass \(18.713 \mathrm{~g}\) is placed in the cylinder and the cylinder is again filled to the 40.00 -mL mark with the mineral oil. The combined mass of the ball bearing and mineral oil is 50.952 g. Calculate the density and radius of the ball bearing. [The volume of a sphere of radius \(r\) is $\left.(4 / 3) \pi r^{3} .\right].
Give an example of an element and a compound. How do elements and compounds differ?
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