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Chapter 33: Problem 968

Find Antilog \(2.3625\).

Short Answer

Expert verified
The antilog of 2.3625 is approximately 230.266.

Step by step solution

01

Understanding the antilogarithm concept

An antilogarithm, as mentioned in the analysis, is the inverse of the logarithm function. Specifically, if \(y = \log_{b}x\), then \(x = b^y\). In this exercise, we're given a logarithmic value of 2.3625, and we're required to find the number (x) whose logarithm (base 10) is equal to this value. Step 2: Calculate the antilog:
02

Calculating the antilogarithm

Assuming the base of our logarithm is 10, we use the antilogarithm formula mentioned in step 1 to find the number whose logarithm would result in the given value. So, \(x = 10^{2.3625}\) Now, you'll need to use a scientific calculator or the antilog table to find the value of \( 10^{2.3625}\). Step 3: Present the final answer:
03

Antilog value

After calculating the value of \( 10^{2.3625}\), we find that: Antilog(2.3625) = 230.266 (rounded to three decimal places)

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