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Calculate the absolute uncertainty in the answers of the following: (a) \((2.78 \pm 0.04)(0.00506 \pm\) 0.00006 ), (b) \((36.2 \pm 0.4) /(27.1 \pm 0.6)\), (c) \((50.23 \pm 0.07)(27.86 \pm 0.05) /(0.1167 \pm 0.0003)\).

Short Answer

Expert verified
(a) \(0.0141 \pm 0.00037\), (b) \(1.335 \pm 0.0442\), (c) \(11987.9 \pm 69.09\)."

Step by step solution

01

Understand the Formula for Uncertainty

When multiplying or dividing quantities, the relative uncertainties are added. If you have a measurement \( x \pm \, ext{Δ}x \) and \( y \pm \, ext{Δ}y \), the relative uncertainty \( \frac{\text{Δ}z}{z} = \frac{\text{Δ}x}{x} + \frac{\text{Δ}y}{y} \) for the product \( z = xy \). For division, the formula is the same, using \( z = \frac{x}{y} \).
02

Calculate Uncertainty for (a)

Given \( (2.78 \pm 0.04)(0.00506 \pm 0.00006) \):1. Calculate relative uncertainties: - For 2.78: \( \frac{0.04}{2.78} \approx 0.0144 \). - For 0.00506: \( \frac{0.00006}{0.00506} \approx 0.0119 \).2. Add the relative uncertainties: - \( 0.0144 + 0.0119 = 0.0263 \).3. Find the product and apply the relative uncertainty: - Product: \( 2.78 \times 0.00506 \approx 0.0141 \). - Absolute uncertainty: \( 0.0141 \times 0.0263 \approx 0.00037 \).Thus, the value is \( 0.0141 \pm 0.00037 \).
03

Calculate Uncertainty for (b)

Given \( \frac{36.2 \pm 0.4}{27.1 \pm 0.6} \):1. Calculate relative uncertainties: - For 36.2: \( \frac{0.4}{36.2} \approx 0.0110 \). - For 27.1: \( \frac{0.6}{27.1} \approx 0.0221 \).2. Add the relative uncertainties: - \( 0.0110 + 0.0221 = 0.0331 \).3. Find the division and apply the relative uncertainty: - Result: \( \frac{36.2}{27.1} \approx 1.335 \). - Absolute uncertainty: \( 1.335 \times 0.0331 \approx 0.0442 \).Thus, the value is \( 1.335 \pm 0.0442 \).
04

Calculate Uncertainty for (c)

Given \( \frac{(50.23 \pm 0.07)(27.86 \pm 0.05)}{0.1167 \pm 0.0003} \):1. Calculate relative uncertainties: - For 50.23: \( \frac{0.07}{50.23} \approx 0.00139 \). - For 27.86: \( \frac{0.05}{27.86} \approx 0.00180 \). - For 0.1167: \( \frac{0.0003}{0.1167} \approx 0.00257 \).2. Add relative uncertainties for products and division: - \( 0.00139 + 0.00180 + 0.00257 \approx 0.00576 \).3. Calculate the compound operation: - Result: \( \frac{50.23 \times 27.86}{0.1167} \approx 11987.9 \). - Absolute uncertainty: \( 11987.9 \times 0.00576 \approx 69.09 \).Thus, the value is \( 11987.9 \pm 69.09 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Uncertainty
Relative uncertainty is a key concept when calculating how precise or uncertain a measurement is in comparison to the actual measurement itself. It is expressed as a fraction or percentage, representing the uncertainty of a measurement divided by the measurement's actual value. This measure helps to understand the precision of an instrument or procedure.
To compute relative uncertainty, use the formula: \[ \text{Relative Uncertainty} = \frac{\Delta x}{x} \] where \( x \) is the measured value and \( \Delta x \) is the absolute uncertainty.
  • For example, if you measure something to be 36.2 ± 0.4, the relative uncertainty is \( \frac{0.4}{36.2} \approx 0.011 \).
  • It indicates that the uncertainty is approximately 1.1% of the measurement.
This concept is practical because multiplying relative uncertainties simplifies the process of dealing with products or quotients of several measurements. It's particularly useful in complex calculations like those shown in problems involving multiple operations.
Absolute Uncertainty
Absolute uncertainty quantifies the margin of error in a measurement. It is different from relative uncertainty, as it is expressed in the same units as the measurement itself, providing a specific range within which the true value is expected to lie.
Absolute uncertainty is often denoted alongside measurements as \( x \pm \Delta x \), where \( x \) is the measurement and \( \Delta x \) represents the uncertainty.
When you have the relative uncertainty, converting it back to absolute uncertainty helps in directly associating the error with the original measurement or result.
  • For instance, if you calculate a value to be 0.0141 with a relative uncertainty of 0.0263, then the absolute uncertainty is \( 0.0141 \times 0.0263 = 0.00037 \).
  • This tells you that the true quantity may be as low as \( 0.0141 - 0.00037 \) or as high as \( 0.0141 + 0.00037 \).
Recognizing the absolute uncertainty is crucial when presenting final results to indicate their precision.
Multiplication and Division of Uncertainties
When dealing with multiplication or division of values that have uncertainties, one does not simply multiply or divide the absolute uncertainties. Instead, the relative uncertainties are used, as the process involves percentage-based calculations.
For multiplication or division of variables \( x \pm \Delta x \) and \( y \pm \Delta y \), the relative uncertainty of the result \( z = xy \) or \( z = \frac{x}{y} \) can be calculated using:
\[ \frac{\Delta z}{z} = \frac{\Delta x}{x} + \frac{\Delta y}{y} \]
  • This formula shows how the errors spread through multiplications and divisions.
  • Once the relative uncertainty is known, it can be converted to absolute uncertainty by multiplying by the resultant value. For example, combining two measurements, \( 50.23 \pm 0.07 \) and \( 27.86 \pm 0.05 \), through multiplication and division, yields a relative uncertainty of 0.00576.
  • The final step is to multiply this relative uncertainty with the result obtained from multiplying or dividing the quantities, such as \( \frac{(50.23 \times 27.86)}{0.1167} \approx 11987.9 \).
  • Thus, finding \( 11987.9 \times 0.00576 = 69.09 \) as the absolute uncertainty, indicating the range of possible error in the calculated result.
Understanding these procedures helps ensure the integrity and reliability of scientific measurements and computations.

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Most popular questions from this chapter

A standard serum sample containing 102 meq/L chloride was analyzed by coulometric titration with silver ion. Duplicate results of 101 and 98 meq/L were obtained. Calculate (a) the mean value, (b) the absolute error of the mean, and (c) the relative error in percent.

The following is a list of common errors encountered in research laboratories. Categorize each as a determinate or an indeterminate error, and further categorize determinate errors as instrumental, operative, or methodological: (a) An unknown being weighed is hygroscopic. (b) One component of a mixture being determined quantitatively by gas chromatography reacts with the column packing. (c) A radioactive sample being counted repeatedly without any change in conditions yields a slightly different count at each trial. (d) The tip of the pipet used in the analysis is broken.

Explain situations when a least-squares linear fit is not appropriate and should not be used. There are at least two common important cases.

A repeated analysis of \(\mathrm{Cl}\) in a given compound resulted in the following results for \(\% \mathrm{Cl}: 2.98\) \(3.16,3.02,2.99,\) and \(3.07 .\) (a) Can any of these results be rejected for statistical reasons at the \(90 \%\) confidence level? (b) If the true value was \(3.03 \%,\) can you be \(95 \%\) confident that your results agree with the known value?

You have developed a new method to measure cholesterol levels in blood that would be cheap, quick and patients could do tests at home (much like glucose tests for diabetics). You need to validate your method, so that you can patent it! Use the information given below and the various statistical methods of data validation you have learned to evaluate the effectiveness of your new testing method. (a) NIST makes a cholesterol in human serum standard that is \(182.1_{5} \mathrm{mg} / \mathrm{dL}\). Your method reports values of 181.83,182.12,182.32 and 182.20 when taking 4 replicate measurements of this standard. Is your value the same? (b) To be comprehensive you tested the same sample (not the NIST standard) numerous times using your method and the "accepted" method for measuring cholesterol. (c) You do not want to give critics an opportunity; there are many at the FDA. You compared the results you get to the accepted method when measuring many different samples. Using the data obtained below, compare your method of analysis to the accepted method for measuring cholesterol. Do your results agree with the accepted method? $$ \begin{array}{ccc} \text { Sample # } & \text { Your Method (mg/dL) } & \text { Accepted Method (mg/dL) } \\ 1 & 174.60 & 174.93 \\ 2 & 142.32 & 142.81 \\ 3 & 210.67 & 209.06 \\ 4 & 188.32 & 187.92 \\ 5 & 112.41 & 112.37 \end{array} $$

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