/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Hemocyanin is a Cu-containing ox... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Hemocyanin is a Cu-containing oxygen-binding protein that is found in some invertebrates. In squid hemocyanin, when the partial pressure of oxygen gas is \(0.13\) atm at \(25^{\circ} \mathrm{C}\), the oxygen binding sites are \(33 \%\) saturated. Assuming that each hemocyanin molecule binds one molecule of oxygen gas, calculate the equilibrium constant. What are the units of the equilibrium constant? Calculate the standard state free energy change when hemocyanin interacts with \(\mathrm{O}_{2}(\mathrm{aq})\). The solubility of pure oxygen in water at \(1 \mathrm{~atm}\) and \(25{ }^{\circ} \mathrm{C}\) is \(0.00117 \mathrm{~mol}\) \(\left(\mathrm{kg} \mathrm{H}_{2} \mathrm{O}\right)^{-1}\).

Short Answer

Expert verified
The equilibrium constant is 32.96 L/mol, and \( \Delta G^0 \) is \(-8.654 \text{ kJ/mol} \).

Step by step solution

01

Write the equilibrium expression

The hemocyanin and oxygen interaction can be summarized by the reaction: \[ \text{Hemocyanin (Hc) + O}_2 \leftrightarrow \text{Hc-O}_2 \]. The equilibrium constant \( K \) for this reaction is given by the expression: \[ K = \frac{[\text{Hc-O}_2]}{[\text{Hc}][\text{O}_2]} \].
02

Calculate the concentrations

Given that the oxygen binding sites are 33% saturated, then 33% of hemocyanin is bound with oxygen, and 67% is free. Assume initial hemocyanin concentration is \( C \):- \([\text{Hc-O}_2] = 0.33C \)- \([\text{Hc}] = 0.67C \)The concentration of \( \text{O}_2 \) is given by Henry's law: \( [\text{O}_2] = k_H \times P_{\text{O}_2} \), where \( k_H \) is the solubility of oxygen in water at 1 atm.
03

Calculate Henry's law constant

Using the solubility of oxygen: \( k_H = 0.00117 \text{ mol/L} \) at 1 atm, then:\[ [\text{O}_2] = 0.00117 \times 0.13 = 0.0001521 \text{ mol/L} \]
04

Substitute into the equilibrium expression

Using the expression for \( K \):\[ K = \frac{[\text{Hc-O}_2]}{[\text{Hc}][\text{O}_2]} = \frac{0.33C}{0.67C \times 0.0001521} \]This simplifies to:\[ K = \frac{0.33}{0.67 \times 0.0001521} = 32.96 \text{ L/mol} \]
05

Determine the units of the equilibrium constant

For the reaction \( Hc + O_2 \leftrightarrow Hc-O_2 \), the units of \( K \) are \( \text{L/mol} \) because concentration terms cancel out but \([\text{O}_2]\) remains.
06

Calculate the standard free energy change

The standard free energy change \( \Delta G^0 \) is calculated using the formula:\[ \Delta G^0 = -RT \ln K \]where \( R = 8.314 \text{ J/mol K} \) and \( T = 298 \text{ K} \):\[ \Delta G^0 = -(8.314)(298) \ln(32.96) \approx -8.314 \times 298 \times 3.493 = -8654 \text{ J/mol} \]
07

Final Calculations and Units

Converting \( \Delta G^0 \) to kJ/mol: \[ \Delta G^0 \approx -8.654 \text{ kJ/mol} \]. The equilibrium constant (\( K \)) is 32.96 with units L/mol, and \( \Delta G^0 \) is \(-8.654 \text{ kJ/mol} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hemocyanin
Hemocyanin is a fascinating protein that plays a crucial role in the physiology of certain invertebrates, such as squids and some arthropods. Unlike hemoglobin, which is found in many animals including humans, hemocyanin contains copper atoms. These copper atoms are directly responsible for binding and transporting oxygen throughout the blood of these creatures.
Hemocyanin is a large, complex protein that costs blue when it binds to oxygen. This is due to the presence of the copper ions, which provides an interesting contrast to the red color of oxygenated hemoglobin in mammals.
Keep in mind that oxygen binding occurs when the copper ions in hemocyanin interact with oxygen molecules. This binding is reversible, enabling the efficient uptake and transportation of oxygen. The protein's structure allows it to house multiple oxygen binding sites, making it highly efficient at capturing and delivering oxygen where needed.
Oxygen-Binding
Oxygen-binding is a fundamental process in biological systems, especially concerning proteins like hemocyanin and hemoglobin. In these proteins, specific sites known as binding sites are allocated for oxygen molecules.
When it comes to hemocyanin, the protein can bind with oxygen through its copper centers. The process begins as molecular oxygen enters the binding sites and forms a temporary, reversible bond.
This transient binding is vital because it means oxygen can be released in the tissues where it is needed. The saturation level—here mentioned as 33% in the exercise—refers to how many of those binding sites are currently occupied by oxygen. This is crucial because it hints at how efficiently the protein is functioning in its oxygen transportation role.
Standard Free Energy Change
Standard free energy change, represented as \(\Delta G^0\), is an important thermodynamic parameter. It indicates the spontaneity of a chemical reaction. Basically, it tells us whether a reaction will proceed without any external energy input.
In analyzing the reaction of oxygen binding with hemocyanin, the \(\Delta G^0\) calculation incorporates equilibrium constants and temperature as part of its formulation: \(\Delta G^0 = -RT \ln K\).
Here, \(\Delta G^0\) is calculated to understand how energetically favorable the oxygen-binding process is under standard state conditions. A negative \(\Delta G^0\) value, as shown in our example (-8.654 kJ/mol), points to the reaction being spontaneous and favorable under those conditions.
Partial Pressure
Partial pressure is a concept often employed in the discussion of gases. It relates to the pressure exerted by an individual gas in a mixture of gases. Understanding partial pressure is essential when studying gas reactions with liquid or solid phases.
In our example, the partial pressure of oxygen (\( P_{O_2} = 0.13 \text{ atm} \)) contributes to how much oxygen is available to bind with hemocyanin. This available oxygen concentration can significantly affect how saturated the hemocyanin becomes in vivo.
Partial pressure is a core concept in understanding how gases like oxygen behave when mixed with other gases or under different environmental conditions such as temperature and concentration.
Henry's Law
Henry's Law is an important principle in chemistry that relates the solubility of a gas in a liquid to the partial pressure of that gas above the liquid. Simply put, it tells us how much of a gas will dissolve in a liquid at a given pressure.
  • The principle can be expressed as \([\text{Gas}] = k_H \times P_{\text{Gas}}\), where \(k_H\) is the Henry's Law constant.

In the case of the exercise, Henry’s Law helps us determine the concentration of oxygen in aqueous solution using the given solubility constant and partial pressure.
This law is integral for those studying environmental science and engineering because it bridges the behavior of gases in different phases, ensuring precise calculations in processes such as industrial applications and understanding respiratory physiology in organisms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The free energy status of a cell can be described in various ways. One of these, called the adenylate energy charge (AEC), was first proposed by Daniel Edward Atkinson (1921-). The AEC is defined as $$ \mathrm{AEC}=([\mathrm{ATP}]+0.5[\mathrm{ADP}]) /([\mathrm{ATP}]+[\mathrm{ADP}]+[\mathrm{AMP}]) $$ and it varies between \(1.0\), when all the adenine nucleotide is ATP, and 0 , when all the \(\beta\) - and \(\gamma\)-phosphoanhydride bonds have been hydrolyzed. The relative amounts of ATP, ADP, and AMP can be determined by comparing the sizes of the respective peaks in a high-performance liquid chromatography (HPLC) profile. The AEC of a healthy cell is about \(0.90-0.95\). Malignant hypothermia is an inherited muscle disease in humans and pigs. Patients suffer rapid rises in body temperature, spasms in skeletal muscle, and increases in the rate of metabolism, which can be fatal if not treated with a suitable muscle relaxant. The following data were obtained before the onset of symptoms and just prior to the death of a pig afflicted with the disease. $$ \begin{array}{lccc} \hline & \multicolumn{3}{c}{[\mathrm{ADP}]} \\ & {[\mathrm{ATP}]} & \mu \mathrm{mol} \mathrm{g}^{-1} \text { tissue } & {[\mathrm{AMP}]} \\ \hline \text { Before symptoms } & 4.2 & 0.37 & 0.029 \\ \text { Before death } & 2.1 & 0.66 & 0.19 \\ \hline \end{array} $$ Calculate the \(\mathrm{AEC}\) before the symptoms began to occur and just before death. Comment on the magnitude of the values and what they indicate.

Analysis of gene regulation involves study of structural and thermodynamic aspects of how proteins bind nucleic acid. One area of such research is the recognition of DNA operator sites by repressor molecules. Suppose protein P binds a single specific sequence on a molecule of DNA D. This is a common mechanism for the regulation of gene expression. At equilibrium, \(\mathrm{P}+\mathrm{D}\) \(\Leftrightarrow \mathrm{P} \bullet \mathrm{D} .\) A bacterial cell contains one molecule of DNA. Assume that cell is cylindrical, and that its diameter and length are \(1 \mu \mathrm{m}\) and \(2 \mu \mathrm{m}\), respectively. Calculate the total concentration of \(\mathrm{D}\). Assume that \(K_{\mathrm{eq}}=10^{-10} \mathrm{M}\). Calculate the \([\mathrm{P} \bullet \mathrm{D}]\), assuming that \([\mathrm{P}]=[\mathrm{D}]\). The concentration of bound \(\mathrm{D}\) is just \([\mathrm{P} \bullet \mathrm{D}]\). Calculate the concentration of unbound D. Calculate \([\mathrm{P} \bullet \mathrm{D}] /[\mathrm{P}]\). Give an interpretation of this quantity. The subject of binding will be discussed in detail in Chapter \(7 .\)

Use the following osmotic pressure data for horse hemoglobin in \(0.2 \mathrm{M}\) phosphate and at \(3{ }^{\circ} \mathrm{C}\) to determine the molecular mass of the protein. $$ \begin{array}{lc} \hline \begin{array}{c} \text { Concentration of } \\ \text { hemoglobin }(\mathrm{g} / \mathrm{I} 00 \mathrm{ml}) \end{array} & \text { Osmotic pressure }\left(\mathrm{cm} \mathrm{H}_{2} \mathrm{O}\right) \\ \hline 0.65 & 3.84 \\ 0.81 & 3.82 \\ 1.11 & 3.51 \\ 1.24 & 3.79 \\ 1.65 & 3.46 \\ 1.78 & 3.82 \\ 2.17 & 3.82 \\ 2.54 & 3.40 \\ 2.98 & 3.76 \\ 3.52 & 3.80 \\ 3.90 & 3.74 \\ 4.89 & 4.00 \\ 6.06 & 3.94 \\ 8.01 & 4.27 \\ 8.89 & 4.36 \\ \hline \end{array} $$

"Hot start." When plasmid DNA is used as the template in a PCR reaction, the enzyme buffer, plasmid, and oligonucleotide primers are often incubated at \(95^{\circ} \mathrm{C}\) for several minutes before starting thermal cycling. Why?

Recall what happens to a red blood cell when it's placed in a hypotonic solution. What must be done to ensure that dialysis tubing doesn't burst?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.