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Most spectrophotometers can display either absorbance or in percent transmittance. What would be the absorbance reading at \(20 \% T ?\) At \(80 \% T ?\) What would the transmittance reading be at 0.25 absorbance? At 1.00 absorbance?

Short Answer

Expert verified
The absorbance at 20% T is 0.699, and at 80% T is 0.097. Transmittance at 0.25 absorbance is 56.2%, and at 1.00 absorbance is 10%.

Step by step solution

01

Understand the relationship

The relationship between absorbance (A) and transmittance (T) is given by the formula: \[ A = -\log_{10}(T) \]Transmittance is expressed as a fraction of 1, so a percentage must be converted by dividing by 100.
02

Convert the 20% Transmittance to Absorbance

For a transmittance of 20%, convert to a fraction:\[ T = \frac{20}{100} = 0.20 \]Then, apply the formula:\[ A = -\log_{10}(0.20) \]Calculate:\[ A \approx 0.699 \]
03

Convert the 80% Transmittance to Absorbance

For a transmittance of 80%, convert to a fraction:\[ T = \frac{80}{100} = 0.80 \]Then, apply the formula:\[ A = -\log_{10}(0.80) \]Calculate:\[ A \approx 0.097 \]
04

Convert the 0.25 Absorbance to Transmittance

Given an absorbance of 0.25, use the inverse of the formula:\[ T = 10^{-A} \]Substitute the absorbance value:\[ T = 10^{-0.25} \]Calculate:\[ T \approx 0.562 \]Converting to percentage:\[ 56.2\% \]
05

Convert the 1.00 Absorbance to Transmittance

Given an absorbance of 1.00, use the inverse of the formula:\[ T = 10^{-A} \]Substitute the absorbance value:\[ T = 10^{-1.00} \]Calculate:\[ T = 0.1 \]Converting to percentage:\[ 10\% \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spectrophotometry
Spectrophotometry is a technique used to measure how much a chemical substance absorbs light by measuring the intensity of light as a beam of light passes through the sample solution. The basic principle is that each compound absorbs or transmits light over a certain range of wavelength.

In spectrophotometry, the key variables are absorbance and transmittance. Absorbance (A) is a measure of the amount of light absorbed by a sample. It is directly influenced by the concentration of the absorbing species in the sample. Transmittance (T) represents how much light passes through the sample, expressed as a fraction or a percentage of the initial light that entered the sample.

A spectrophotometer is the instrument used, and it typically allows the user to switch between measuring either absorbance or transmittance. Understanding how to calculate and convert between these two measurements is crucial in chemical analysis and various scientific fields.
Logarithmic Calculations
Logarithmic calculations are essential in understanding the relationship between absorbance and transmittance. The formula used to express this relationship is: \[ A = -\log_{10}(T) \]This formula means that absorbance is the negative logarithm (base 10) of transmittance. The logarithmic scale condenses a large range of values into a smaller and more manageable set of numbers.

For calculations, transmittance as a percentage should first be converted into a decimal by dividing by 100. For example, a transmittance of 20% becomes 0.20. Using the formula, the absorbance can be calculated: \[ A = -\log_{10}(0.20) \approx 0.699 \]

Similarly, if absorbance is known, transmittance can be calculated by rearranging the formula: \[ T = 10^{-A} \]Here, an absorbance of 0.25 results in: \[ T = 10^{-0.25} \approx 0.562 \]Converting this fraction to a percentage gives approximately 56.2%.

Logarithmic calculations are crucial in chemistry, allowing for easy manipulation of exponential relationships.
Chemical Analysis
Chemical analysis often relies on spectrophotometry because it provides a simple and precise way to measure the concentration of a substance in a solution. The absorbance of a sample is usually directly proportional to the concentration of its absorbing components, as stated in Beer-Lambert Law. This makes spectrophotometry a vital tool in both quantitative and qualitative analysis.

With the known relationship between absorbance and concentration, chemists can determine the concentration of unknown samples by comparing them to known standards. When you measure the absorbance of a solution at a specific wavelength, you can ascertain the concentration of the solute. The higher the absorbance, the higher the concentration.

In chemical analysis, using a spectrophotometer can reveal critical information about the molecular structure and composition of compounds, helping in various sectors like pharmaceuticals, bioengineering, environmental monitoring, and more. Understanding absorbance and transmittance is fundamental to effectively utilizing spectrophotometry in these applications.

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Most popular questions from this chapter

An analyst would like to measure the concentrations of benzene in ethanol with a spectrophotometer using \(1-\mathrm{cm}\) pathlength cells. Benzene has two characteristic absorption wavelengths at \(204 \mathrm{nm}\) and \(256 \mathrm{nm},\) and ethanol has a minimum usable (cutoff) wavelength at \(220 \mathrm{nm}\). (a) Which absorption wavelength of benzene should be used for the analysis? (b) Which kinds of light source would be ideal for this measurement? (c) What cell material would be used in the spectrophotometer for this analysis?

Nitrate nitrogen in water is determined by reacting with phenoldisulfonic acid to give a yellow color with an absorption maximum at \(410 \mathrm{nm}\). A 100 -mL sample that has been stabilized by adding \(0.8 \mathrm{~mL} \mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{L}\) is treated with silver sulfate to precipitate chloride ion, which interferes. The precipitate is filtered and washed (washings added to filtered sample). The sample solution is adjusted to \(\mathrm{pH} 7\) with dilute \(\mathrm{NaOH}\) and evaporated just to dryness. The residue is treated with \(2.0 \mathrm{~mL}\) phenol disulfonic acid solution and heated in a hot-water bath to aid dissolution. Twenty milliliters distilled water and \(6 \mathrm{~mL}\) ammonia are added to develop the maximum color, and the clear solution is transferred to a 50 -mL volumetric flask and diluted to volume with distilled water. A blank is prepared using the same volume of reagents, starting with the disulfonic acid step. A standard nitrate solution is prepared by dissolving \(0.722 \mathrm{~g}\) anhydrous \(\mathrm{KNO}_{3}\) and diluting to 1 L. A standard addition calibration is performed by spiking a separate 100 -mL portion of sample with \(1.00 \mathrm{~mL}\) of the standard solution and carrying through the entire procedure. The following absorbance readings were obtained: blank, 0.032 ; sample, 0.270 ; sample plus standard, 0.854 . What is the concentration of nitrate nitrogen in the sample in parts per million?

The most widely used wavelength region for infrared analysis is about 2 to \(15 \mu \mathrm{m}\). Express this range in angstroms and in wavenumbers.

What is a necessary criterion for absorption to occur in the infrared region?

Compare the operations of a single-beam spectrophotometer and a double-beam spectrophotometer.

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