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Chapter 20: Problem 36

Write a balanced equation describing the reaction of aluminum metal with concentrated aqueous sodium hydroxide.

Short Answer

Expert verified
The balanced equation for the reaction of aluminum metal with concentrated aqueous sodium hydroxide is: \( 2Al + 6NaOH \rightarrow 2Al(OH)_3 + 3H_2 \)

Step by step solution

01

Write the unbalanced equation

To start, write down the formulas of the reactants and the products. Aluminum reacts with sodium hydroxide, and it produces aluminum hydroxide and hydrogen gas. The unbalanced equation is: Al + NaOH -> Al(OH)鈧� + H鈧�
02

Balance the equation

Now, we need to balance the equation by making sure there are equal numbers of atoms of each element on both sides of the equation. Start by balancing the aluminum (Al) atoms. 2Al + NaOH -> 2Al(OH)鈧� + H鈧� Now, balance the sodium (Na) atoms and adjust the hydroxide (OH) groups accordingly. 2Al + 6NaOH -> 2Al(OH)鈧� + H鈧� Lastly, balance the hydrogen (H) atoms. 2Al + 6NaOH -> 2Al(OH)鈧� + 3H鈧�
03

Confirm the balanced equation

Check that the equation is balanced by counting the atoms of each element on both sides of the equation. 2Al + 6NaOH -> 2Al(OH)鈧� + 3H鈧� Reactants: - 2 Al - 6 Na - 6 O - 12 H Products: - 2 Al - 6 Na - 6 O - 12 H Both sides have the same number of atoms for each element, so the equation is now balanced. The balanced equation for the reaction of aluminum metal with concentrated aqueous sodium hydroxide is: 2Al + 6NaOH -> 2Al(OH)鈧� + 3H鈧�

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