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When Zn reacts with HCl solution, the products are \(\mathrm{H}_{2}\) gas and \(\mathrm{ZnCl}_{2}\). A volume of \(425 \mathrm{~mL}\) of \(\mathrm{H}_{2}\) gas is collected over water at a total pressure of \(758 \mathrm{mmHg}\) and \(16^{\circ} \mathrm{C}\). The vapor pressure of water at \(16{ }^{\circ} \mathrm{C}\) is \(14 \mathrm{mmHg}\). $$ \mathrm{Zn}(s)+\mathrm{HCl}(a q) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{ZnCl}_{2}(a q) $$ a. What was the partial pressure of the \(\mathrm{H}_{2}\) gas? b. How many moles of \(\mathrm{H}_{2}\) gas were produced in the reaction?

Short Answer

Expert verified
a. 744 mmHg; b. 0.0175 moles

Step by step solution

01

Calculate the partial pressure of \(\text{H}_{2}\) gas

First, find the partial pressure of \(\text{H}_{2}\) gas by subtracting the vapor pressure of water from the total pressure. Use the formula: \[ P_{\text{H}_{2}} = P_{\text{total}} - P_{\text{H}_{2}\text{O}} \]Substitute the given values into the equation: \[ P_{\text{H}_{2}} = 758 \text{ mmHg} - 14 \text{ mmHg} = 744 \text{ mmHg} \]Thus, the partial pressure of \(\text{H}_{2}\) gas is 744 mmHg.
02

Convert the volume to liters

Convert the volume of \(\text{H}_{2}\) gas from mL to L. Use the conversion factor: \[ 1 \text{ mL} = 0.001 \text{ L} \]So, \[ 425 \text{ mL} = 425 \times 0.001 \text{ L} = 0.425 \text{ L} \]
03

Use the Ideal Gas Law to find moles of \(\text{H}_{2}\) gas

Recall the Ideal Gas Law equation: \[ PV = nRT \]Solve for \( n \): \[ n = \frac{PV}{RT} \]Make sure to use consistent units: \(\text{Pressure in atm, Volume in L, R = 0.0821 L·atm/(K·mol), and Temperature in K}\). Convert the pressure from mmHg to atm: \[ P = 744 \text{ mmHg} \times \frac{1 \text{ atm}}{760 \text{ mmHg}} = 0.9789 \text{ atm} \]Convert the temperature from Celsius to Kelvin: \[ T = 16^{\circ} \text{C} + 273.15 = 289.15 \text{ K} \]Substitute in the values: \[ n = \frac{(0.9789 \text{ atm})(0.425 \text{ L})}{(0.0821 \text{ L·atm/(K·mol)})(289.15 \text{ K})} \]Calculate: \[ n = \frac{0.4165 \text{ atm·L}}{23.7471 \text{ L·atm/(K·mol)}} = 0.0175 \text{ moles} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
To understand partial pressure, think of each gas in a mixture as contributing to the total pressure. The partial pressure of a gas is the pressure it would exert if it were the only gas present in the container. In our exercise, we need to find the partial pressure of hydrogen gas \(H_2\) collected over water. The total pressure measured is the sum of the pressures exerted by \(H_2\) and the water vapor. Using the formula: \[ P_{H_2} = P_{total} - P_{H_2O} \] we subtract the vapor pressure of water (\(14 \) mmHg) from the total pressure (\(758 \) mmHg), resulting in a partial pressure of \(744 \) mmHg.
Moles Calculation
In chemistry, calculating the number of moles of a substance produced in a reaction is essential. Moles help us quantify amounts in a chemical reaction. The Ideal Gas Law, represented as \[ PV = nRT \] can be rearranged to solve for the number of moles, \(n\): \[ n = \frac{PV}{RT} \] Here, \(P\) is pressure, \(V\) is volume, \(R\) is the gas constant (0.0821 L·atm/(K·mol)), and \(T\) is temperature in Kelvin. After converting pressure from mmHg to atm, volume to liters, and temperature to Kelvin, substitute these values into the equation: \[ n = \frac{(0.9789\text{ atm})(0.425\text{ L})}{(0.0821\text{ L·atm/(K·mol)})(289.15\text{ K})} = 0.0175 \text{ moles} \] This gives us the amount of hydrogen gas produced.
Gas Conversions
Gas conversions are crucial for using the Ideal Gas Law accurately. Pressure is often measured in mmHg or atm, volume in liters or milliliters, and temperature in Celsius or Kelvin. Consistent units are vital. For pressure conversion: \[ 1 \text{ atm} = 760 \text{ mmHg} \] So, to convert \(744 \text{ mmHg}\) to atm: \[ 744 \text{ mmHg} \times \frac{1 \text{ atm}}{760 \text{ mmHg}} = 0.9789 \text{ atm} \] Volume conversion from mL to L uses: \[ 1 \text{ mL} = 0.001 \text{ L} \] For temperature conversion to Kelvin: \[ T(K) = T(^{\text{C}}) + 273.15 \] Convert \(16^{\text{C}}\) to Kelvin: \[ 16^{\text{C}} + 273.15 = 289.15 \text{ K} \] Applying these conversions ensures the correct use of the Ideal Gas Law.
Chemical Reactions
Chemical reactions describe the process where reactants convert to products. In our example: \[ \text{Zn}(s) + \text{HCl}(aq) \rightarrow \text{H}_2(g) + \text{ZnCl}_2(aq) \] Zinc (\text{Zn}) reacts with hydrochloric acid (\text{HCl}) to produce hydrogen gas (\text{H}_2) and zinc chloride (\text{ZnCl}_2). Balancing chemical equations ensures that the number of atoms for each element is equal on both sides of the reaction. This balanced equation also helps in stoichiometric calculations, determining the amount of each reactant used and each product formed. Stoichiometry and gas laws help predict and measure the outcomes of chemical reactions reliably. Always ensure equations are balanced before proceeding with calculations.

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