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What reagents and conditions would you use to prepare 2 -methylpropanamine by the following reactions: a. Hofmann rearrangement b. Schmidt rearrangement c. Curtius rearrangement d. Gabriel synthesis e. lithium aluminum hydride reaction

Short Answer

Expert verified
Use appropriate starting compounds and reagents for each method: Hofmann (amide, Br₂/NaOH), Schmidt (carboxylic acid, HN₃/H₂SO₄), Curtius (acyl azide), Gabriel (phthalimide, alkyl halide), LiAlH₄ reduction (nitrile).

Step by step solution

01

Understand the Target Molecule

The target molecule is 2-methylpropanamine, which is an amine with the structure CH₃CH(CH₃)CH₂NH₂.
02

Hofmann Rearrangement

In the Hofmann rearrangement, an amide is converted to an amine with the loss of one carbon atom. To prepare 2-methylpropanamine, start with 2-methylbutanamide, use bromine in an alkaline medium, such as NaOH, to facilitate the rearrangement.
03

Schmidt Rearrangement

The Schmidt rearrangement involves the conversion of carboxylic acids to amines. Begin with 2-methylbutanoic acid, react it with hydrazoic acid (HN₃) in the presence of a strong acid such as H₂SO₄, to directly obtain 2-methylpropanamine.
04

Curtius Rearrangement

Curtius rearrangement requires converting an acyl azide to an amine. Convert 2-methylbutanoic acid to the corresponding acyl azide, and then heat the azide to induce rearrangement, forming 2-methylpropanamine.
05

Gabriel Synthesis

Gabriel synthesis is used for primary amines. Use phthalimide and potassium hydroxide (KOH) to form the potassium salt, then react with 2-methyl-1-bromopropane to substitute with the amine group, and finally hydrolyze to get 2-methylpropanamine.
06

Lithium Aluminum Hydride Reduction

Use Lithium Aluminum Hydride (LiAlHâ‚„), a strong reducing agent, to reduce 2-methylpropionitrile (or its equivalent starting compound) in the presence of a suitable solvent like ether, to convert it to 2-methylpropanamine.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hofmann Rearrangement
The Hofmann Rearrangement is a fascinating method for transforming amides into amines with the loss of one carbon atom. It's particularly useful when you have an amide substrate and need to simplify the molecule. For this rearrangement to work, an amide is treated with bromine (Brâ‚‚) in the presence of a strong base such as sodium hydroxide (NaOH).
The reaction mechanism involves the formation of an isocyanate intermediate, which then undergoes hydrolysis to form the desired amine.
This process is handy for chemists looking to make smaller amines by losing a carbon atom. In practice, to make 2-methylpropanamine, one would start with 2-methylbutanamide. The reaction is fairly reliable, offering a straightforward route to primary amines.
Schmidt Rearrangement
The Schmidt Rearrangement is another classic organic transformation. It allows the conversion of carboxylic acids into amines. This is accomplished by treating the carboxylic acid with hydrazoic acid (HN₃) in the presence of a strong acid, like sulfuric acid (H₂SO₄).
This reaction forms a new carbon-nitrogen bond and can occasionally be used to directly produce amines from simple carboxylic acids.
  • First, a protonation of the carboxylic group occurs.
  • Next, the carboxylic acid reacts with hydrazoic acid to form an acylium ion.
  • Finally, nitrogen gas is expelled, rearranging the structure to form an amine.
To generate 2-methylpropanamine, beginning with 2-methylbutanoic acid makes this reaction an effective choice.
Curtius Rearrangement
In the realm of rearrangements, the Curtius Rearrangement stands out for its use of acyl azides. This reaction involves the transformation of acyl azides into isocyanates, which can then be further manipulated or hydrolyzed to produce amines.
The starting point is typically a carboxylic acid that is converted into its acyl azide form. Upon heating, the azide rearranges to an isocyanate intermediate, which can then be converted to a primary amine through hydrolysis.
This process is both elegant and efficient for generating amines from basic carboxylic acids. For those looking to synthesize 2-methylpropanamine, transforming 2-methylbutanoic acid into an acyl azide and inducing the Curtius rearrangement is an effective pathway.
Gabriel Synthesis
The Gabriel Synthesis is a well-known method for creating primary amines, tailored for success with alkyl halides. The process begins with phthalimide, which is reacted with potassium hydroxide (KOH) to generate a potassium phthalimide salt.
This salt acts as a nucleophile, ready to attack an alkyl halide, such as 2-methyl-1-bromopropane. Following this nucleophilic substitution, the resulting product undergoes hydrolysis, liberating the primary amine.
  • Use phthalimide in an alkali environment to begin the reaction.
  • React with the desired alkyl halide for the substitution.
  • Remove the phthaloyl group through hydrolysis to yield the primary amine.
This method is reliable and gives the chemist control over the type of amine produced, making it perfect for synthesizing compounds like 2-methylpropanamine.
Lithium Aluminum Hydride Reduction
Lithium Aluminum Hydride (LiAlHâ‚„) is a robust reducing agent, particularly adept at converting nitriles into primary amines. This reduction reaction involves the LiAlHâ‚„ donating hydrides, which react with the nitrile to produce the corresponding amine.
The reaction typically takes place in an inert solvent such as diethyl ether or tetrahydrofuran (THF), facilitating a smooth conversion of the nitrile to amine. It's critical to ensure the reaction environment remains free of water to prevent premature hydrolysis.
For synthesizing 2-methylpropanamine, one could reduce 2-methylpropionitrile using LiAlHâ‚„. This technique is immensely powerful, as it opens pathways to producing a wide array of amines from basic nitrile starting materials.

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Most popular questions from this chapter

The point of this exercise is to show that reactions of known stereospecificity can be used to establish configuration at chiral centers. A carboxylic acid of \((+)\) optical rotation was converted to an amide by way of the acyl chloride. The amide in turn was converted to a primary amine of one less carbon atom than the starting carboxylic acid. The primary amine was identified as 2\(S\) -aminobutane. What was the structure and configuration of the \((+)\) -carboxylic acid? Indicate the reagents you would need to carry out each step in the overall sequence \(\mathrm{RCO}_{2} \mathrm{H} \rightarrow \mathrm{RCOCl} \rightarrow \mathrm{RCONH}_{2} \rightarrow \mathrm{RNH}_{2}\).

3-Nitrobenzenamine is less than \(1 / 100\) as strong a base as benzenamine, but is 23 times stronger than \(4-\) nitrobenzenamine. Remembering that the inductive effect falls of rapidly with the number of intervening bonds, why should 3nitrobenzenamine be a much weaker base than benzenamine itself, but substantially stronger than 4-nitrobenzenamine?

Write a structural formula (one for each part) that fits the following descriptions. (These descriptions can apply to more than one structural formula.) a. A liquid basic nitrogen compound of formula \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{~N}\) with \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\) and excess \(\mathrm{NaOH}\) solution gives a clear solution. This solution when acidified gives a solid product of formula \(\mathrm{C}_{9} \mathrm{H}_{11} \mathrm{O}_{2} \mathrm{NS}\). b. A liquid diamine of formula \(\mathrm{C}_{5} \mathrm{H}_{14} \mathrm{~N}_{2}\) with \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\) and \(\mathrm{NaOH}\) gives an insoluble solid. This solid dissolves when the mixture is acidified with dilute hydrochloric acid.

a. Explain why 1,3-diazacyclopentadiene (imidazole) is a much stronger acid than azacyclopentadiene (pyrrole). b. Would you expect benzenamine to be a stronger or weaker acid than cyclohexanamine? Give your reasoning.

Show how the following compounds may be prepared from ammonia and the given starting materials: a. 1,2 -ethanediamine from ethene b. 2 -aminoethanol from ethene c. benzenamine from chlorobenzene

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