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Chapter 2: Problem 10

Dalton assumed that all atoms of the same element were identical in all their properties. Explain why this assumption is not valid.

Short Answer

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In summary, Dalton's assumption that all atoms of the same element are identical in all their properties is not valid due to the discovery of isotopes. Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons, resulting in variations in their atomic mass and other properties, such as chemical reactivity and radioactivity. This demonstrates that atoms of the same element can indeed have different properties, disproving Dalton's assumption.

Step by step solution

01

Introduction to Dalton's Atomic Theory

Dalton's atomic theory was proposed in the early 1800s. One of its main postulates was that all atoms of the same element are identical in every aspect, including their mass and properties. However, we now know that this assumption is not entirely accurate, mainly due to the discovery of isotopes. Let's discuss isotopes and how they show that atoms of the same element can have different properties.
02

Understanding Isotopes

Isotopes are atoms of the same element that have the same number of protons (atomic number) but different numbers of neutrons. Since they have the same number of protons, they are considered to be of the same element. However, their differing numbers of neutrons result in variations in their atomic masses and other properties. For example, carbon-12 and carbon-14 are two isotopes of the element carbon. Both have six protons, but carbon-12 has six neutrons, and carbon-14 has eight neutrons.
03

Variations in Mass

Due to the different numbers of neutrons, isotopes of the same element have different atomic masses. In the example of carbon-12 and carbon-14, carbon-12 has an atomic mass of 12 atomic mass units (amu), while carbon-14 has an atomic mass of 14 amu. This variation in mass proves that not all atoms of the same element are identical, as per Dalton's assumption.
04

Variations in Other Properties

In addition to differences in atomic mass, isotopes may also exhibit variations in other properties, such as chemical reactivity and radioactive behavior. For example, carbon-14 is radioactive, while carbon-12 is not. The difference in radioactive behavior is due to the instability caused by having more neutrons in carbon-14 compared to carbon-12.
05

Conclusion

In conclusion, Dalton's assumption that all atoms of the same element are identical in their properties is not valid. The discovery of isotopes has shown that atoms of the same element can have different numbers of neutrons, resulting in variations in atomic mass and other properties. This disproves the idea that all atoms of the same element are identical in every aspect.

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Most popular questions from this chapter

In a reaction, 34.0 g of chromium(III) oxide reacts with 12.1 g of aluminum to produce chromium and aluminum oxide. If 23.3 g of chromium is produced, what mass of aluminum oxide is produced?

You have gone back in time and are working with Dalton on a table of relative masses. Following are his data. 0.602 g gas A reacts with 0.295 g gas \(\mathrm{B}\) 0.172 \(\mathrm{g}\) gas \(\mathrm{B}\) reacts with 0.401 \(\mathrm{g}\) gas \(\mathrm{C}\) 0.320 \(\mathrm{g}\) gas A reacts with 0.374 \(\mathrm{g}\) gas \(\mathrm{C}\) a. Assuming simplest formulas (AB, BC, and AC), construct a table of relative masses for Dalton. b. Knowing some history of chemistry, you tell Dalton that if he determines the volumes of the gases reacted at constant temperature and pressure, he need not assume simplest formulas. You collect the following data: 6 volumes gas \(\mathrm{A}+1\) volume gas \(\mathrm{B} \rightarrow\) 4 volumes product 1 volume gas \(\mathrm{B}+4\) volumes gas \(\mathrm{C} \rightarrow\) 4 volumes product 3 volumes gas \(\mathrm{A}+2\) volumes gas \(\mathrm{C} \rightarrow\) 6 volumes product Write the simplest balanced equations, and find the actual relative masses of the elements. Explain your reasoning.

In the periodic table, how many elements are found in each of the following? a. Group 2A b. the oxygen family c. the nickel group d. Group 8A

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Consider 80.0-g samples of two different compounds consisting of only carbon and oxygen. One of the compounds consists of 21.8 g of carbon, and the other has 34.3 g of carbon. Determine the ratio in whole numbers of the masses of carbon that combine with 1.00 g of oxygen between the two compounds.
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