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A cylinder contains \(40 \mathrm{~g} \mathrm{He}, 56 \mathrm{~g} \mathrm{~N}_{2}\), and \(40 \mathrm{~g}\) Ar. (a) What is the mole fraction of each gas in the mixture? (b) If the total pressure of the mixture is \(10 \mathrm{~atm}\), what is the partial pressure of \(\mathrm{He}\) ?

Short Answer

Expert verified
(a) The mole fractions of He, Nâ‚‚, and Ar are 0.769, 0.154, and 0.077, respectively. (b) The partial pressure of He in the cylinder is 7.69 atm.

Step by step solution

01

Calculate the moles of each gas

To calculate the moles of each gas, we'll use the formula: moles = mass / molar_mass where mass is in grams and molar_mass is in grams/mol. The molar_mass of He, Nâ‚‚, and Ar are 4 g/mol, 28 g/mol, and 40 g/mol, respectively. For He: moles_He = 40 g / 4 g/mol = 10 moles For Nâ‚‚: moles_N2 = 56 g / 28 g/mol = 2 moles For Ar: moles_Ar = 40 g / 40 g/mol = 1 mole
02

Calculate the total moles and mole fraction of each gas

To calculate the total moles, add the moles of He, Nâ‚‚, and Ar: total_moles = moles_He + moles_N2 + moles_Ar = 10 + 2 + 1 = 13 moles Now, we'll calculate the mole fraction of each gas using: mole_fraction = moles_of_gas / total_moles For He: mole_fraction_He = 10 / 13 = 0.769 For Nâ‚‚: mole_fraction_N2 = 2 / 13 = 0.154 For Ar: mole_fraction_Ar = 1 / 13 = 0.077 (a) The mole fraction of He, Nâ‚‚, and Ar are 0.769, 0.154, and 0.077, respectively.
03

Calculate the partial pressure of He

To calculate the partial pressure of He, we'll use the formula: partial_pressure_He = total_pressure × mole_fraction_He where total_pressure is given as 10 atm. partial_pressure_He = 10 atm × 0.769 = 7.69 atm (b) The partial pressure of He in the cylinder is 7.69 atm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Mole Fraction
The mole fraction is an important concept when dealing with gas mixtures. It indicates the proportion of a particular gas in a mixture relative to the total number of moles in that mixture. It's an expression of concentration that doesn't have units. To find the mole fraction of a gas, you use the formula:
  • \( \text{mole fraction} = \frac{\text{moles of gas}}{\text{total moles of mixture}} \)
For example, in a mixture containing helium, nitrogen, and argon, you first determine the moles of each gas using their respective masses and molar masses. Add up these mole values to find the total moles of the mixture. Each gas's mole fraction is then calculated by dividing its moles by the total moles. For helium in this scenario, the calculated mole fraction is approximately 0.769, meaning it makes up about 76.9% of the gas mixture by moles. This calculation helps chemists understand the gas composition in various applications, such as chemical reactions or industrial processes.
Understanding Partial Pressure
Partial pressure refers to the pressure exerted by an individual gas within a mixture of gases. Each gas in a mixture contributes to the total pressure proportionally according to its mole fraction. The relationship between mole fraction and partial pressure is described by Dalton's Law of Partial Pressures.
  • The formula is: \( \text{partial pressure of gas} = \text{total pressure} \times \text{mole fraction of the gas} \)
In practice, to find the partial pressure of helium in a gas cylinder, given that the total pressure inside is 10 atm, multiply the total pressure by helium's mole fraction (0.769). The result is a partial pressure of approximately 7.69 atm for helium. This concept is crucial in fields like meteorology, respiratory physiology, and many engineering applications, where understanding how different gases exert pressure can impact system design and function.
Understanding Molar Mass
Molar mass is a fundamental concept in chemistry, representing the mass of one mole of a given substance. It is usually expressed in grams per mole (g/mol) and forms the basis for converting mass into moles, which is essential for stoichiometry and chemical equations.
  • Using molar mass, you can find number of moles: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \)
In our gas mixture, the molar masses of helium, nitrogen, and argon were used to determine the number of moles for each gas from their given masses. For instance, helium's molar mass is 4 g/mol, so 40 grams correspond to 10 moles. Understanding molar mass allows scientists and engineers to calculate the amounts of substances needed for reactions, to determine product yields, and to balance chemical equations accurately. It's a keystone concept that serves as a bridge between the macroscopic and molecular worlds in chemistry.

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Most popular questions from this chapter

A sample of air held in a graduated cylinder over water has a volume of \(88.3 \mathrm{ml}\) at a temperature of \(18.5^{\circ} \mathrm{C}\) and a pressure of \(741 \mathrm{~mm}\) (see figure). What would the volume of the air be if it were dry and at the same temperature and pressure?

The volume of hydrogen evolved during the course of a reaction is measured by the displacement of water as shown in the diagram below. Hydrogen is evolved in flask \(\mathrm{A}\) and displaces water from flask B into beaker C. If, during a particular run of this experiment in which atmospheric pressure is 765 torr and the water temperature is \(293.15^{\circ} \mathrm{K}\), \(65.0 \mathrm{ml}\) of water is displaced, how much water would be displaced at 760 torr and \(298.15^{\circ} \mathrm{K} ?\) (The equilibrium vapor pressure of water at \(293.15^{\circ} \mathrm{K}\) is \(17.5\) torr and at \(298.15^{\circ} \mathrm{K}\) is 23,8 torr.

Graham's law states that the rate at which gas molecules escape through a small orifice (rate of effusion) is inversely proportional to the square root of the density of the gas. Derive Graham's law from the following assumptions: (a) temperature is directly proportional to the average kinetic energy of the molecules; (b) the rate of effusion is directly proportional to the root mean square speed of the molecules; (c) the density of a gas at constant temperature and pressure is directly proportional to the molecular mass.

A sample of hydrogen is collected in a bottle over water. By carefully raising and lowering the bottle, the height of the water outside is adjusted so that it is just even with the water level inside (see figure) . When a sample of gas was collected the initial conditions were: volume \(=425 \mathrm{ml}\), pressure \(=753 \mathrm{~mm}\) and the temperature of the water (and thus, the gas also) \(=34^{\circ} \mathrm{C}\). Calculate the volume of the hydrogen if it were dry and at a pressure of \(760 \mathrm{~mm}\) and a temperature of \(0^{\circ} \mathrm{C}\) (STP)

Two balloons at the same temperature of equal volume and porosity are each filled to a pressure of 4 atmospheres, one with \(16 \mathrm{~kg}\) of oxygen, the other with \(1 \mathrm{~kg}\) of hydrogen. The oxygen balloon leaks to a pressure of \(1 / 2\) atmosphere (atm) in 1 hour. How long will it take for the hydrogen balloon to reach a pressure of \(1 / 2 \mathrm{~atm} ?\)

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