Chapter 8: Problem 21
Calculate the \(\mathrm{pH}\) at \(0,25.0,50.0,75.0,100,\) and \(125 \%\) titration in the titration of both protons of the diprotic acid \(\mathrm{H}_{2} \mathrm{~A}\) with \(0.100 \mathrm{M} \mathrm{NaOH}\), starting with \(100 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{H}_{2}\) A. \(K_{a 1}=1.0 \times 10^{-3}, K_{a 2}=1.0 \times 10^{-7}\).
Short Answer
Step by step solution
Determine Initial Moles of Acid
Define Titration Points
Calculate pH at 0% Titration
Calculate pH at 25% Titration
Calculate pH at 50% Titration
Calculate pH at 75% Titration
Calculate pH at 100% Titration
Calculate pH at 125% Titration
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Diprotic Acid
- The first dissociation: \( H_2A \rightarrow H^+ + HA^- \)
- The second dissociation: \( HA^- \rightarrow H^+ + A^{2-} \)
Titration Curve
- The first equivalence point corresponds to the complete neutralization of the first proton, converting \( H_2A \) to \( HA^- \).
- The second equivalence point occurs when \( HA^- \) is fully neutralized to \( A^{2-} \).
- Between these points, buffer regions exist where \( H_2A \) and \( HA^- \), or \( HA^- \) and \( A^{2-} \), coexist.
Buffer Solution
- The Henderson-Hasselbalch equation is often used to calculate the pH of buffer solutions:
- This equation allows us to predict the pH at any point of the buffer section of the titration.
Acid Dissociation Constant (Ka)
- \( K_{a1} \) for the first dissociation \( H_2A \rightarrow H^+ + HA^- \)
- \( K_{a2} \) for the second dissociation \( HA^- \rightarrow H^+ + A^{2-} \)