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The internal energy of a system increased by \(982 \mathrm{~J}\) when it absorbed \(492 \mathrm{~J}\) of heat. (a) Was work done by or on the system? (b) How much work was done?

Short Answer

Expert verified
Work was done on the system, and the amount of work done was 490 Joules.

Step by step solution

01

Understanding the First Law of Thermodynamics

Recall the first law of thermodynamics, which states that the change in internal energy of a system (∆U) is equal to the heat added to the system (Q) minus the work done by the system (W), expressed as ∆U = Q - W. This law indicates that the energy change in a system can be the result of heat flow and work.
02

Assessing If Work Was Done By or On the System

In this scenario, the system absorbed heat (Q) and the internal energy increased (∆U). If Q is greater than ∆U, work was done by the system, as it would have used some energy to do work. Conversely, if Q is less than ∆U, work was done on the system, as it would require external work to increase its energy more than the absorbed heat.
03

Calculating the Work Done

We are given that ∆U is 982 Joules and Q is 492 Joules. We can rearrange the first law equation to solve for work: W = Q - ∆U. Inserting the given values gives us W = 492 J - 982 J = -490 J. The negative sign indicates that work was done on the system. The magnitude of work done on the system is 490 Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
Internal energy is a key concept in thermodynamics that refers to the total energy contained within a system. It encompasses all the kinetic and potential energies of the particles making up the system. Unlike external factors like temperature and pressure, which can influence a system from the outside, internal energy is a property inherent to the system's state.

To understand how changes in a system’s internal energy occur, imagine a gas in a sealed container. The molecules of gas are in constant motion, possessing kinetic energy. The faster they move, the higher their kinetic energy. If the gas is heated, these particles move more rapidly, increasing the internal energy of the system. Interestingly, we cannot measure a system's total internal energy directly, but we can measure changes in internal energy, which are critical for analyzing thermodynamic processes.

In our exercise, the increase in a system's internal energy is given by the numerical value of 982 Joules, indicating that energy has been transferred into the system, resulting in increased motion or potential interactions among its particles.
Heat Transfer
Heat transfer is the process through which thermal energy moves from one place to another. It can occur in three fundamental ways: conduction, convection, and radiation. Understanding heat transfer is essential in thermodynamics as it explains how energy moves through systems and their surroundings.

In conduction, heat moves through a material without the material itself moving. This happens, for example, when you heat one end of a metal rod; gradually, the other end becomes hot due to the transfer of kinetic energy from one particle to another. Convection involves the bulk movement of a fluid (such as air or water) where warmer parts move away from the heat source, carrying energy with them. Radiation, on the other hand, is the transfer of energy by electromagnetic waves and can occur in a vacuum, like the heat from the sun reaching Earth.

In our textbook exercise, the system under consideration absorbs 492 Joules of heat. This absorption indicates an inflow of thermal energy into the system, which is one mechanism through which the internal energy of the system can increase.
Work Done in Thermodynamics
When we talk about 'work done' in thermodynamics, we're referring to the energy transferred when a force is applied to an object causing it to move. Work, like heat, can either be transferred into or out of a system. It's a form of energy change in the system governed by processes such as compression or expansion of gases, or movement of pistons in an engine.

It's important to note that the convention in thermodynamics is to consider work done by the system on its surroundings as positive, while work done on the system by the surroundings is negative. This convention aids in applying the first law of thermodynamics consistently across problems.

In the given exercise, the system has work done on it equivalent to 490 Joules. Since the system is not expanding or performing work on its environment, but rather being compressed or influenced in such a way that its internal energy increases, the work is considered negative in the context of the system's energy balance.

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Most popular questions from this chapter

The standard enthalpies of combustion of graphite and diamond are \(-393.51 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\) and \(-395.41 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), respectively. Calculate the enthalpy of the graphite \(\rightarrow\) diamond transition.

A gas sample in a piston assembly expands, doing \(536 \mathrm{~kJ}\) of work on its surroundings at the same time that \(214 \mathrm{~kJ}\) of heat is added to the gas. (a) What is the change in internal energy of the gas during this process? (b) Will the pressure of the gas be higher or lower when these changes are completed?

(a) Calculate the work associated with the isothermal, reversible expansion of \(1.000 \mathrm{~mol}\) of an ideal gas from \(7.00 \mathrm{~L}\) to \(15.50 \mathrm{~L}\) at \(25.0^{\circ} \mathrm{C}\). (b) Calculate the work associated with the irreversible adiabatic expansion of the sample of gas described in part (a) against a constant atmospheric pressure of 760 . Torr. (c) How will the temperature of the gas in part (b) compare with that in part (a) after the expansion?

Each of the four cylinders of a new type of combustion engine has a displacement of \(3.60 \mathrm{~L}\). (The volume of the cylinder expands \(3.60 \mathrm{~L}\) each time the fuel is ignited.) (a) If each piston in the four cylinders is displaced against a pressure of \(1.80 \mathrm{kbar}\) and each cylinder is ignited once per second, how much work can the engine do in \(1.00\) minute? (b) Is the work positive or negative with respect to the engine and its contents?

For a certain reaction at constant pressure, \(\Delta U=-72 \mathrm{~kJ}\), and \(35 \mathrm{~kJ}\) of expansion work is done by the system. What is \(\Delta H\) for this process?

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