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Phosphoric acid is a common ingredient in traditional cola drinks. It is added to provide the drinks with a pleasant tart taste. Assuming that in cola drinks the concentration of phosphoric acid is \(0.007 M,\) calculate the \(\mathrm{pH}\) of this solution.

Short Answer

Expert verified
The pH of the cola drink solution containing 0.007 M phosphoric acid is approximately 2.20.

Step by step solution

01

Write the dissociation expression for phosphoric acid

Phosphoric acid, H鈧働O鈧, is a triprotic weak acid which means it can release three hydrogen ions. However, for simplicity, we'll consider only the first dissociation step: H鈧働O鈧 <--> H鈦 + H鈧侾O鈧勨伝 Now, write the acid dissociation constant expression, Ka鈧, for this reaction: Ka鈧 = \(\frac{[H鈦篯[H鈧侾O鈧勨伝]}{[H鈧働O鈧刔}\)
02

Set up the reaction's equilibrium concentrations

Let x represent the amount of H鈧働O鈧 that dissociates. At equilibrium, we'll have the following concentrations: [H鈧働O鈧刔 = 0.007 M - x [H鈦篯 = x [H鈧侾O鈧勨伝] = x We can rewrite the acid dissociation constant expression using these concentrations: Ka鈧 = \(\frac{x^2}{0.007 - x}\)
03

Make an approximation to simplify the equation

Since phosphoric acid is a weak acid and doesn't dissociate much, we can make the approximation that x << 0.007. This allows us to simplify the equation as follows: Ka鈧 鈮 \(\frac{x^2}{0.007}\)
04

Solve for the concentration of H鈧僌鈦 ions

The Ka鈧 value of phosphoric acid is 7.1 脳 10鈦宦. Now, we can solve for x: 7.1 脳 10鈦宦 鈮 \(\frac{x^2}{0.007}\) x虏 = 7.1 脳 10鈦宦 脳 0.007 x = 鈭(7.1 脳 10鈦宦 脳 0.007) x 鈮 0.00634 M The concentration of H鈧僌鈦 ions (or H鈦 ions) is approximately 0.00634 M.
05

Calculate the pH of the solution

Now that we have the concentration of H鈧僌鈦 ions, we can find the pH using the formula: pH = -log鈧佲個[H鈧僌鈦篯 pH 鈮 -log鈧佲個(0.00634) pH 鈮 2.20 The pH of the cola drink solution containing 0.007 M phosphoric acid is approximately 2.20.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phosphoric Acid
Phosphoric acid, known chemically as \(\text{H}_3\text{PO}_4\), is a triprotic acid, meaning it can donate three protons (\(\text{H}^+\) ions). This characteristic makes it unique among acids. Yet, it is more common to discuss its first dissociation step because this is typically the strongest. This first step can be represented by the equation: \[\text{H}_3\text{PO}_4 \rightleftharpoons \text{H}^+ + \text{H}_2\text{PO}_4^-\]Phosphoric acid's ability to release protons gives it the acidic properties that influence taste, such as in cola drinks. Lower levels of phosphoric acid contribute to a tart and tangy flavor. Despite its acidic nature, phosphoric acid is considered a weak acid because it does not fully dissociate in solution.
Equilibrium Concentration
In a chemical reaction, equilibrium concentration refers to the concentrations of the reactant and product molecules at equilibrium. For phosphoric acid, when it reaches equilibrium in water, the amount of acid that has dissociated into ions and the amount that remains in molecular form balance out.In our exercise, we have an initial concentration of \(0.007 M\) phosphoric acid. At equilibrium, the concentrations are adjusted based on how much \(\text{H}_3\text{PO}_4\) dissociates. Let's say "\(x\)" is the change due to dissociation:
  • \([\text{H}_3\text{PO}_4] = 0.007 - x\)
  • \([\text{H}^+] = x\)
  • \([\text{H}_2\text{PO}_4^-] = x\)
This finds a state where the reaction neither proceeds forward nor backward significantly, maintaining stable concentrations of these entities.
Acid Dissociation Constant
The acid dissociation constant, \(K_a\), is a numerical value that indicates the strength of an acid in solution. For phosphoric acid, we're interested in \(K_{a1}\), which pertains to the first dissociation step. This constant provides a way to quantify how easily the acid donates its protons to the surrounding solution.The equation for the dissociation constant is:\[K_{a1} = \frac{[\text{H}^+][\text{H}_2\text{PO}_4^-]}{[\text{H}_3\text{PO}_4]}\]Given \(K_{a1}\) as \(7.1 \times 10^{-3}\), we can predict the extent of dissociation in the solution. A low \(K_a\) value, like in weak acids such as phosphoric acid, indicates minimal tendency to dissociate, which means less hydrogen ion production compared to strong acids.
pH Calculation
Calculating the pH of a solution helps us understand its acidity. The pH scale ranges from 0 to 14, with lower values indicating higher acidity. To find the pH, we use the concentration of hydrogen ions, \([\text{H}^+]\), determined from the equilibrium concentrations.The formula to find pH is:\[\text{pH} = -\log_{10}[\text{H}_3\text{O}^+]\]From our steps, we solved to find \([\text{H}_3\text{O}^+] = 0.00634 M\). Using the formula, the pH is approximately calculated as:\[\text{pH} \approx -\log_{10}(0.00634) \approx 2.20\]This low pH value confirms that the solution is quite acidic, which matches the tartness experienced in beverages like cola that contain phosphoric acid.

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Most popular questions from this chapter

The \(\mathrm{pH}\) of a \(0.016-M\) aqueous solution of \(p\) -toluidine \(\left(\mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\right)\) is 8.60 . Calculate \(K_{\mathrm{b}}\) .

Hemoglobin (abbreviated Hb) is a protein that is responsible for the transport of oxygen in the blood of mammals. Each hemoglobin molecule contains four iron atoms that are the binding sites for \(\mathrm{O}_{2}\) molecules. The oxygen binding is pH- dependent. The relevant equilibrium reaction is $$ \mathrm{HbH}_{4}^{4+}(a q)+4 O_{2}(g) \rightleftharpoons \mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4}(a q)+4 \mathrm{H}^{+}(a q) $$ Use Le Ch芒telier's principle to answer the following. a. What form of hemoglobin, HbH \(_{4}^{4+}\) or \(\mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4},\) is favored in the lungs? What form is favored in the cells? b. When a person hyperventilates, the concentration of \(\mathrm{CO}_{2}\) in the blood is decreased. How does this affect the oxygen-binding equilibrium? How does breathing into a paper bag help to counteract this effect? (See Exercise \(146 .\) ) c. When a person has suffered a cardiac arrest, injection of a sodium bicarbonate solution is given. Why is this necessary? (Hint: CO, blood levels increase during cardiac arrest.)

Place the species in each of the following groups in order of increasing acid strength. Explain the order you chose for each group. a. \(\mathrm{HIO}_{3}, \mathrm{HBrO}_{3}\) b. \(\mathrm{HNO}_{2}, \mathrm{HNO}_{3}\) c. HOCl, HOI d. \(\mathrm{H}_{3} \mathrm{PO}_{4}, \mathrm{H}_{3} \mathrm{PO}_{3}\)

Are solutions of the following salts acidic, basic, or neutral? For those that are not neutral, write balanced equations for the reactions causing the solution to be acidic or basic. The relevant \(K_{\mathrm{a}}\) and \(K_{\mathrm{b}}\) values are found in Tables 14.2 and \(14.3 .\) \(\begin{array}{ll}{\text { a. } \operatorname{Sr}\left(\mathrm{NO}_{3}\right)_{2}} & {\text { d. } \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{3} \mathrm{ClO}_{2}} \\ {\text { b. } \mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}} & {\text { e. } \mathrm{NH}_{4} \mathrm{F}} \\ {\text { c. } \mathrm{CH}_{3} \mathrm{NH}_{3} \mathrm{O} \mathrm{l}} & {\text { f. } \mathrm{CH}_{3} \mathrm{NH}_{3} \mathrm{CN}}\end{array}\)

Classify each of the following as a strong acid, weak acid, strong base, or weak base in aqueous solution. a. \(\mathrm{HNO}_{2}\) b. HNO \(_{3}\) c. \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) d. \(\mathrm{NaOH}\) e. \(\mathrm{NH}_{3}\) f. \(\mathrm{HF}\) g. \(\mathrm{HC}-\mathrm{OH}\) h. \(\mathrm{Ca}(\mathrm{OH})_{2}\) i. \(\mathrm{H}_{2} \mathrm{SO}_{4}\)

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