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n lab you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. a. 2.0 \(\mathrm{mKCl}\) in water (density of \(\mathrm{H}_{2} \mathrm{O}=1.00 \mathrm{g} / \mathrm{cm}^{3} )\) b. 15\(\% \mathrm{NaOH}\) by mass in water \(\left(d=1.00 \mathrm{g} / \mathrm{cm}^{3}\right)\) c. 25\(\% \mathrm{NaOH}\) by mass in \(\mathrm{CH}_{3} \mathrm{OH}\left(d=0.79 \mathrm{g} / \mathrm{cm}^{3}\right)\) d. 0.10 mole fraction of \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) in water \(\left(d=1.00 \mathrm{g} / \mathrm{cm}^{3}\right)\)

Short Answer

Expert verified
To prepare the four solutions: a. 2.0 m KCl in water: 1. Weigh 14.91 g of KCl. 2. Dissolve KCl in ~80 mL water in a beaker. 3. Transfer to a 100 mL volumetric flask and add water up to the mark. 4. Mix thoroughly. b. 15% NaOH in water: 1. Weigh 15 g of NaOH. 2. Dissolve NaOH in ~80 mL water in a beaker. 3. Transfer to a 100 mL volumetric flask and add water up to the mark. 4. Mix thoroughly. c. 25% NaOH in CH鈧僌H: 1. Weigh 25 g of NaOH. 2. Dissolve NaOH in ~60 mL CH鈧僌H in a beaker. 3. Add CH鈧僌H until total mass reaches 104 g. 4. Mix thoroughly. d. 0.10 mole fraction of C鈧咹鈧佲倐O鈧 in water: 1. Weigh 111.24 g of C鈧咹鈧佲倐O鈧. 2. Dissolve C鈧咹鈧佲倐O鈧 in ~80 mL water in a beaker. 3. Transfer to a 100 mL volumetric flask and add water up to the mark. 4. Mix thoroughly.

Step by step solution

01

Calculate the mass of KCl required

Firstly, we must define that a 2.0 m (molal) KCl solution means that there are 2.0 moles of KCl in 1 kg of solvent (water). Now, let's assume that we have to prepare 100 mL of this solution. Since the density of water is 1.00 g/cm鲁, the mass of 100 mL of water is: Mass of water = Density 脳 Volume = 1.00 g/cm鲁 脳 100 mL = 100 g In 1 kg of water, there are 2.0 moles of KCl, so in 100 g of water, there will be: 2.0 moles 脳 100 g/1000 g = 0.2 moles of KCl Now, we need to convert moles to mass. The molar mass of KCl is approximately 39.10 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol. Thus, the mass of KCl required is: Mass = Moles 脳 Molar mass= 0.2 moles 脳 74.55 g/mol = 14.91 g
02

Prepare the KCl solution

To prepare the 2.0 m KCl solution: 1. Weigh 14.91 g of KCl using a balance. 2. Add the KCl to a beaker containing approximately 80 mL of water. 3. Stir until the KCl is completely dissolved. 4. Transfer the solution to a 100 mL volumetric flask using a funnel, rinse the beaker with water, and pour the rinsing into the flask. 5. Add water to the volumetric flask until the 100 mL mark is reached. 6. Stir or invert the flask to ensure uniform mixing. b. 15% NaOH by mass in water
03

Calculate the mass of NaOH required

Let's assume we need to prepare 100 mL of the 15% NaOH solution. The mass of 100 mL of water is 100 g. A 15% NaOH by mass solution means that there are 15 g of NaOH in 100 g of solution. Therefore, the mass of NaOH required is 15 g.
04

Prepare the NaOH solution

To prepare the 15% NaOH solution: 1. Weigh 15 g of NaOH using a balance. 2. Add the NaOH to a beaker containing approximately 80 mL of water. 3. Stir until the NaOH is completely dissolved. 4. Transfer the solution to a 100 mL volumetric flask using a funnel, rinse the beaker with water, and pour the rinsing into the flask. 5. Add water to the volumetric flask until the 100 mL mark is reached. 6. Stir or invert the flask to ensure uniform mixing. c. 25% NaOH by mass in CH鈧僌H
05

Calculate the mass of NaOH and CH鈧僌H required

For a 25% NaOH by mass solution, there are 25 g of NaOH in every 100 g of solution. Firstly, we need to determine the mass of the CH鈧僌H required to obtain 100 mL of the final solution. The density of CH鈧僌H is 0.79 g/cm鲁: Mass of CH鈧僌H = Density 脳 Volume = 0.79 g/cm鲁 脳 100 mL = 79 g Now, we must calculate the total mass of the NaOH and CH鈧僌H in the solution: Total mass = mass of NaOH + mass of CH鈧僌H = 25 g + 79 g = 104 g
06

Prepare the NaOH in CH鈧僌H solution

To prepare the 25% NaOH in CH鈧僌H solution: 1. Weigh 25 g of NaOH using a balance. 2. Add the NaOH to a beaker containing approximately 60 mL of CH鈧僌H. 3. Stir until the NaOH is completely dissolved. 4. Add more CH鈧僌H to the beaker until the total mass reaches 104 g using a balance. 5. Stir or invert the beaker to ensure uniform mixing. d. 0.10 mole fraction of C鈧咹鈧佲倐O鈧 in water
07

Calculate the mass of C鈧咹鈧佲倐O鈧 required

Let's assume we are preparing 100 mL of a solution of C鈧咹鈧佲倐O鈧 in water with a 0.10 mole fraction. Firstly, we will find the moles of C鈧咹鈧佲倐O鈧 and water in the solution: When X(C鈧咹鈧佲倐O鈧) = 0.10, X(H鈧侽) = 1 - X(C鈧咹鈧佲倐O鈧) = 0.90 Using mole fraction equation: n(C鈧咹鈧佲倐O鈧) = X(C鈧咹鈧佲倐O鈧) 脳 n(total) = 0.10 脳 n(total); n(H鈧侽) = X(H鈧侽) 脳 n(total) = 0.90 脳 n(total) Total mass of 100 mL of water is 100 g. Since we are given the solution's density as 1.00 g/cm鲁, the volume of the solution is also 100 mL. To calculate the moles of H鈧侽 in 100 g, using its molar mass (18 g/mol): n(H鈧侽) = mass(H鈧侽) / Molar mass(H鈧侽) = 100 g / 18 g/mol 鈮 5.56 moles Now, we can find n(total): n(total) = n(H鈧侽) / X(H鈧侽) = 5.56 moles / 0.90 鈮 6.18 moles And, we calculate the moles of C鈧咹鈧佲倐O鈧: n(C鈧咹鈧佲倐O鈧) = X(C鈧咹鈧佲倐O鈧) 脳 n(total) = 0.10 脳 6.18 moles 鈮 0.618 moles Now we can find the mass of C鈧咹鈧佲倐O鈧, using its molar mass (180 g/mol): Mass(C鈧咹鈧佲倐O鈧) = n(C鈧咹鈧佲倐O鈧) 脳 Molar mass(C鈧咹鈧佲倐O鈧) = 0.618 moles 脳 180 g/mol 鈮 111.24 g
08

Prepare the C鈧咹鈧佲倐O鈧 solution

To prepare the 0.10 mole fraction C鈧咹鈧佲倐O鈧 solution: 1. Weigh 111.24 g of C鈧咹鈧佲倐O鈧 using a balance. 2. Add the C鈧咹鈧佲倐O鈧 to a beaker containing approximately 80 mL of water. 3. Stir until the C鈧咹鈧佲倐O鈧 is completely dissolved. 4. Transfer the solution to a 100 mL volumetric flask using a funnel, rinse the beaker with water, and pour the rinsing into the flask. 5. Add water to the volumetric flask until the 100 mL mark is reached. 6. Stir or invert the flask to ensure uniform mixing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concentration Calculations
Concentration calculations are crucial for accurately preparing solutions in any chemical experiment. Concentration indicates how much solute is present in a given quantity of solvent or total solution. There are several ways to express concentration, such as molarity, molality, percent by mass, and mole fraction.
- **Molarity (M)** is the number of moles of solute per liter of solution. It is often used when diluting solutions to a desired concentration. - **Molality (m)** is the number of moles of solute per kilogram of solvent. This unit remains constant with temperature changes and is useful in precise calculations, like those in colligative properties. - **Percent by mass** measures the mass of the solute relative to the mass of the solution, usually expressed as a percentage. - **Mole fraction** indicates the ratio of the number of moles of one component to the total number of moles in the solution. By understanding these measurements, you can accurately calculate how much substance is needed for specific solutions, ensuring successful outcomes in your experiments.
Molar Mass
Molar mass is a key component in solution preparation because it allows you to convert between the amount of substance (moles) and its mass (grams). Each element in the periodic table has a defined atomic mass, usually given in atomic mass units (amu) or grams per mole (g/mol). The molar mass of a compound is the sum of the molar masses of its constituent elements.
For example, the molar mass of potassium chloride (KCldata-math=" KCl ") is calculated by adding the molar masses of potassium (39.10 g/mol) and chlorine (35.45 g/mol), arriving at a total of 74.55 g/mol.
When preparing a solution, you will often need to convert the required moles of solute into grams using its molar mass; this is done with the formula: \[\text{Mass (g)} = \text{Moles} \times \text{Molar Mass (g/mol)}\]With this, you can accurately measure the quantity of each compound needed for your solution, ensuring precise results every time.
Density
Density is a physical property that relates the mass of a substance to its volume. It is expressed as grams per cubic centimeter (g/cm鲁) or kilograms per liter (kg/L). This concept is particularly important when preparing solutions because it helps determine the mass of solvents needed based on required volumes.
For example, if you know that water has a density of 1.00 g/cm鲁, then 100 mL of water would weigh 100 g. - **Importance in Solution Preparation**: Knowing the density of a liquid allows you to convert volume to mass, which is vital in measurements and mixing. - **Application**: Calculate the mass of solvents like methanol (density = 0.79 g/cm鲁) when preparing solutions to ensure proper concentration ratios. When working with various solvents, always refer to their densities to ensure your calculations lead to successful solutions as planned.
Volumetric Flask Usage
Volumetric flasks are essential laboratory glassware used for preparing precise solution concentrations. They are designed to accurately measure a specific volume of liquid, marked by a line on the narrow neck of the flask. Here鈥檚 how they are properly used in solution preparation: - **Start by dissolving** the solute in a smaller volume of liquid: This ensures complete dissolving and avoids contaminating the precise measurements. - **Transfer the solution**: Use a funnel to carefully pour the prepared solution into the volumetric flask to avoid spillage. - **Rinse the original container**: Always rinse the beaker you originally used with a little more solvent, pouring the rinsing into the flask. This ensures that any residue is transferred. - **Fill to the calibration line**: Add solvent carefully until you reach the marked line, ensuring accuracy. - **Mix thoroughly**: After sealing with a stopper, invert the flask multiple times to ensure homogeneity and uniform concentration distribution throughout the solution. Volumetric flasks provide the accuracy needed in solution preparation, making them indispensable in any chemistry lab setting.

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Most popular questions from this chapter

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