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What is the osmotic pressure at \(20 .{ }^{\circ} \mathrm{C}\) of (a) \(0.010 \mathrm{M}\) complete dissociation of the \(\mathrm{CaCl}_{2}\).

Short Answer

Expert verified
\Pi = 7.20 \, atm

Step by step solution

01

Understanding the concept of Osmotic Pressure

Osmotic pressure is the pressure that must be applied to prevent osmotically active particles' flow across a semipermeable membrane. It is given by the formula \(\Pi = i M R T\), where \(\Pi\) is the osmotic pressure, \(i\) is the van't Hoff factor (the number of particles the solute dissociates into), \(M\) is the molarity of the solution, \(R\) is the ideal gas constant, and \(T\) is the temperature in Kelvin.
02

Calculating the van't Hoff factor (i) for \(\mathrm{CaCl}_{2}\)

Since \(\mathrm{CaCl}_{2}\) dissociates into one \(\mathrm{Ca}^{2+}\) ion and two \(\mathrm{Cl}^{-}\) ions, the van't Hoff factor, \(i\), for \(\mathrm{CaCl}_{2}\) is 3.
03

Converting the temperature to Kelvin

The temperature in Celsius is 20 degrees, so to convert to Kelvin, we add 273.15: \( T = 20 + 273.15 = 293.15 \, K\).
04

Using the formula to calculate the osmotic pressure

Plug the values into the formula \(\Pi = i M R T\). Given the molarity \(M = 0.010 \, M\), the ideal gas constant \(R = 0.0821 \, \text{L·atm/mol·K}\), and the calculated temperature in Kelvin, the osmotic pressure can be calculated as \(\Pi = 3 × 0.010 \, M × 0.0821 \, \text{L·atm/mol·K} × 293.15 \, K\).
05

Calculating the final value

Calculating the final value of the osmotic pressure gives us \(\Pi = 3 × 0.010 × 0.0821 × 293.15 = 7.19745 \, atm\), which can be rounded to two decimal places, as standard in most scientific contexts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

van't Hoff factor
The van't Hoff factor, represented by the symbol 'i', is a dimensionless number that indicates the number of particles into which a solute dissociates in solution. It's one of the key factors in determining the osmotic pressure of a solution. For non-electrolytes, which do not dissociate, the van't Hoff factor is equal to 1. However, for electrolytes like salts, acids, and bases, this factor can be greater than 1.

For example, in the case of calcium chloride (CaCl2), a common electrolyte, the dissociation in water would be as follows: CaCl2 → Ca2+ + 2 Cl-The van't Hoff factor here is 3 because one formula unit of CaCl2 dissociates into three separate ions. It's essential to determine the exact number of particles produced during dissociation to properly calculate the osmotic pressure, as any deviation from the expected van't Hoff factor can significantly impact the calculation's outcome.
dissociation in electrolytes
Dissociation in electrolytes refers to the process by which ionic compounds separate into their constituent ions when dissolved in a solvent such as water. This phenomenon is crucial because it affects properties such as conductivity and osmotic pressure of solutions. Understanding the extent to which an electrolyte dissociates helps in predicting the behavior of the solution in various chemical processes.

For the electrolyte calcium chloride (CaCl2), full dissociation would imply it completely separates into one Ca2+ ion and two Cl- ions. In practical scenarios, not all ionic compounds fully dissociate. This is why the actual concentration of ions in a solution might differ from the initial concentration of the electrolyte. Therefore, when calculating osmotic pressure, it's important to know whether the dissociation is complete or partial to apply the correct van't Hoff factor.
ideal gas constant
The ideal gas constant, often represented by the letter 'R', is a physical constant that appears in the equation of state for ideal gases. It serves as a bridge connecting various units of measure in the realm of gas laws. The value of 'R' can vary depending on the units used for pressure, volume, temperature, and the amount of substance.

In the context of osmotic pressure calculations, 'R' is commonly expressed as 0.0821 L·atm/mol·K, which accommodates the units of liters for volume, atmospheres for pressure, moles for the amount of substance, and Kelvin for temperature. The ideal gas constant is fundamental in the formula to calculate osmotic pressure because it relates the physical quantities involved to the inherent energy per mole per unit temperature of a gas.
converting Celsius to Kelvin
Temperature conversions are essential in scientific calculations as they ensure consistency and accuracy. The Kelvin scale is the base unit of temperature in the International System of Units (SI), and it is often used in scientific equations, including those for osmotic pressure. To convert Celsius to Kelvin, which is crucial for osmotic pressure calculations, you need to add 273.15 to the Celsius temperature.

To illustrate:If the temperature is 20°C, the conversion to Kelvin is as follows:T(K) = 20°C + 273.15 = 293.15 KThis step guarantees that the temperature is in the correct unit for the osmotic pressure formula and avoids any errors that could arise from unit mismatches. Accurate temperature conversion is indispensable in chemistry where reactions are sensitive to even slight variations in temperature.

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Most popular questions from this chapter

Interpret the following verse from the Coleridge's Rime of the Ancient Mariner: Water, water, every where, And all the boards did shrink, Water, water every where, Nor any drop to drink.

Catalase, a liver enzyme, dissolves in warer. A \(10.0-\mathrm{mL}\). solution containing \(0.166 \mathrm{~g}\) of catalase exhibits an osmotic pressure of \(1.2\) Torr at \(20 .{ }^{\circ} \mathrm{C}\). What is the molar mass of catalase? $.

Consider an apparatus in which \(A\) and B are two \(1.00-\mathrm{L}\) flasks joined by a stopcock \(\mathrm{C}\). The volume of the stopcock is negligible. Initially, \(\mathrm{A}\) and \(\mathrm{B}\) are evacuated, the stopcock \(\mathrm{C}\) is dosed, and \(1.50 \mathrm{~g}\) of diethyl ether, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}\), is introduced into flask A. The vapor pressure of diethyl ether is 57 Torr at \(-45^{\circ} \mathrm{C}\), 185 Torr at \(0 .{ }^{\circ} \mathrm{C}, 534\) Torr at \(25^{\circ} \mathrm{C}\), and negligible below \(-86^{\circ} \mathrm{C}\). (a) If the stopcock is left closed and the flask is brought to equilibrium at \(-45^{\circ} \mathrm{C}\), what will be the pressure of diethyl ether in flask A? (b) If the temperature is raised to \(25^{\circ} \mathrm{C}\), what will be the pressure of diethyl ether in the flask? (c) If the temperature of the assembly is returned to \(-45^{\circ} \mathrm{C}\) and the stopcock \(\mathrm{C}\) is opened, what will be the pressure of diethyl ether in the apparatus? (d) If flask \(\mathrm{A}\) is maintained at \(-45^{\circ} \mathrm{C}\) and flask B is cooled with liquid nitrogen (boiling point, \(-196^{\circ} \mathrm{C}\) ) with the stopcock open, what changes will take place in the apparatus? Assume ideal behavior.

A \(0.20-\mathrm{g}\) sample of a polymer, dissolved in \(0.100 \mathrm{~L}\) of toluene, has an osmotic pressure of \(6.3\) Torr at \(20 .{ }^{\circ} \mathrm{C}\). What is the molar mass of the polymer?

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