Chapter 3: Problem 172
Natural rubidium has the average mass of 85.4678 \(\mathrm{u}\) and is composed of isotopes \(^{85} \mathrm{Rb}(\mathrm{mass}=84.9117 \mathrm{u})\) and \(^{87} \mathrm{Rb}\) . The ratio of atoms \(^{85} \mathrm{Rb} /^{87} \mathrm{Rb}\) in natural rubidium is \(2.591 .\) Calculate the mass of \(^{87} \mathrm{Rb}\) .
Short Answer
Step by step solution
Write down the formula for the average mass of the element
Express the abundance of \(^{87}\mathrm{Rb}\) in terms of the abundance of the \(^{85}\mathrm{Rb}\)
Insert the known values into the formula
Solve for the mass of \(^{87}\mathrm{Rb}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Abundance Ratio
- The abundance ratio helps us understand the composition of isotopes in a sample.
- It is crucial when calculating the average atomic mass of an element with multiple isotopes.
- Knowing the ratio allows us to express the abundance of one isotope in terms of the other.
Average Atomic Mass
\[ M = \sum m_i a_i \] where \(m_i\) is the mass of each isotope and \(a_i\) is its abundance.
- This calculation considers both the mass and the abundance of each isotope.
- It results in an average that can be compared to the standard atomic mass seen on periodic tables.
- The key is to sum the products of each isotope's mass and its abundance.
Rubidium Isotopes
- The isotope \(^{85}\text{Rb}\) has a mass of \(84.9117 \text{u}\) and is more abundant in natural rubidium.
- The isotope \(^{87}\text{Rb}\) is present to a lesser extent but plays a significant role in dating geological formations due to its radioactivity.
- The isotopes differ in neutron number while sharing the same number of protons (37, which is unique to rubidium).