/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 101 Give a possible set of values of... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Problem 101

Give a possible set of values of the four quantum numbers for all the electrons in a boron atom and a nitrogen atom if each is in the ground state.

Short Answer

Expert verified
The possible sets of quantum numbers for all electrons in a boron atom (1s虏2s虏2p鹿) in the ground state are: Electron 1: \( (n = 1, l = 0, m_l = 0, m_s = +1/2) \) Electron 2: \( (n = 1, l = 0, m_l = 0, m_s = -1/2) \) Electron 3: \( (n = 2, l = 0, m_l = 0, m_s = +1/2) \) Electron 4: \( (n = 2, l = 0, m_l = 0, m_s = -1/2) \) Electron 5: \( (n = 2, l = 1, m_l = -1, m_s = +1/2) \) For a nitrogen atom (1s虏2s虏2p鲁) in the ground state, quantum numbers are the same as boron for electrons 1-4. The rest are: Electron 5: \( (n = 2, l = 1, m_l = -1, m_s = +1/2) \) Electron 6: \( (n = 2, l = 1, m_l = 0, m_s = +1/2) \) Electron 7: \( (n = 2, l = 1, m_l = +1, m_s = +1/2) \)

Step by step solution

01

Electron configuration of boron

To find the quantum numbers, we first need to determine the electron configuration of boron. The ground state electron configuration of boron is 1s虏2s虏2p鹿.
02

Quantum numbers for boron

Now, we will determine the four quantum numbers for each electron in a boron atom: Electron 1 (1s虏): - n = 1 - l = 0 - m_l = 0 - m_s = +1/2 Electron 2 (1s虏): - n = 1 - l = 0 - m_l = 0 - m_s = -1/2 Electron 3 (2s虏): - n = 2 - l = 0 - m_l = 0 - m_s = +1/2 Electron 4 (2s虏): - n = 2 - l = 0 - m_l = 0 - m_s = -1/2 Electron 5 (2p鹿): - n = 2 - l = 1 - m_l = -1, 0, or +1 (we choose -1 since this is the first electron in the 2p orbital) - m_s = +1/2 Now, let's move on to the nitrogen atom:
03

Electron configuration of nitrogen

To find the quantum numbers, we first need to determine nitrogen's electron configuration. The ground state electron configuration of nitrogen is 1s虏2s虏2p鲁.
04

Quantum numbers for nitrogen

Now, we will determine the four quantum numbers for each electron in a nitrogen atom: Electrons 1-4 are in the same orbitals as the boron, so their quantum numbers will be the same. Electron 5 (2p鲁): - n = 2 - l = 1 - m_l = -1 - m_s = +1/2 Electron 6 (2p鲁): - n = 2 - l = 1 - m_l = 0 (since m_l can't be the same for two electrons in the same orbital) - m_s = +1/2 Electron 7 (2p鲁): - n = 2 - l = 1 - m_l = +1 (since m_l can't be the same for two electrons in the same orbital) - m_s = +1/2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using only the periodic table inside the front cover of the text, write the expected ground-state electron configurations for a. the third element in Group 5 \(\mathrm{A}\) . b. element number \(116 .\) c. an element with three unpaired 5\(d\) electrons. d. the halogen with electrons in the 6\(p\) atomic orbitals.

In defining the sizes of orbitals, why must we use an arbitrary value, such as 90% of the probability of finding an electron in that region?

The electron affinities of the elements from aluminum to chlorine are \(-44,-120,-74,-200.4,\) and \(-384.7 \mathrm{kJ} / \mathrm{mol}\) respectively. Rationalize the trend in these values.

Element 106 has been named seaborgium, Sg, in honor of Glenn Seaborg, discoverer of the first transuranium element. a. Write the expected electron configuration for element 106. b. What other element would be most like element 106 in its properties? c. Predict the formula for a possible oxide and a possible oxyanion of element 106.

Octyl methoxycinnamate and oxybenzone are common ingredients in sunscreen applications. These compounds work by absorbing ultraviolet (UV) B light (wavelength 280鈥�320 nm), the UV light most associated with sunburn symptoms. What frequency range of light do these compounds absorb?
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Nuclear Chemistry

Read Explanation

Making Measurements

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.