Chapter 10: Problem 101
What quantity of energy does it take to convert 0.500 \(\mathrm{kg}\) ice at \(-20.0^{\circ} \mathrm{C}\) to steam at \(250.0^{\circ} \mathrm{C} ?\) Specific heat capacities: ice, \(2.03 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} ;\) liquid, \(4.18 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} ;\) steam, 2.02 \(\mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}\) \(\Delta H_{\mathrm{vap}}=40.7 \mathrm{kJ} / \mathrm{mol} ; \Delta H_{\mathrm{fus}}=6.02 \mathrm{kJ} / \mathrm{mol} .\)
Short Answer
Step by step solution
Convert mass to grams
Heat the ice to 0°C
Melt the ice to water
Heat the water to 100°C
Vaporize water to steam
Heat the steam to 250°C
Calculate the total energy
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat Capacity
For example, the specific heat capacity of ice is 2.03 J/g°C. This means you need 2.03 joules of energy to raise the temperature of one gram of ice by one degree Celsius. The exercise involves heating ice from -20°C to 0°C, which requires the formula:
- Formula: \[ Q = m \times C \times \Delta T \]
- Where:
- \( Q \) is the heat energy.
- \( m \) is the mass.
- \( C \) is the specific heat capacity.
- \( \Delta T \) is the change in temperature.
Phase Change
In the exercise, the phase changes include:
- Solid ice to liquid water, which requires melting.
- Liquid water to gaseous steam, which involves boiling or vaporization.
Enthalpy of Fusion
The process requires calculating the moles of the substance and applying the enthalpy of fusion:
- Given: \( \Delta H_{fus} = 6.02 \text{ kJ/mol} \)
- To find the energy needed, use:
- \[ Q = n \times \Delta H_{fus} \]
Enthalpy of Vaporization
For vaporization, the calculation involves:
- Given: \( \Delta H_{vap} = 40.7 \text{ kJ/mol} \)
- To find the energy needed, follow:
- \[ Q = n \times \Delta H_{vap} \]