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Calculate \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) for each solution at \(25^{\circ} \mathrm{C}\) . Identify each solution as neutral, acidic, or basic. a. \(\mathrm{pH}=7.40\) (the normal pH of blood) b. \(\mathrm{pH}=15.3\) c. \(\mathrm{pH}=-1.0\) d. \(\mathrm{pH}=3.20\) e. \(\mathrm{pOH}=5.0\) f. \(\mathrm{pOH}=9.60\)

Short Answer

Expert verified
a. H鈦 = 3.98脳10鈦烩伕 M, OH鈦 = 2.51脳10鈦烩伔 M, slightly basic b. H鈦 = 5.01脳10鈦宦光伓 M, OH鈦 = 19.95 M, basic c. H鈦 = 10 M, OH鈦 = 1脳10^鈦宦光伒 M, acidic d. H鈦 = 6.31脳10鈦烩伌 M, OH鈦 = 1.58脳10^鈦宦孤 M, acidic e. H鈦 = 1脳10^鈦烩伖 M, OH鈦 = 1脳10鈦烩伒 M, basic f. H鈦 = 3.98脳10^鈦烩伒 M, OH鈦 = 2.51脳10^鈦宦光伆 M, acidic

Step by step solution

01

Calculate H鈦 ion concentration

Use the formula: pH = -log[H鈦篯 Hence, H鈦 = 10^(-pH) = 10^(-7.40) = 3.98脳10鈦烩伕 M
02

Calculate OH鈦 ion concentration

Use the formula: pH + pOH = 14 pOH = 14 - pH = 14 - 7.40 = 6.60 Then use the formula: pOH = -log[OH鈦籡 Hence, OH鈦 = 10^(-pOH) = 10^(-6.60) = 2.51脳10鈦烩伔 M
03

Identify the solution type

Since pH is slightly greater than 7, the solution is slightly basic. b. pH = 15.3
04

Calculate H鈦 ion concentration

H鈦 = 10^(-pH) = 10^(-15.3) = 5.01脳10^鈦宦光伓 M
05

Calculate OH鈦 ion concentration

pOH = 14 - pH = 14 - 15.3 = -1.3 OH鈦 = 10^(-pOH) = 10^(1.3) = 19.95 M
06

Identify the solution type

Since pH is greater than 7, the solution is basic. c. pH = -1.0
07

Calculate H鈦 ion concentration

H鈦 = 10^(-pH) = 10^1 = 10 M
08

Calculate OH鈦 ion concentration

pOH = 14 - pH = 14 - (-1.0) = 15 OH鈦 = 10^(-pOH) = 10^(-15) = 1脳10^鈦宦光伒 M
09

Identify the solution type

Since pH is less than 7, the solution is acidic. d. pH = 3.20
10

Calculate H鈦 ion concentration

H鈦 = 10^(-pH) = 10^(-3.2) = 6.31脳10鈦烩伌 M
11

Calculate OH鈦 ion concentration

pOH = 14 - pH = 14 - 3.20 = 10.8 OH鈦 = 10^(-pOH) = 10^(-10.8) = 1.58脳10^鈦宦孤 M
12

Identify the solution type

Since pH is less than 7, the solution is acidic. e. pOH = 5.0
13

Calculate OH鈦 ion concentration

OH鈦 = 10^(-pOH) = 10^(-5.0) = 1脳10鈦烩伒 M
14

Calculate H鈦 ion concentration

pH = 14 - pOH = 14 - 5 = 9 H鈦 = 10^(-pH) = 10^(-9) = 1脳10^鈦烩伖 M
15

Identify the solution type

Since pH is greater than 7, the solution is basic. f. pOH = 9.60
16

Calculate OH鈦 ion concentration

OH鈦 = 10^(-pOH) = 10^(-9.6) = 2.51脳10^鈦宦光伆 M
17

Calculate H鈦 ion concentration

pH = 14 - pOH = 14 - 9.60 = 4.4 H鈦 = 10^(-pH) = 10^(-4.4) = 3.98脳10^鈦烩伒 M
18

Identify the solution type

Since pH is less than 7, the solution is acidic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

acidic and basic solutions
Let's dive into the fascinating world of acidic and basic solutions. The acidity or basicity of a solution is determined by its pH level. In simple terms, - Solutions with a pH less than 7 are considered **acidic**. These solutions have a higher concentration of hydrogen ions (H鈦). Popular examples include lemon juice and vinegar. - Solutions with a pH greater than 7 are considered **basic** or **alkaline**. Here, hydroxide ions (OH鈦) prevail, like in baking soda or soapy water. - When the pH is exactly 7, the solution is **neutral**, like pure water.
Understanding these categories helps in identifying the nature of various solutions, be it in biological systems, industrial processes, or everyday life. The pH scale, ranging from 0 to 14, serves as a quick reference to gauge where a solution stands. A lower pH means more acid, and a higher pH means more base. In the real world, balancing these solutions is crucial, especially in environmental science and healthcare, where pH plays a pivotal role in processes like digestion and aquatic life sustenance.
H+ ion concentration
Understanding hydrogen ion concentration is key to grasping the concept of pH. The pH scale is logarithmic, based on the concentration of H鈦 ions:- **pH** is calculated using the formula: \[ \text{pH} = -\log[\text{H}^+] \]This formula dictates that as the concentration of H鈦 ions increases, the pH value decreases.
When dealing with exercises, a small change in pH reflects a significant shift in H鈦 ion concentration due to this exponential relationship. Thus, even a minute change can indicate a drastic alteration in the solution's properties.When calculating H鈦 from pH, remember:- Use the inverse calculation: \[ [\text{H}^+] = 10^{-\text{pH}} \]This equation lets us derive the precise concentration of H鈦 ions in moles per liter (Molarity, M) from any pH value.
Such calculations are invaluable, whether you are checking the acidity of rainwater or making a buffer solution in a lab experiment. The H鈦 ion concentration truly unlocks the power to predict and control chemical reactions based on their acidity.
OH- ion concentration
Hydroxide ion concentration complements our understanding of pH and plays a crucial role in the pH-pOH relationship within chemistry. The basic relationship between pH and pOH is:\[ \text{pH} + \text{pOH} = 14 \]In an ideal scenario at 25掳C, this equation forms the basis for calculating either component when one is known. If you have the pH, you can instantly find pOH, and vice versa.For hydroxide ions (OH鈦), the concentration is found using the formula:\[ [\text{OH}^-] = 10^{-\text{pOH}} \]This calculation unveils the concentration of OH鈦 ions in molarity (M), providing insight into a solution's basicity.By determining both H鈦 and OH鈦 concentrations, we gain a comprehensive view of a solution's chemical nature. This is essential whether you're analyzing blood pH in medicine or understanding the cleaning power of detergents. The ability to calculate and adjust OH鈦 levels helps control and harness basic solutions effectively.

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Most popular questions from this chapter

When determining the pH of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) solutions, sometimes the \(\mathrm{H}^{+}\) contribution from \(\mathrm{HSO}_{4}^{-}\) can be ignored by the 5\(\%\) rule. At what concentrations of an \(\mathrm{H}_{2} \mathrm{SO}_{4}\) solution can the \(\mathrm{H}^{+}\) contribution from \(\mathrm{HSO}_{4}^{-}\) be ignored when determining the pH of the solution?

A \(1.0 \times 10^{-2}-M\) solution of cyanic acid (HOCN) is 17\(\%\) dissociated. Calculate \(K_{\mathrm{a}}\) for cyanic acid.

A typical aspirin tablet contains 325 mg acetylsalicylic acid \(\left(\mathrm{HC}_{9} \mathrm{H}_{7} \mathrm{O}_{4}\right) .\) Calculate the \(\mathrm{pH}\) of a solution that is prepared by dissolving two aspirin tablets in enough water to make one \(\operatorname{cup}(237 \mathrm{mL})\) of solution. Assume the aspirin tablets are pure acetylsalicylic acid, \(K_{\mathrm{a}}=3.3 \times 10^{-4}\) .

What mass of \(\mathrm{NaOH}(s)\) must be added to 1.0 \(\mathrm{L}\) of 0.050 \(\mathrm{M}\) \(\mathrm{NH}_{3}\) to ensure that the percent ionization of \(\mathrm{NH}_{3}\) is no greater than 0.0010\(\% ?\) Assume no volume change on addition of \(\mathrm{NaOH} .\)

Hemoglobin (abbreviated Hb) is a protein that is responsible for the transport of oxygen in the blood of mammals. Each hemoglobin molecule contains four iron atoms that are the binding sites for \(\mathrm{O}_{2}\) molecules. The oxygen binding is pH- dependent. The relevant equilibrium reaction is $$ \mathrm{HbH}_{4}^{4+}(a q)+4 O_{2}(g) \rightleftharpoons \mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4}(a q)+4 \mathrm{H}^{+}(a q) $$ Use Le Ch芒telier's principle to answer the following. a. What form of hemoglobin, HbH \(_{4}^{4+}\) or \(\mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4},\) is favored in the lungs? What form is favored in the cells? b. When a person hyperventilates, the concentration of \(\mathrm{CO}_{2}\) in the blood is decreased. How does this affect the oxygen-binding equilibrium? How does breathing into a paper bag help to counteract this effect? (See Exercise \(146 .\) ) c. When a person has suffered a cardiac arrest, injection of a sodium bicarbonate solution is given. Why is this necessary? (Hint: CO, blood levels increase during cardiac arrest.)

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