Chapter 2: Problem 6
The weak acid HA is \(2 \%\) ionized (dissociated) in a \(0.20 \mathrm{M}\) solution. (a) What is \(K_{\mathrm{a}}\) for this acid? (b) What is the pH of this solution?
Short Answer
Expert verified
(a) \( K_a \approx 8.16 \times 10^{-5} \); (b) pH \( \approx 2.40 \).
Step by step solution
01
Identify Initial Concentrations
The initial concentration of the weak acid HA is given as \( [HA]_0 = 0.20 \text{ M} \). Since it is \( 2\% \) ionized, the concentrations that dissociate are important for calculating \( K_a \).
02
Determine Concentration of Ionized Acid
Calculate the concentration of HA that ionizes: \( [HA]_0 \cdot \frac{2}{100} = 0.20 \cdot 0.02 = 0.004 \text{ M} \). This means, \( [H^+] = [A^-] = 0.004 \text{ M} \) at equilibrium.
03
Calculate Equilibrium Concentrations
The remaining concentration of HA after ionization is \( [HA] = [HA]_0 - [H^+] = 0.20 - 0.004 = 0.196 \text{ M} \).
04
Write the Expression for Ka
The expression for the acid dissociation constant, \( K_a \), is \[ K_a = \frac{[H^+][A^-]}{[HA]} \]. Substitute the equilibrium concentrations into this formula.
05
Calculate Ka
Substitute known values into the equation: \( K_a = \frac{(0.004)(0.004)}{0.196} = \frac{0.000016}{0.196} \approx 8.16 \times 10^{-5} \).
06
Calculate pH of the Solution
pH is calculated using the formula \( pH = -\log [H^+] \). Here, \( [H^+] = 0.004 \text{ M} \).
07
Compute pH Value
Calculate \( pH = -\log(0.004) \approx 2.40 \). The solution has a pH of approximately 2.40.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionization Percentage
Ionization percentage is a key concept in understanding how much of an acid ionizes or dissociates in a solution. When we talk about a 2% ionization for a weak acid like HA, it means that 2% of the acid molecules dissociate into ions in the solution.
The formula to calculate the ionization percentage is:
In understanding ionization, remember that it tells how extensively an acid ionizes, giving insight into the acidity and strength of the acid in a given solution.
The formula to calculate the ionization percentage is:
- Ionization Percentage = \( \left( \frac{[ ext{Dissociated Acid}]}{[ ext{Initial Acid}]} \right) \times 100 \)
- The concentration of ionized HA = \( 0.20 \times \frac{2}{100} = 0.004 \) M
In understanding ionization, remember that it tells how extensively an acid ionizes, giving insight into the acidity and strength of the acid in a given solution.
Acid Dissociation Constant
The acid dissociation constant, symbolized as \( K_a \), is a crucial parameter in evaluating the strength of a weak acid in solution. It reflects the equilibrium position of the acid dissociation reaction.
For an acid HA that ionizes into \( H^+ \) and \( A^- \), the expression for \( K_a \) is:
Understanding \( K_a \) helps chemists and students alike compare acids' strengths. A larger \( K_a \) value indicates a stronger acid, as it means more of the acid ionizes in the solution.
For an acid HA that ionizes into \( H^+ \) and \( A^- \), the expression for \( K_a \) is:
- \( K_a = \frac{[H^+][A^-]}{[HA]} \)
- \([H^+] = [A^-] = 0.004 \text{ M} \)
- \([HA] = 0.196 \text{ M} \)
- \( K_a = \frac{(0.004)(0.004)}{0.196} \approx 8.16 \times 10^{-5} \)
Understanding \( K_a \) helps chemists and students alike compare acids' strengths. A larger \( K_a \) value indicates a stronger acid, as it means more of the acid ionizes in the solution.
pH Calculation
Calculating pH is fundamental in assessing the acidity of solutions. For a weak acid solution, such as our 0.20 M HA, knowing the hydrogen ion concentration is key to determining the pH.
The formula to find pH is:
Remember, the pH scale ranges from 0 to 14:
The formula to find pH is:
- \( pH = -\log [H^+] \)
- \( pH = -\log(0.004) \approx 2.40 \)
Remember, the pH scale ranges from 0 to 14:
- Poorly acidic solutions have a lower pH
- Neutral solutions, like pure water, have a pH of around 7
- Alkaline solutions have a pH higher than 7