/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Draw the five structural isomers... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 22: Problem 15

Draw the five structural isomers of hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right)\)

Short Answer

Expert verified
The five structural isomers of hexane \(\mathrm{C}_{6}\mathrm{H}_{14}\) are: 1. Hexane (straight chain): \(\mathrm{CH_3CH_2CH_2CH_2CH_2CH_3}\) 2. 2-Methylpentane: \(\mathrm{CH_3CH(CH_3)CH_2CH_2CH_3}\) 3. 3-Methylpentane: \(\mathrm{CH_3CH_2CH(CH_3)CH_2CH_3}\) 4. 2,2-Dimethylbutane: \(\mathrm{CH_3C(CH_3)_2CH_2CH_3}\) 5. 2,3-Dimethylbutane: \(\mathrm{CH_3CH(CH_3)CH(CH_3)CH_3}\)

Step by step solution

01

Draw straight-chain hexane

Start by drawing the straight-chain structure of hexane, containing six carbon atoms in a row, with each carbon atom bonded to the appropriate number of hydrogen atoms to fulfill its four covalent bonds. 1. Hexane (straight chain): \[ \mathrm{CH_3CH_2CH_2CH_2CH_2CH_3} \]
02

Create the first branched isomer

To create the first branched isomer, remove a hydrogen from one of the carbon atoms, and add a methyl group (CH3) to a neighboring carbon atom. It's essential not to create an isomer that is just a rotated version of one you already drew. 2. 2-Methylpentane (one of the carbons now has a methyl group attached) : \[ \mathrm{CH_3CH(CH_3)CH_2CH_2CH_3} \]
03

Create the second branched isomer

Follow the method in Step 2 to create another branched isomer by removing a hydrogen atom from an internal carbon atom (not already containing a methyl group) and attaching a methyl group to that carbon atom without duplicating any previous structures. 3. 3-Methylpentane (another methyl group attached on a different carbon) : \[ \mathrm{CH_3CH_2CH(CH_3)CH_2CH_3} \]
04

Create the third and fourth branched isomers

Repeat the process in Steps 2 and 3 to create a third and fourth branched isomer with the methyl groups in different arrangements. Make sure not to create a duplicate of a previously drawn structure. Ensure that only two methyl groups are being added for these isomers, or you will break the hexane molecular formula. 4. 2,2-Dimethylbutane (two methyl groups attached to the same carbon) : \[ \mathrm{CH_3C(CH_3)_2CH_2CH_3} \] 5. 2,3-Dimethylbutane (two methyl groups attached to different carbons) : \[ \mathrm{CH_3CH(CH_3)CH(CH_3)CH_3} \] Now you have drawn the five structural isomers of hexane. Each has the same molecular formula, C6H14, but different arrangements of the carbon and hydrogen atoms in the structure.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hexane
Hexane is an important molecule in organic chemistry. It is composed of six carbon atoms and fourteen hydrogen atoms, giving it the molecular formula \(\mathrm{C_6H_{14}}\). As a hydrocarbon, hexane is part of the alkane family, meaning it only has single bonds between its carbon atoms.

Hexane is commonly found in gasoline and used in chemical laboratories as a non-polar solvent. This compound is linear, making it the simplest and straight-chain version of hexane. Despite its simple structure, hexane plays a massive role in learning about structural isomers, as students can explore different ways to arrange its atoms while keeping the same formula.
Organic Chemistry
The field of organic chemistry focuses on carbon-containing compounds, primarily their structure, properties, reactions, and synthesis. Given carbon's unique ability to bond in various ways, this field deals with an enormous variety of molecules ranging from simple ones like methane to complex structures such as proteins and DNA.

Organic chemistry forms the foundation for studying hexane and its isomers. Understanding how carbon chains can be rearranged helps scientists and students predict chemical behaviors and reactions. It is crucial in developing synthetic materials, pharmaceuticals, and fuels. Key concepts in organic chemistry include functional groups, molecular bonding, and isomerism, all of which are essential when learning about compounds like hexane.
Molecular Structure
The molecular structure of a compound describes how its atoms are arranged and connected through bonds. For hexane, this involves understanding how six carbon atoms are linked in a chain and how hydrogen atoms fulfill the remaining valence requirements to form single bonds.

Molecular structures can be depicted through different representations like structural formulas or three-dimensional models, which help visualize and differentiate between isomers. These structural diagrams are essential in organic chemistry for showing how atoms connect in various isomers of a compound like hexane. Through structure, chemists understand properties such as boiling and melting points, solubility, and chemical reactivity.
Isomerism
Isomerism is the phenomenon where compounds share the same molecular formula but have different arrangements of atoms, leading to different properties. Structural isomers vary in how the atoms are arranged and connected, unlike stereoisomers, which differ in spatial orientation.

In hexane's case, creating structural isomers involves rearranging the carbon chain. The five structural isomers of hexane include straight-chain hexane and branched versions such as 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, and 2,3-dimethylbutane.
  • Each isomer has unique physical properties, despite having the same molecular formula \( \mathrm{C_6H_{14}} \).
  • Isomerism is pivotal for understanding chemical diversity and reactivity in organic chemistry.
  • Students can learn a lot about molecular interactions by studying how different isomers react under similar conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Polystyrene can be made more rigid by copolymerizing styrene with divinylbenzene: How does the divinylbenzene make the copolymer more rigid?

When acrylic polymers are burned, toxic fumes are produced. For example, in many airplane fires, more passenger deaths have been caused by breathing toxic fumes than by the fire itself. Using polyacrylonitrile as an example, what would you expect to be one of the most toxic, gaseous combustion products created in the reaction?

Draw structural formulas for each of the following alcohols Indicate whether the alcohol is primary, secondary, or tertiary. $$ \begin{array}{ll}{\text { a. } 1-\text { butanol }} & {\text { c. } 2 \text { -methyl- } 1 \text { -butanol }} \\ {\text { b. } 2 \text { -butanol }} & {\text { d. } 2 \text { -methyl-2-butanol }}\end{array} $$

Ethylene oxide is an important industrial chemical. Although most ethers are unreactive, ethylene oxide is quite reactive. It resembles \(\mathrm{C}_{2} \mathrm{H}_{4}\) in its reactions in that addition reactions occur across the \(\mathrm{C}-\mathrm{O}\) bond in ethylene oxide. a. Why is ethylene oxide so reactive? (Hint: Consider the bond angles in ethylene oxide as compared with those predicted by the VSEPR model.) b. Ethylene oxide undergoes addition polymerization, forming a polymer used in many applications requiring a nonionic surfactant. Draw the structure of this polymer.

In the presence of light, chlorine can substitute for one (or more) of the hydrogens in an alkane. For the following reactions, draw the possible monochlorination products. $$ 2,2 \text { -dimethylpropane }+\mathrm{Cl}_{2} \longrightarrow $$ $$ 1,3 \text { -dimethylcyclobutane }+\mathrm{Cl}_{2} \stackrel{\mathrm{hn}}{\longrightarrow} $$ $$ 2,3 \text { -dimethylbutane }+\mathrm{Cl}_{2} \stackrel{\mathrm{w}}{\longrightarrow} $$
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Read Explanation

The Earths Atmosphere

Read Explanation

Nuclear Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Reactions

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.