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Indium oxide contains 4.784 \(\mathrm{g}\) of indium for every 1.000 \(\mathrm{g}\) of oxygen. In \(1869,\) when Mendeleev first presented his version of the periodic table, he proposed the formula \(\operatorname{In}_{2} \mathrm{O}_{3}\) for indium oxide. Before that time it was thought that the formula was InO. What values for the atomic mass of indium are obtained using these two formulas? Assume that oxygen has an atomic mass of 16.00 .

Short Answer

Expert verified
Using the formulas InO and In₂O₃ and the given mass ratio, the calculated values for the atomic mass of Indium are 76.544 g per atom for InO and 114.816 g per atom for In₂O₃.

Step by step solution

01

Determine the mass of Oxygen in both formulas

In the InO formula, there is one Oxygen atom, so the mass of Oxygen will be its atomic mass (16.00g). In the In₂O₃ formula, there are three Oxygen atoms, so the mass of Oxygen will be three times its atomic mass (48.00 g).
02

Calculate the mass of Indium in both formulas using the mass ratio.

Using the given mass ratio, we will determine the mass of Indium in both formulas. In the InO formula: For 1g of Oxygen, there are 4.784g of Indium; For 16g of Oxygen (equal to one Oxygen atom), there will be: \( 16 \times 4.784 \) = \( 76.544 g \) of Indium (one Indium atom). In the In₂O₃ formula: For 1g of Oxygen, there are 4.784g of Indium; For 48g of Oxygen (equal to three Oxygen atoms), there will be: \( 48 \times 4.784 \) = \( 229.632 g \) of Indium (two Indium atoms).
03

Determine the atomic mass of Indium for each formula.

For the InO formula: There is one Indium atom, so the atomic mass of Indium is equal to the total mass of Indium in the InO formula, which is 76.544 g per atom. For the In₂O₃ formula: There are two Indium atoms, so we need to divide the total mass of Indium in the In₂O₃ formula by 2 to find the atomic mass of Indium. \( \frac{229.632}{2} \) = \( 114.816 g \) per atom. So, the values for atomic mass of Indium that are obtained using the formulas are: InO: 76.544 g per atom In₂O₃: 114.816 g per atom

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The periodic table is a crucial tool in chemistry that organizes all known chemical elements. It arranges elements by increasing atomic number, which is the number of protons in an atom. This arrangement reveals recurring trends in element properties called periodicity. For instance, elements in the same column, known as groups, often exhibit similar chemical behavior.

Mendeleev is credited with the introduction of the first well-organized periodic table in 1869. His table was noteworthy because he left gaps for undiscovered elements and even predicted their properties based on patterns. These predictions include the formulas of compounds they would form, such as predicting the formula for indium oxide as In₂O₃. This shows how the periodic table has been a powerful predictive tool in chemistry.
Indium Oxide
Indium oxide is a compound formed between indium and oxygen. Its chemical formula signifies the ratio of indium to oxygen atoms in the compound. Indium oxide is important in various high-tech applications, such as transparent conductors in displays.

The different proposed formulas for indium oxide, InO and In₂O₃, arise from different historical understandings of atomic masses. The formula InO suggests a simpler mixture of one indium atom per oxygen atom, whereas In₂O₃ implies a compound with two indium atoms for every three oxygen atoms. Adjusting the formula changes the calculated atomic structure and affects chemical properties.
Chemical Formulas
Chemical formulas are symbolic representations of molecules and compounds, showing the elements involved and their proportions. These formulas are significant because they convey essential information about the substance, such as its composition and the number of atoms of each element.

For example, the formula In₂O₃ for indium oxide indicates that two indium atoms bond with three oxygen atoms. This contrasts with the simpler formula InO, which suggests a one-to-one ratio between indium and oxygen. Understanding how these formulas are derived and what they signify is critical for working in chemistry, as the formula impacts properties and reactions.
Oxygen Atomic Mass
The atomic mass of oxygen is essential in calculating molecular masses and chemical reactions. It represents the mass of an oxygen atom relative to carbon-12, which has been assigned a mass of exactly 12. This makes oxygen's atomic mass approximately 16.00 on the atomic mass scale.

In our indium oxide example, knowing that the atomic mass of oxygen is 16.00 helps determine the overall mass of oxygen in compounds. For the InO formula, there is one oxygen atom contributing 16.00 g. In In₂O₃, three oxygen atoms contribute a collective 48.00 g to the compound's mass. This knowledge is crucial for solving problems involving molar masses and stoichiometry in chemistry.

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Most popular questions from this chapter

The two most reactive families of elements are the halogens and the alkali metals. How do they differ in their reactivities?

In Section 1.1 of the text, the concept of a chemical reaction was introduced with the example of the decomposition of water, represented as follows: Use ideas from Dalton’s atomic theory to explain how the above representation illustrates the law of conservation of mass.

A sample of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) contains 2.02 \(\mathrm{g}\) of hydrogen, 32.07 \(\mathrm{g}\) of sulfur, and 64.00 \(\mathrm{g}\) of oxygen. How many grams of sulfur and grams of oxygen are present in a second sample of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) containing 7.27 \(\mathrm{g}\) of hydrogen?

Each of the following statements is true, but Dalton might have had trouble explaining some of them with his atomic theory. Give explanations for the following statements. a. The space-filling models for ethyl alcohol and dimethyl ether are shown below. These two compounds have the same composition by mass \((52 \% \text { carbon, } 13 \% \text { hydrogen, and } 35 \% \text { oxygen }),\) yet the two have different melting points, boiling points, and solubilities in water. b. Burning wood leaves an ash that is only a small fraction of the mass of the original wood. c. Atoms can be broken down into smaller particles. d. One sample of lithium hydride is 87.4\(\%\) lithium by mass, while another sample of lithium hydride is 74.9\(\%\) lithium by mass. However, the two samples have the same chemical properties.

Early tables of atomic weights (masses) were generated by measuring the mass of a substance that reacts with 1.00 g of oxygen. Given the following data and taking the atomic mass of hydrogen as 1.00, generate a table of relative atomic masses for oxygen, sodium, and magnesium. How do your values compare with those in the periodic table? How do you account for any differences?

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