Chapter 24: Problem 855
Explain what is meant by primary, secondary, and tertiary treatment of sewage.
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Chapter 24: Problem 855
Explain what is meant by primary, secondary, and tertiary treatment of sewage.
These are the key concepts you need to understand to accurately answer the question.
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Phosphate can be removed from sewage effluent by adding magnesium oxide and ammonium ion according to the reaction \(5 \mathrm{H}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{PO}^{-}{ }_{4}+\mathrm{MgO}+\mathrm{NH}^{+}{ }_{4} \rightarrow \mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) The magnesium ammonium phosphate hexahydrate \(\left(\mathrm{Mg}\left(\mathrm{NH}_{4}\right) \mathrm{PO}_{4}-6 \mathrm{H}_{2} \mathrm{O}\right)\) precipitates out. In theory, how much of this could be produced if a city processes 5 million gal. (41.7 million lb.) daily of wastewater containing \(30 \mathrm{ppm}\) \(\mathrm{H}_{2} \mathrm{PO}^{-}{ }_{4} ?(1\) pound \(=453.59 \mathrm{~g} .)\)
The following observations have been made on a typical day in Los Angeles: The hydrocarbon content in the atmosphere starts to rise at about 6 A.M. It peaks at 8 A.M. and dies off at 10 A.M. A similar peaked curve occurs at 6 P.M. About 2 hours after each peak, the ozone concentration rises. How can you explain these observations?
Given that the earth's mean radius \(=6.37 \times 10^{6} \mathrm{~m}\), normal atmosphere pressure \(=1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}_{2}\), and the gravitational acceleration \(=9.8 \mathrm{~m} / \mathrm{sec}^{2}\), what is the mass of the homosphere?
The average concentration of particulate lead in a city with highly polluted air is \(5 \mu \mathrm{g} / \mathrm{m}^{3}\). If an adult respires 8500 liters of air daily and if 50 per cent of the particles below \(1 \mu \mathrm{m}\) in size are retained in the lungs, calculate how much lead is absorbed in the lungs each day. Of the particulate lead in urban air, 75 per cent is less than \(1 \mu \mathrm{m}\) in size.
If the carbon dioxide content of the air doubled, what would happen to the temperature of the earth. Explain your answer.
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