/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Why would the pH of your blood p... [FREE SOLUTION] | 91影视

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Why would the pH of your blood plasma increase if you breathe fast?

Short Answer

Expert verified
Faster breathing reduces CO鈧 levels in blood, decreasing H鈦 ions, hence increasing pH (respiratory alkalosis).

Step by step solution

01

- Understand the role of CO鈧

When you breathe, you take in oxygen (O鈧) and expel carbon dioxide (CO鈧). CO鈧 dissolved in the blood forms carbonic acid (H鈧侰O鈧), which dissociates into hydrogen ions (H鈦) and bicarbonate ions (HCO鈧冣伝). The hydrogen ions contribute to the acidity of your blood.
02

- The relationship between CO鈧 and pH

The concentration of CO鈧 in your blood is directly related to the pH level. Higher CO鈧 levels result in more H鈦 ions, making the blood more acidic (lower pH). Conversely, lower CO鈧 levels result in fewer H鈦 ions, making the blood less acidic (higher pH).
03

- Effect of faster breathing (hyperventilation)

When you breathe fast, you expel CO鈧 from your lungs rapidly. This reduces the partial pressure of CO鈧 in your blood, leading to a decrease in H鈦 ion concentration. Consequently, the pH of your blood increases, resulting in a condition called respiratory alkalosis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

carbon dioxide and blood pH
The concentration of carbon dioxide (CO鈧) in your blood is a key factor in determining its pH level. CO鈧 is a byproduct of cellular respiration, the process by which cells produce energy. When you breathe, you take in oxygen (O鈧) and expel CO鈧. This balance is crucial for maintaining the pH of your blood within a narrow and healthy range.
If CO鈧 levels are high, it reacts with water in your blood to form carbonic acid (H鈧侰O鈧). Carbonic acid then dissociates into hydrogen ions (H鈦) and bicarbonate ions (HCO鈧冣伝). The hydrogen ions contribute to the acidity of your blood, lowering its pH. Conversely, when CO鈧 levels are low, fewer hydrogen ions are produced, leading to a less acidic (higher pH) environment in your blood.
This delicate balance ensures that your blood pH stays within the normal range of about 7.35 to 7.45.
carbonic acid formation in blood
Carbonic acid (H鈧侰O鈧) plays a crucial role in the regulation of blood pH. When CO鈧 dissolves in the blood, it reacts with water (H鈧侽) to form carbonic acid. This reaction is catalyzed by an enzyme called carbonic anhydrase. The chemical equation for this process is:
\( CO鈧 + H鈧侽 \rightarrow H鈧侰O鈧 \)
Once formed, carbonic acid can easily dissociate into hydrogen ions (H鈦) and bicarbonate ions (HCO鈧冣伝):
\( H鈧侰O鈧 \rightarrow H鈦 + HCO鈧冣伝 \)
The hydrogen ions increase the acidity of the blood, while the bicarbonate ions serve as a buffer to maintain pH stability. This system allows the body to quickly respond to changes in CO鈧 levels and maintain a stable blood pH.
For instance, if there's an increase in CO鈧 due to slower breathing, more carbonic acid is formed, leading to a higher concentration of hydrogen ions and a lower pH (more acidic blood). Conversely, if CO鈧 levels drop due to rapid breathing, less carbonic acid is formed, resulting in fewer hydrogen ions and a higher pH (less acidic blood).
respiratory alkalosis
Respiratory alkalosis is a condition characterized by an increase in blood pH due to excessive loss of carbon dioxide through rapid breathing, also known as hyperventilation. When you hyperventilate, CO鈧 is expelled from your lungs more quickly than it is produced by your cells. This rapid loss of CO鈧 leads to a decrease in the partial pressure of CO鈧 in your blood, causing a subsequent reduction in hydrogen ion concentration.
As we learned earlier, fewer hydrogen ions mean that the blood becomes less acidic, thus increasing its pH. This increased pH can lead to various symptoms such as dizziness, light-headedness, tingling in the extremities, and even fainting. The body's response to this condition includes slowing down breathing to retain CO鈧 and stabilize pH levels.
Respiratory alkalosis can be temporary and often occurs as a result of anxiety, panic attacks, or strenuous exercise. In some cases, it can be more serious, associated with medical conditions like lung diseases or fever. If persistent, medical intervention may be necessary to address the underlying causes and restore normal breathing patterns and blood pH levels.

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Most popular questions from this chapter

Calculate the \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) for a solution with each of the following \(\mathrm{pH}\) values: \((14.6)\) a. \(2.2\) b. \(7.2\) c. \(10.6\) d. \(12.1\)

State whether each of the following is acidic, basic, or neutral: \((14.5)\) a. lime juice, \(\mathrm{pH} 2.2\) b. potato, \(\mathrm{pH} 5.8\) c. pure water, \(\mathrm{pH} 7.0\) d. bleach, \(\mathrm{pH} 12.0\)

Balance each of the following neutralization reactions: a. \(\mathrm{HCl}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(s) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{MgCl}_{2}(a q)\) b. \(\mathrm{H}_{3} \mathrm{PO}_{4}(a q)+\mathrm{LiOH}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Li}_{3} \mathrm{PO}_{4}(a q)\)

$$ \begin{aligned} &\text { Complete the following table: (14.2) } \\ &\begin{array}{ll} \text { Acid } & \text { Conjugate Base } \\ \text { HI } & \\ & \mathrm{Cl}^{-} \\ \mathrm{NH}_{4}^{+} & \\ & \mathrm{HS}^{-} \end{array} \end{aligned} $$

Identify the Br酶nsted-Lowry acid-base pairs in each of the following equations: a. \(\mathrm{H}_{2} \mathrm{CO}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftarrows \mathrm{HCO}_{3}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q)\) b. \(\mathrm{NH}_{4}^{+}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftarrows \mathrm{NH}_{3}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q)\) c. \(\mathrm{HCN}(a q)+\mathrm{NO}_{2}^{-}(a q) \rightleftarrows \mathrm{CN}^{-}(a q)+\mathrm{HNO}_{2}(a q)\) d. \(\mathrm{CHO}_{2}^{-}(a q)+\mathrm{HF}(a q) \rightleftarrows \mathrm{HCHO}_{2}(a q)+\mathrm{F}^{-}(a q)\)

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