Chapter 16: Problem 12
Define absorption, absorbance, percent transmittance, and transmittance.
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Chapter 16: Problem 12
Define absorption, absorbance, percent transmittance, and transmittance.
These are the key concepts you need to understand to accurately answer the question.
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A 20 -ppm solution of a DNA molecule (unknown molecular weight) isolated from Escherichia coli was found to give an absorbance of 0.80 in a \(2-\mathrm{cm}\) cell. Calculate the absorptivity of the molecule.
A compound of formula weight 280 absorbed \(65.0 \%\) of the radiation at a certain wavelength in a \(2-\mathrm{cm}\) cell at a concentration of \(15.0 \mu \mathrm{g} / \mathrm{mL} .\) Calculate its molar absorptivity at the wavelength.
Why do acid-base base indicators change color in going from acid to alkaline solution?
Express the wavelength 2500 Ã… in micrometers and nanometers.
Nitrate nitrogen in water is determined by reacting with phenoldisulfonic acid to give a yellow color with an absorption maximum at \(410 \mathrm{nm} .\) A 100 -mL sample that has been stabilized by adding \(0.8 \mathrm{~mL} \mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{L}\) is treated with silver sulfate to precipitate chloride ion, which interferes. The precipitate is filtered and washed (washings added to filtered sample). The sample solution is adjusted to \(\mathrm{pH} 7\) with dilute \(\mathrm{NaOH}\) and evaporated just to dryness. The residue is treated with \(2.0 \mathrm{~mL}\) phenol disulfonic acid solution and heated in a hot-water bath to aid dissolution. Twenty milliliters distilled water and \(6 \mathrm{~mL}\) ammonia are added to develop the maximum color, and the clear solution is transferred to a \(50-\mathrm{mL}\) volumetric flask and diluted to volume with distilled water. A blank is prepared using the same volume of reagents, starting with the disulfonic acid step. A standard nitrate solution is prepared by dissolving \(0.722 \mathrm{~g}\) anhydrous \(\mathrm{KNO}_{3}\) and diluting to \(1 \mathrm{~L} .\) A standard addition calibration is performed by spiking a separate 100 -mL portion of sample with \(1.00 \mathrm{~mL}\) of the standard solution and carrying through the entire procedure. The following absorbance readings were obtained: blank, 0.032 ; sample, 0.270 ; sample plus standard, \(0.854 .\) What is the concentration of nitrate nitrogen in the sample in parts per million?
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