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Writc the cmpirical formula for cach of the following substances: a. \(\mathrm{H}_{2} \mathrm{O}_{2}\), peroxide b. \(\mathrm{C}_{18} \mathrm{H}_{12}\), chrysene, used in the manufacture of dyes c. \(\mathrm{C}_{10} \mathrm{H}_{16} \mathrm{O}_{2}\), chrysanthemic acid, in pyrethrum flowers d. \(\mathrm{C}_{9} \mathrm{H}_{18} \mathrm{~N}_{6}\), altretamine, an anticancer medication e. \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~N}_{2} \mathrm{O}_{2}\), oxamide, a fertilizer

Short Answer

Expert verified
a. HO, b. C鈧僅鈧, c. C鈧匟鈧圤, d. C鈧僅鈧哊鈧, e. CH鈧侼O.

Step by step solution

01

Identify the Ratio of Elements in Each Compound

To find the empirical formula for each compound, start by identifying the number of atoms of each element present in the given molecular formulas.
02

Simplify the Ratios for Each Compound

Divide the number of atoms of each element by the greatest common divisor (GCD) to simplify the ratios. The empirical formula is the simplest whole-number ratio of atoms.
03

Empirical Formula for H鈧侽鈧

Hydrogen peroxide (H鈧侽鈧): - Number of hydrogen atoms: 2- Number of oxygen atoms: 2Ratio: 2:2. Simplify the ratio to 1:1. The empirical formula is HO.
04

Empirical Formula for C鈧佲倛H鈧佲倐

Chrysene (C鈧佲倛H鈧佲倐): - Number of carbon atoms: 18- Number of hydrogen atoms: 12Ratio: 18:12. Simplify the ratio to 3:2. The empirical formula is C鈧僅鈧.
05

Empirical Formula for C鈧佲個H鈧佲倖O鈧

Chrysanthemic acid (C鈧佲個H鈧佲倖O鈧): - Number of carbon atoms: 10- Number of hydrogen atoms: 16- Number of oxygen atoms: 2Ratio: 10:16:2. Simplify the ratio to 5:8:1. The empirical formula is C鈧匟鈧圤.
06

Empirical Formula for C鈧塇鈧佲倛N鈧

Altretamine (C鈧塇鈧佲倛N鈧): - Number of carbon atoms: 9- Number of hydrogen atoms: 18- Number of nitrogen atoms: 6Ratio: 9:18:6. Simplify the ratio to 3:6:2. The empirical formula is C鈧僅鈧哊鈧.
07

Empirical Formula for C鈧侶鈧凬鈧侽鈧

Oxamide (C鈧侶鈧凬鈧侽鈧): - Number of carbon atoms: 2- Number of hydrogen atoms: 4- Number of nitrogen atoms: 2- Number of oxygen atoms: 2Ratio: 2:4:2:2. Simplify the ratio to 1:2:1:1. The empirical formula is CH鈧侼O.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ratio of Elements
Understanding the ratio of elements in a compound is crucial for determining its empirical formula. The empirical formula represents the simplest whole-number ratio of elements in a compound. To start, you need to identify the number of each type of atom in a given molecule. For example, hydrogen peroxide (H鈧侽鈧) has 2 hydrogen atoms and 2 oxygen atoms.
In chrysene (C鈧佲倛H鈧佲倐), there are 18 carbon atoms and 12 hydrogen atoms. Similarly, chrysanthemic acid (C鈧佲個H鈧佲倖O鈧) contains 10 carbon atoms, 16 hydrogen atoms, and 2 oxygen atoms. Once you identify these numbers, you can move forward to finding their simplest ratio.
Simplifying Ratios
Next comes simplifying the ratios, which involves dividing the number of each type of atom by their greatest common divisor (GCD). This process reduces the numbers to their simplest whole-number form. For instance, in hydrogen peroxide (H鈧侽鈧), the ratio of hydrogen to oxygen is 2:2. Dividing both numbers by 2 simplifies this ratio to 1:1, resulting in the empirical formula HO.
For chrysene (C鈧佲倛H鈧佲倐), the GCD of 18 and 12 is 6. Dividing both by 6 gives a simplified ratio of 3:2, so the empirical formula is C鈧僅鈧. In the case of chrysanthemic acid (C鈧佲個H鈧佲倖O鈧), the ratio of elements is 10:16:2. The GCD here is 2, so we divide each number by 2 to get a simplified ratio of 5:8:1, resulting in the empirical formula C鈧匟鈧圤.
Molecular Formulas
A molecular formula shows the exact number of atoms of each element in a molecule, but it doesn't always represent the simplest form. The empirical formula, on the other hand, is always the simplest whole-number ratio of atoms in a compound. For instance, hydrogen peroxide's molecular formula is H鈧侽鈧, but its empirical formula is HO.
However, it鈥檚 important to note that a molecular formula can sometimes be the same as its empirical formula. For example, in water (H鈧侽), both the molecular and empirical formulas are the same. The molecular formula provides more detailed information about the compound鈥檚 actual structure and composition, which can be invaluable in certain contexts like chemical reactions and stoichiometry.
Understanding these distinctions and how to derive each formula helps you gain deeper insights into chemical compositions and their properties.

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