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What number of Fe atoms and what amount (moles) of Fe atoms are in 500.0 g of iron?

Short Answer

Expert verified
In a 500.0 g sample of iron, there are \(8.952\) moles of iron (Fe) atoms and approximately \(5.389 \times 10^{24}\) iron (Fe) atoms.

Step by step solution

01

Calculate the moles of iron (Fe)

To find the moles of iron, we will use the given mass (500.0 g) and divide it by the molar mass of iron (55.845 g/mol). This will give us the amount (moles) of Fe atoms in the sample. Moles of Fe = (mass of iron) / (molar mass of iron) Moles of Fe = (500.0 g) / (55.845 g/mol) Moles of Fe = 8.952 moles
02

Calculate the number of iron atoms (Fe)

To find the number of iron atoms in the sample, we will use the moles of iron (from Step 1) and multiply it by Avogadro's number (6.022 x 10^23 atoms/mol). Number of Fe atoms = (moles of Fe) x (Avogadro's number) Number of Fe atoms = (8.952 moles) x (6.022 x 10^23 atoms/mol) Number of Fe atoms = 5.389 x 10^24 atoms In conclusion, there are \(8.952\) moles of iron (Fe) atoms and approximately \(5.389 \times 10^{24}\) iron (Fe) atoms in 500.0 g of iron.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Molar mass is a fundamental concept in chemistry. It allows us to convert between the mass of a substance and the amount in moles, making it a vital tool for stoichiometry. Molar mass is defined as the mass of one mole of a substance.

For any element, the molar mass is numerically equal to its atomic mass but expressed in grams per mole (g/mol). For example, the atomic mass of iron (Fe) is approximately 55.845 amu (atomic mass units), so the molar mass of iron is 55.845 g/mol. This constant lets us easily convert grams to moles when dealing with pure substances.

To find the molar mass of a compound, you simply add up the molar masses of the constituent elements. This value helps accurately predict how substances react in chemical equations and enable quantifiable measurements of the atoms involved.
Avogadro's Number
Avogadro's number is a cornerstone in the study of stoichiometry and represents the link between the microscopic world and our everyday macroscopic observations. It defines how many particles, such as atoms or molecules, are in one mole of a substance. This number is a constant: \(6.022 \times 10^{23} \text{ particles/mol}\).

Imagine if each particle were a tiny building block. Avogadro's number tells you just how many blocks are in a mole, providing a scale that makes counting atoms practical. Relating this to our problem, by knowing how many moles of iron we have, we can calculate the number of iron atoms by multiplying the moles by Avogadro鈥檚 number.

This concept is crucial for converting between the amount of substance in moles and the actual number of atoms or molecules.
Moles Calculation
Moles are a key unit in chemistry that allow us to count atoms in a given sample using a manageable number. A mole represents \(6.022 \times 10^{23}\) items, whether they are atoms, molecules, or any other chemical units. It's similar to a dozen; just instead of 12, a mole has this much larger number.

To calculate the number of moles in a sample, use the formula:
  • Moles = \( \frac{\text{mass}}{\text{molar mass}} \)
The mass refers to how much of the material you have in grams, and the molar mass is the mass of one mole of that substance.

In the example problem, we calculated the moles of iron by dividing its mass, 500.0 g, by its molar mass, 55.845 g/mol. This gives us 8.952 moles, showing us how many moles of iron atoms we have in 500.0 grams. Once you know the moles, using Avogadro's number, you can find out exactly how many atoms are in that quantity.

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Most popular questions from this chapter

Determine the molecular formulas to which the following empirical formulas and molar masses pertain. a. \(\operatorname{SNH}(188.35 \mathrm{g} / \mathrm{mol})\) b. \(\mathrm{NPCl}_{2}(347.64 \mathrm{g} / \mathrm{mol})\) c. \(\operatorname{CoC}_{4} \mathrm{O}_{4}(341.94 \mathrm{g} / \mathrm{mol})\) d. \(\mathrm{SN}(184.32 \mathrm{g} / \mathrm{mol})\)

You are making cookies and are missing a key ingredient鈥攅ggs. You have most of the other ingredients needed to make the cookies, except you have only 1.33 cups of butter and no eggs. You note that the recipe calls for two cups of butter and three eggs (plus the other ingredients) to make six dozen cookies. You call a friend and have him bring you some eggs. a. What number of eggs do you need? b. If you use all the butter (and get enough eggs), what number of cookies will you make Unfortunately, your friend hangs up before you tell him how many eggs you need. When he arrives, he has a surprise for you鈥攖o save time, he has broken them all in a bowl for you. You ask him how many he brought, and he replies, 鈥淚 can鈥檛 remember.鈥 You weigh the eggs and find that they weigh 62.1 g. Assuming that an average egg weighs 34.21 g, a. What quantity of butter is needed to react with all the eggs? b. What number of cookies can you make? c. Which will you have left over, eggs or butter? d. What quantity is left over?

An iron ore sample contains \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) plus other impurities. A 752 -g sample of impure iron ore is heated with excess carbon, producing 453 g of pure iron by the following reaction: $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(g) $$ What is the mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the impure iron ore sample? Assume that \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is the only source of iron and that the reaction is 100\(\%\) efficient.

A binary compound between an unknown element \(\mathrm{E}\) and hydrogen contains 91.27\(\% \mathrm{E}\) and 8.73\(\% \mathrm{H}\) by mass. If the formula of the compound is \(\mathrm{E}_{3} \mathrm{H}_{8},\) calculate the atomic mass of \(\mathrm{E}\)

What amount (moles) is represented by each of these samples? a. 150.0 g Fe_ \(\mathrm{O}_{3}\) b. 10.0 \(\mathrm{mg} \mathrm{NO}_{2}\) c. \(1.5 \times 10^{16}\) molecules of \(\mathrm{BF}_{3}\)

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