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A sulfuric acid solution has a density of \(1.8 \mathrm{~g} / \mathrm{ml}\) and is \(90 \%\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) by weight. What weight of \(\mathrm{H}_{2} \mathrm{SO}_{4}\), is present in 1000 \(\mathrm{ml}\) of the solution? What is the molarity of the solution? the normality?

Short Answer

Expert verified
Weight of H鈧係O鈧 = \( 0.90 \times (1.8 g/ml \times 1000 ml) = 1620 g \) Moles of H鈧係O鈧 = \( \frac{1620 g}{98.08 g/mol} = 16.52 mol \) Molarity of H鈧係O鈧 = \( \frac{16.52 mol}{1 L} = 16.52 M \) Normality of H鈧係O鈧 = \( 16.52 M \times 2 = 33.04 N \) In 1000 ml of the given sulfuric acid solution, there are 1620 g of H鈧係O鈧 with a molarity of 16.52 M and a normality of 33.04 N.

Step by step solution

01

Calculate the total weight of the solution

Using the density, convert the volume of the solution to its total weight: Weight of solution = Density 脳 Volume Weight of solution = 1.8 g/ml 脳 1000 ml
02

Calculate the weight of H鈧係O鈧 in the solution

Given that H鈧係O鈧 accounts for 90% of the weight of the solution, we can determine how much H鈧係O鈧 is present in 1000 ml: Weight of H鈧係O鈧 = Percentage of H鈧係O鈧 脳 Total weight of solution Weight of H鈧係O鈧 = 90% 脳 (1.8 g/ml 脳 1000 ml)
03

Calculate the moles of H鈧係O鈧

To find the molarity, we first need to determine the moles of H鈧係O鈧 using the molecular weight (98.08 g/mol): Moles of H鈧係O鈧 = Weight of H鈧係O鈧 / Molecular weight of H鈧係O鈧
04

Calculate the molarity of H鈧係O鈧

Now, we can calculate the molarity of the solution by dividing the moles of H鈧係O鈧 by the volume of the solution in liters: Molarity of H鈧係O鈧 = Moles of H鈧係O鈧 / Volume of solution in liters
05

Calculate the normality of H鈧係O鈧

To calculate the normality of the solution, we need to consider the number of hydrogen ions (H鈦) that can be released by one molecule of H鈧係O鈧. Since H鈧係O鈧 is a strong diacid, it can release 2 H鈦 ions. Therefore, the normality can be determined as follows: Normality of H鈧係O鈧 = Molarity of H鈧係O鈧 脳 Number of H鈦 ions released per molecule (2) Now let's plug in the values from the previous steps to find the weight, molarity, and normality of the given sulfuric acid solution:

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solution Density
Understanding the density of a solution is crucial when conducting calculations in chemistry. Density is defined as the mass of a substance divided by its volume. For a sulfuric acid solution with a density of 1.8 g/ml, this means that each milliliter of the solution weighs 1.8 grams.

To find the total weight of the solution, simply multiply the volume of the solution by its density. In our example, a 1000 ml volume of sulfuric acid solution would weigh 1.8 g/ml times 1000 ml, resulting in a total weight of 1800 grams.
Percentage Concentration
Percentage concentration provides a measure of how much solute is present in a solution relative to the total weight of the solution, expressed as a percentage. For a sulfuric acid solution that is 90% \(\mathrm{H}_2\mathrm{SO}_4\) by weight, it signifies that out of every 100 grams of the solution, 90 grams are pure \(\mathrm{H}_2\mathrm{SO}_4\) and the remaining 10 grams are other components or impurities.

By knowing the percentage concentration and the total weight of the solution, we can calculate the weight of the sulfuric acid present in the solution. For example, in a 1000 ml solution with a density of 1.8 g/ml, the amount of \(\mathrm{H}_2\mathrm{SO}_4\) present would be 90% of the total weight (which is 1800 grams), thus equaling 1620 grams.
Molarity
Molarity, a term frequently used in chemistry, describes the concentration of a solution in terms of moles of solute per liter of solution (mol/L). It's a way to quantify how concentrated or dilute a solution is. To calculate molarity, you need to know the moles of the solute in question and the volume of the solution in liters.

Moles of a substance can be obtained by dividing the weight of the solute by its molecular weight. For sulfuric acid \(\mathrm{H}_2\mathrm{SO}_4\) with a molecular weight of 98.08 g/mol, if you have 1620 grams of it in a solution, simply divide this weight by 98.08 g/mol to obtain the moles. Then, divide the moles of \(\mathrm{H}_2\mathrm{SO}_4\) by the volume of the solution in liters to calculate molarity.
Normality
Normality is another measure of concentration that takes into account the reactive capacity of the solute. Specifically, for acids and bases, it relates to the number of hydrogen or hydroxide ions that can be donated or accepted. For \(\mathrm{H}_2\mathrm{SO}_4\) that is a diprotic acid, meaning it can donate two hydrogen ions \(\mathrm{H}^+\) per molecule, the normality is twice the molarity.

After calculating the molarity, find the normality for \(\mathrm{H}_2\mathrm{SO}_4\) by multiplying the molarity by 2. This value will tell you the equivalent per liter of solution regarding its capacity to donate hydrogen ions, which is particularly important in titration calculations.
Moles of Solute
The mole is a fundamental unit in chemistry that represents a specific number of particles, atoms, or molecules. When you calculate the moles of solute, you determine how many moles are present in a given weight of that substance. The formula to calculate moles is to divide the weight of the solute by its molecular weight.

For 1620 grams of \(\mathrm{H}_2\mathrm{SO}_4\) with a molecular weight of 98.08 g/mol, the calculation would be 1620 g / 98.08 g/mol, resulting in approximately 16.53 moles of \(\mathrm{H}_2\mathrm{SO}_4\) in the solution. This is a crucial step for finding the molarity, as moles of solute are a key component in that calculation.

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