Chapter 16: Problem 38
A compound on treatment with NaOH followed by addition of \(\mathrm{AgNO}_{3}\) produces white precipitate at room temperature, the precipitate is soluble in \(\mathrm{NH}_{4} \mathrm{OH}\). The compound is identified as: [AFMC 1997] (a) vinyl chloride (b) benzyl chloride (c) chlorobenzene (d) ethyl bromide
Short Answer
Step by step solution
Recall the reagent behavior
Consider the solubility in NH鈧凮H
Identify the possible halide
Analyze compound reactivity and structure
Determine the final compound
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nucleophilic Substitution
There are two primary types of nucleophilic substitution reactions in organic chemistry:
- SN1 reactions: The `S` stands for substitution, `N` for nucleophilic, and `1` indicates a unimolecular reaction. This means the rate of reaction depends solely on the concentration of the substrate. In SN1 reactions, a carbocation intermediate is formed and then attacked by the nucleophile.
- SN2 reactions: Similar to SN1, but bimolecular. Here, the nucleophile attacks the substrate simultaneously as the leaving group departs, resulting in a one-step, concerted process.
Halide Identification
Silver nitrate (AgNO鈧) is used in this identification due to its reaction with halide ions. When AgNO鈧 is added to a solution containing Cl鈦, it forms silver chloride (AgCl), which shows up as a white precipitate. Similarly, silver bromide (AgBr) forms a pale yellow precipitate. However, a clue lies in the behavior of these silver halides in ammonium hydroxide (NH鈧凮H):
- Silver chloride (AgCl): Soluble in excess NH鈧凮H, which dissolves the precipitate.
- Silver bromide (AgBr): Not soluble in excess NH鈧凮H.
Reaction Mechanism Analysis
In the given scenario, detailed step-by-step analysis led us to identify that benzyl chloride was the responsive compound in question. Let's break down the approach:
- Structural analysis: Observing the given compounds, chlorobenzene is known for its strong C-Cl bond due to resonance stabilization and does not react under conditions similar to NaOH and AgNO鈧 treatment.
- Reactivity comparison: Vinyl chloride has stability in its vinyl cation, thus less likely to precipitate with Ag鈦. However, benzyl chloride forms a reactive benzyl cation when treated with NaOH, liberating Cl鈦 ions readily.
- Solubility tests: The resulting silver chloride from benzyl chloride's NaOH and AgNO鈧 treatment aligns with the white precipitate description that dissolves in NH鈧凮H.