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Write the formula for each of the following compounds: a. ammonium hydrogen phosphate b. mercury(I) sulfide c. silicon dioxide d. sodium sulfite e. aluminum hydrogen sulfate f. nitrogen trichloride g. hydrobromic acid h. bromous acid i. perbromic acid j. potassium hydrogen sulfide k. calcium iodide l. cesium perchlorate

Short Answer

Expert verified
a. \( (NH_4)_2HPO_4 \) b. \(Hg_2S\) c. \(SiO_2\) d. \(Na_2SO_3\) e. \(Al(HSO_4)_3\) f. \(NCl_3\) g. \(HBr\) h. \(HBrO_2\) i. \(HBrO_4\) j. \(KHS\) k. \(CaI_2\) l. \(CsClO_4\)

Step by step solution

01

Identify the ions

Ammonium: \(NH_4^+\) and hydrogen phosphate: \(HPO_4^{2-}\).
02

Write the formula

Combine the ions ensuring that the charges cancel out: \( (NH_4)_2HPO_4 \). b. mercury(I) sulfide
03

Identify the ions

Mercury (I): \(Hg_2^{2+}\) and sulfide: \(S^{2-}\).
04

Write the formula

Combine the ions ensuring that the charges cancel out: \(Hg_2S\). c. silicon dioxide
05

Identify the ions

Silicon: \(Si^{4+}\) and oxide: \(O^{2-}\).
06

Write the formula

Combine the ions ensuring that the charges cancel out: \(SiO_2\). d. sodium sulfite
07

Identify the ions

Sodium: \(Na^+\) and sulfite: \(SO_3^{2-}\).
08

Write the formula

Combine the ions ensuring that the charges cancel out: \(Na_2SO_3\). e. aluminum hydrogen sulfate
09

Identify the ions

Aluminum: \(Al^{3+}\) and hydrogen sulfate: \(HSO_4^-\).
10

Write the formula

Combine the ions ensuring that the charges cancel out: \(Al(HSO_4)_3\). f. nitrogen trichloride
11

Identify the atoms

Nitrogen: N and Chlorine: Cl.
12

Write the formula

Combine the atoms according to the given prefixes: \(NCl_3\). g. hydrobromic acid
13

Identify the ions

Hydrogen: \(H^+\) and bromide: \(Br^-\).
14

Write the formula

Combine the ions ensuring that the charges cancel out: \(HBr\). h. bromous acid
15

Identify the ions

Hydrogen: \(H^+\) and bromite: \(BrO_2^-\).
16

Write the formula

Combine the ions ensuring that the charges cancel out: \(HBrO_2\). i. perbromic acid
17

Identify the ions

Hydrogen: \(H^+\) and perbromate: \(BrO_4^-\).
18

Write the formula

Combine the ions ensuring that the charges cancel out: \(HBrO_4\). j. potassium hydrogen sulfide
19

Identify the ions

Potassium: \(K^+\) and hydrogen sulfide: \(HS^-\).
20

Write the formula

Combine the ions ensuring that the charges cancel out: \(KHS\). k. calcium iodide
21

Identify the ions

Calcium: \(Ca^{2+}\) and iodide: \(I^-\).
22

Write the formula

Combine the ions ensuring that the charges cancel out: \(CaI_2\). l. cesium perchlorate
23

Identify the ions

Cesium: \(Cs^+\) and perchlorate: \(ClO_4^-\).
24

Write the formula

Combine the ions ensuring that the charges cancel out: \(CsClO_4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are formed when metals combine with non-metals. In this type of compound, atoms transfer electrons to achieve stability. The metal, which loses electrons, becomes a positively charged ion (cation), while the non-metal, which gains electrons, transforms into a negatively charged ion (anion).

These oppositely charged ions attract each other to form a stable ionic compound. Here are some examples from the exercise:
  • In mercury(I) sulfide ( Hg_2S o), mercury ions ( Hg_2^{2+} o) pair with sulfide ions ( S^{2-} o) to balance the charges.
  • Calcium iodide ( CaI_2 o) forms when calcium ions ( Ca^{2+} o) combine with iodide ions ( I^- o).
  • Cesium perchlorate ( CsClO_4 o) arises from cesium ions ( Cs^+ o) bonding with perchlorate ions ( ClO_4^- o).
The result is a neutral compound where total positive and negative charges equalize.
Molecular Compounds
Molecular compounds, unlike ionic ones, are composed of non-metals connected by covalent bonds. Instead of swapping electrons, these atoms share pairs of electrons. This sharing results in a molecule, characterized by distinct chemical properties.

For example, silicon dioxide ( SiO_2 o) is composed of silicon and oxygen. Both are non-metals, and they share electrons to form a stable compound. Additionally, nitrogen trichloride ( NCl_3 o) is formed by the sharing of electrons between nitrogen and chlorine atoms.

The covalent bonds in molecular compounds generally hold the atoms tighter together compared to ionic bonds, leading to distinct differences in physical properties like boiling and melting points.
Nomenclature
Nomenclature refers to the systematic method of naming chemical compounds. Understanding how to name compounds correctly is essential for clear communication in chemistry.

When naming ionic compounds, the cation is named first followed by the anion. For example, in ammonium hydrogen phosphate ( (NH_4)_2HPO_4 o), ammonium ( NH_4^+ o) is the cation and hydrogen phosphate ( HPO_4^{2-} o) is the anion. Similarly, in sodium sulfite ( Na_2SO_3 o), sodium is the cation and sulfite is the anion.
Molecular compounds use prefixes such as "mono-", "di-", "tri-", etc., to indicate the number of atoms. For example, in nitrogen trichloride ( NCl_3 o), the "tri-" prefix indicates three chlorine atoms.

Mastering nomenclature allows chemists to write and interpret chemical formulas efficiently.
Acid Naming
Acid naming can often seem complex, but it follows specific rules based on the anion in the acid. There are two main types of acids: binary and oxyacids.

Binary acids, like hydrobromic acid ( HBr o), consist of hydrogen and one other non-metal. These acids are named with "hydro-" plus the root of the non-metal's name and the suffix "-ic."

Oxyacids, on the other hand, contain hydrogen, oxygen, and another element. The name is based on the polyatomic ion being part of the acid. For example, bromous acid ( HBrO_2 o) uses the root of bromine, with the suffix changed to "-ous" for an ion with fewer oxygen atoms. Meanwhile, perbromic acid ( HBrO_4 o) employs "per-", indicating a higher number of oxygen atoms in the ion, and "-ic".
  • Understanding the nuances of acid naming helps in identifying the components of the acids.

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Most popular questions from this chapter

How many protons and neutrons are in the nucleus of each of the following atoms? In a neutral atom of each element, how many electrons are present? a. \(^{79} \mathrm{Br}\) b. \(^{81} \mathrm{Br}\) c. \(^{239} \mathrm{Pu}\) d. \(^{133} \mathrm{Cs}\) e. \(^{3} \mathrm{H}\) f. \(^{56} \mathrm{Fe}\)

Which of the following statements is(are) correct? a. The symbols for the elements magnesium, aluminum, and xenon are Mn, Al, and Xe, respectively. b. The elements \(P,\) As, and \(B\) i are in the same family on the periodic table. c. All of the following elements are expected to gain electrons to form ions in ionic compounds: Ga, Se, and Br. d. The elements \(\mathrm{Co},\) Ni, and Hg are all transition elements. e. The correct name for \(\mathrm{TiO}_{2}\) is titanium dioxide.

In a reaction, 34.0 g of chromium(III) oxide reacts with 12.1 g of aluminum to produce chromium and aluminum oxide. If 23.3 g of chromium is produced, what mass of aluminum oxide is produced?

Name the compounds in parts a鈥揹 and write the formulas for the compounds in parts e鈥揾. a. \(\operatorname{NaBr}\) b. \(\mathrm{Rb}_{2} \mathrm{O}\) c. \(\mathrm{CaS}\) d. d. \(\mathrm{AlI}_{3}\) e. strontium fluoride f. aluminum selenide g. potassium nitride h. magnesium phosphide

The early alchemists used to do an experiment in which water was boiled for several days in a sealed glass container. Eventually, some solid residue would appear in the bottom of the flask, which was interpreted to mean that some of the water in the flask had been converted into 鈥渆arth.鈥 When Lavoisier repeated this experiment, he found that the water weighed the same before and after heating, and the mass of the flask plus the solid residue equaled the original mass of the flask. Were the alchemists correct? Explain what really happened. (This experiment is described in the article by A. F. Scott in Scientific American, January 1984.)

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