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Chapter 21: Problem 40

Give formulas for the following complex ions. a. tetrachloroferrate(III) ion b. pentaammineaquaruthenium(III) ion c. tetracarbonyldihydroxochromium(III) ion d. amminetrichloroplatinate(II) ion

Short Answer

Expert verified
The formulas for the given complex ions are as follows: a. Tetrachloroferrate(III) ion: \(\ce{[Fe(Cl)4]^{3-}}\) b. Pentaammineaquaruthenium(III) ion: \(\ce{[Ru(NH3)5(H2O)]^{3+}}\) c. Tetracarbonyldihydroxochromium(III) ion: \(\ce{[Cr(CO)4(OH)2]^{3-}}\) d. Amminetrichloroplatinate(II) ion: \(\ce{[Pt(NH3)Cl3]^{2-}}\)

Step by step solution

01

a. Tetrachloroferrate(III) ion

We can break down the name into three parts - the counterion (chloride), the central ion (iron), and its oxidation state (III, meaning a charge of +3). The Latin prefix "tetra" indicates that there are four chloride ions. Thus, our complex ion is as follows: 1. Chloride: Cl^- 2. Iron: Fe^3+ 3. Oxidation state of central ion: +3 4. Number of chloride ions: 4 Now we can combine these to generate the formula for tetrachloroferrate(III) ion: \[ \ce{[Fe(Cl)4]^{3-}} \]
02

b. Pentaammineaquaruthenium(III) ion

Here, the name of the complex ion has the following parts: 1. Central ion: ruthenium, Ru^3+ 2. Prefix penta indicates five ammine ligands: \( \ce{NH3} \) 3. One aqua ligand: \( \ce{H2O} \) 4. Oxidation state of central ion: +3 With this information, the formula for pentaammineaquaruthenium(III) ion can be written as: \[ \ce{[Ru(NH3)5(H2O)]^{3+}} \]
03

c. Tetracarbonyldihydroxochromium(III) ion

We can break down the name as follows: 1. Central ion: chromium, Cr^3+ 2. Prefix tetra indicates four carbonyl ligands: \( \ce{CO} \) 3. Prefix di indicates two hydroxo ligands: \( \ce{OH} \) 4. Oxidation state of central ion: +3 The formula for tetracarbonyldihydroxochromium(III) ion can then be written as: \[ \ce{[Cr(CO)4(OH)2]^{3-}} \]
04

d. Amminetrichloroplatinate(II) ion

Lastly, we break down the name of this complex ion: 1. Central ion: platinum, Pt^2+ 2. One ammonium ligand: \( \ce{NH3} \) 3. Prefix tri indicates three chloro ligands: Cl^- 4. Oxidation state of central ion: +2 So, the formula for amminetrichloroplatinate(II) ion is: \[ \ce{[Pt(NH3)Cl3]^{2-}} \]

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Most popular questions from this chapter

Qualitatively draw the crystal field splitting of the \(d\) orbitals in a trigonal planar complex ion. (Let the \(z\) axis be perpendicular to the plane of the complex.)

The complex ion \(\operatorname{Ru}(\text { phen })_{3}^{2+}\) has been used as a probe for the structure of DNA. (Phen is a bidentate ligand.) a. What type of isomerism is found in \(\operatorname{Ru}(\text { phen })_{3}^{2+} ?\) b. \(\operatorname{Ru}(\text { phen })_{3}^{2+}\) is diamagnetic (as are all complex ions of \(\mathrm{Ru}^{2+} \)). Draw the crystal field diagram for the \(d\) orbitals in this complex ion.

Name the following coordination compounds. a. \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Br}\right] \mathrm{Br}_{2}\) b. \(\mathrm{Na}_{3}\left[\mathrm{Co}(\mathrm{CN})_{6}\right]\) c. \(\left[\mathrm{Fe}\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\right)_{2}\left(\mathrm{NO}_{2}\right)_{2}\right] \mathrm{Cl}\) d. \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{2}\right]\left[\mathrm{PtI}_{4}\right]\)

A coordination compound of cobalt (III) contains four ammonia molecules, one sulfate ion, and one chloride ion. Addition of aqueous \(\mathrm{BaCl}_{2}\) solution to an aqueous solution of the compound gives no precipitate. Addition of aqueous \(\mathrm{AgNO}_{3}\) to an aqueous solution of the compound produces a white precipitate. Propose a structure for this coordination compound.

Iron is present in the earth's crust in many types of minerals. The iron oxide minerals are hematite \(\left(\mathrm{Fe}_{2} \mathrm{O}_{3}\right)\) and magnetite \(\left(\mathrm{Fe}_{3} \mathrm{O}_{4}\right) .\) What is the oxidation state of iron in each mineral? The iron ions in magnetite are a mixture of \(\mathrm{Fe}^{2+}\) and Fe \(^{3+}\) ions. What is the ratio of \(\mathrm{Fe}^{3+}\) to \(\mathrm{Fe}^{2+}\) ions in magnetite? The formula for magnetite is often written as \(\mathrm{FeO} \cdot \mathrm{Fe}_{2} \mathrm{O}_{3} .\) Does this make sense? Explain.
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