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Write the formula for each of the following ionic compounds: a. cobalt(III) chloride b. lead(IV) oxide c. silver iodide d. calcium nitride e. copper(I) phosphide f. chromium(II) chloride

Short Answer

Expert verified
a. CoCl\textsubscript{3}, b. PbO\textsubscript{2}, c. AgI, d. Ca\textsubscript{3}N\textsubscript{2}, e. Cu\textsubscript{3}P, f. CrCl\textsubscript{2}.

Step by step solution

01

Identifying the ions

Identify the ions involved in each compound. Note the charge of each ion as indicated by the Roman numeral or by common charge conventions.
02

Balancing charges

Combine the ions in ratios that balance the total positive and negative charges to form neutral compounds.
03

Writing the formulas

Combine the symbols of the ions, writing the cation (positive ion) first followed by the anion (negative ion), and indicate the number of each ion using subscripts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cation and Anion Identification
Understanding how to identify cations and anions is crucial in writing ionic compound formulas. In ionic compounds, cations are positively charged ions, and anions are negatively charged ions.
Cations are usually metallic elements or positive polyatomic ions, while anions are typically non-metallic elements or negative polyatomic ions.
When given the name of an ionic compound, you'll need to break it down into its constituent ions. The Roman numerals next to transition metals indicate their charge. For example, in cobalt(III) chloride, cobalt is the cation with a +3 charge. Similarly, non-transition metals and anions usually have standard charges; chloride (Cl), for instance, always carries a -1 charge.
  • **Cobalt(III) chloride**: Cobalt is Co鲁鈦, Chloride is Cl鈦.
  • **Lead(IV) oxide**: Lead is Pb鈦粹伜, Oxide is O虏鈦.
  • **Silver iodide**: Silver is Ag鈦, Iodide is I鈦.
  • **Calcium nitride**: Calcium is Ca虏鈦, Nitride is N鲁鈦.
  • **Copper(I) phosphide**: Copper is Cu鈦, Phosphide is P鲁鈦.
  • **Chromium(II) chloride**: Chromium is Cr虏鈦, Chloride is Cl鈦.
Balancing Ionic Charges
After identifying the cations and anions, the next step is to balance their charges to make a neutral compound. This is done by adjusting the ratio of ions so that the total positive charge equals the total negative charge.
For example, to balance cobalt(III) chloride, we know cobalt carries a 3+ charge, and chloride carries a 1- charge. We need three chloride ions to balance the charge of one cobalt ion (3 x -1 = -3, which balances +3).
  • **Cobalt(III) chloride**: Co鲁鈦 and 3 Cl鈦 combine to form CoCl鈧.
  • **Lead(IV) oxide**: Pb鈦粹伜 and 2 O虏鈦 combine to form PbO鈧.
  • **Silver iodide**: Ag鈦 and I鈦 already balance, forming AgI.
  • **Calcium nitride**: 3 Ca虏鈦 and 2 N鲁鈦 combine to form Ca鈧僋鈧.
  • **Copper(I) phosphide**: 3 Cu鈦 and 1 P鲁鈦 combine to form Cu鈧働.
  • **Chromium(II) chloride**: Cr虏鈦 and 2 Cl鈦 combine to form CrCl鈧.
Chemical Formulas
Once you have your ions and their balanced ratios, you're ready to write the chemical formulas.
In writing formulas, the cation (the positive ion) is always written first, followed by the anion (the negative ion). Subscripts are used to indicate the number of each type of ion in the compound.
Let's translate our previous balances into chemical formulas:
  • **Cobalt(III) chloride**: The formula is CoCl鈧, as we have 1 cobalt ion and 3 chloride ions.
  • **Lead(IV) oxide**: Here, PbO鈧 is the formula, with 1 lead ion and 2 oxide ions.
  • **Silver iodide**: AgI is straightforward with 1 silver ion and 1 iodide ion.
  • **Calcium nitride**: Ca鈧僋鈧 reflects 3 calcium ions and 2 nitride ions.
  • **Copper(I) phosphide**: Cu鈧働 shows 3 copper ions and 1 phosphide ion.
  • **Chromium(II) chloride**: CrCl鈧 indicates 1 chromium ion and 2 chloride ions.
Remember to always double-check if all charges are balanced and if the ions are written in the correct order for creating accurate chemical formulas.

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