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A chemist wants to dilute \(50 \mathrm{ml}\) of \(3.50 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) to \(2.00 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\). To what volume must it be diluted?

Short Answer

Expert verified
The chemist must dilute the 50 mL of 3.50 M H鈧係O鈧 solution to \(87.5 \mathrm{mL}\) to achieve a concentration of 2.00 M.

Step by step solution

01

Write down the given information

We are given the following information: Initial concentration, c鈧 = 3.50 M Initial volume, V鈧 = 50 mL Desired final concentration, c鈧 = 2.00 M
02

Write down the dilution formula

We can use the dilution formula to find the final volume: c鈧乂鈧 = c鈧俈鈧
03

Plug in the given values to the formula

Now, plug in the given values into the formula: (3.50 M)(50 mL) = (2.00 M)V鈧
04

Solve for the final volume V鈧

Rearrange and solve for V鈧: V鈧 = (3.50 M * 50 mL) / (2.00 M)
05

Calculate the final volume V鈧

Now, divide the product of the initial concentration and volume by the final concentration to get the final volume: V鈧 = (3.50 * 50) / (2.00) V鈧 = 175 / 2 V鈧 = 87.5 mL The chemist must dilute the 50 mL of 3.50 M H鈧係O鈧 solution to \(87.5 \mathrm{mL}\) to achieve a concentration of 2.00 M.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Solution Concentration
In chemistry, the concentration of a solution is a critical concept, defining how much solute is present in a given volume of solution. This concentration can be represented in several ways, but molarity is one of the most common. Molarity, denoted by the symbol M, measures the number of moles of solute per liter of solution.
For example, a 3.50 M solution of sulfuric acid ( H鈧係O鈧 ) means there are 3.50 moles of H鈧係O鈧 molecules in every liter of the solution. The concentration is essential to know how reactants will interact in a chemical reaction and determines the dosage needed in applications. Concentration is adjustable; you can change it by altering the amount of solute or solvent.
Molarity Calculations Simplified
Molarity calculations are essential for working with solutions and involve finding or working with the concentration of solutes in a solution. The basic formula for molarity is:\[ M = \frac{n}{V} \]where M is the molarity, n is the number of moles of solute, and V is the volume of the solution in liters.
In practical terms, molarity helps us understand how concentrated a solution is. For instance, when given a solution of 50 mL with a concentration of 3.50 M, we know it equates to 3.50 moles of solute per liter of that H鈧係O鈧 solution. Sometimes, you may need to use molarity calculations to determine the amount of solute needed to make up a solution of desired volume and concentration. Additionally, these calculations are critical for understanding the mix between reactants in a solution.
What is the Dilution Formula?
Dilution involves lowering the concentration of a solute in a solution, usually by adding more solvent. This process is critical when the concentration needs to be adjusted for specific reactions or uses. The dilution formula provides a simple way to determine how to achieve the desired concentration:\[ c鈧乂鈧 = c鈧俈鈧 \]Where c鈧 and V鈧 are the initial concentration and volume, respectively, and c鈧 and V鈧 are the final concentration and volume after dilution.
In the given exercise, the chemist needed to dilute 50 mL of a 3.50 M H鈧係O鈧 solution to reach a concentration of 2.00 M. By using the dilution formula, they calculated the final volume, V鈧, required to achieve the desired concentration was 87.5 mL. This calculation shows how you can alter a solution's concentration without changing the quantity of solute, simply by increasing the solution's volume.

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