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Prada and colleagues described an indirect method for determining sulfate in natural samples, such as seawater and industrial effluents. \({ }^{12}\) The method consists of three steps: precipitating the sulfate as \(\mathrm{PbSO}_{4}\); dissolving the \(\mathrm{PbSO}_{4}\) in an ammonical solution of excess EDTA to form the soluble \(\mathrm{Pb} \mathrm{Y}^{2-}\) complex; and titrating the excess EDTA with a standard solution of \(\mathrm{Mg}^{2+}\). The following reactions and equilibrium constants are known $$ \begin{array}{ll} \mathrm{PbSO}_{4}(s) \rightleftharpoons \mathrm{Pb}^{2+}(a q)+\mathrm{SO}_{4}^{2-}(a q) & K_{\mathrm{sp}}=1.6 \times 10^{-8} \\ \mathrm{~Pb}^{2+}(a q)+\mathrm{Y}^{4-}(a q) \rightleftharpoons \mathrm{Pb} \mathrm{Y}^{2-}(a q) & K_{\mathrm{f}}=1.1 \times 10^{18} \\ \mathrm{Mg}^{2+}(a q)+\mathrm{Y}^{4-}(a q) \rightleftharpoons \mathrm{Mg} \mathrm{Y}^{2-}(a q) & K_{\mathrm{f}}=4.9 \times 10^{8} \\ \mathrm{Zn}^{2+}(a q)+\mathrm{Y}^{4-}(a q)=\mathrm{Zn} \mathrm{Y}^{2-}(a q) & K_{\mathrm{f}}=3.2 \times 10^{16} \end{array} $$ (a) Verify that a precipitate of \(\mathrm{PbSO}_{4}\) will dissolve in a solution of \(\mathrm{Y}^{4-}\). (b) Sporek proposed a similar method using \(\mathrm{Zn}^{2+}\) as a titrant and found that the accuracy frequently was poor. \(^{13}\) One explanation is that \(\mathrm{Zn}^{2+}\) might react with the \(\mathrm{PbY}^{2-}\) complex, forming \(\mathrm{ZnY}^{2-}\). Show that this might be a problem when using \(\mathrm{Zn}^{2+}\) as a titrant, but that it is not a problem when using \(\mathrm{Mg}^{2+}\) as a titrant. Would such a displacement of \(\mathrm{Pb}^{2+}\) by \(\mathrm{Zn}^{2+}\) lead to the reporting of too much or too little sulfate? (c) In a typical analysis, a 25.00 -mL sample of an industrial effluent is carried through the procedure using \(50.00 \mathrm{~mL}\) of \(0.05000 \mathrm{M}\) EDTA. Titrating the excess EDTA requires \(12.42 \mathrm{~mL}\) of \(0.1000 \mathrm{M}\) \(\mathrm{Mg}^{2+}\). Report the molar concentration of \(\mathrm{SO}_{4}^{2-}\) in the sample of effluent.

Short Answer

Expert verified
(a) PbSO4 dissolves in Y4-. (b) Zn2+ can displace Pb2+, leading to errors; Mg2+ does not. It suggests too much sulfate. (c) [SO42-] = 0.05032 M.

Step by step solution

01

Determining Solubility of PbSO4 in Y4- Solution

To verify if PbSO4 will dissolve in a solution containing Y4-, we need to verify if the reaction \( \mathrm{PbSO}_{4}(s) \rightleftharpoons \mathrm{Pb}^{2+}(aq) + \mathrm{SO}_{4}^{2-}(aq) \) will shift to the right when \( \mathrm{Pb}^{2+}(aq) \) is complexed with \( \mathrm{Y}^{4-} \). The formation constant for \( \mathrm{PbY}^{2-} \) is very large (\( K_f = 1.1 \times 10^{18} \)). Since \( K_{sp} = 1.6 \times 10^{-8} \), the equilibrium is greatly shifted to the right, indicating \( \mathrm{PbSO_{4}} \) will dissolve by forming \( \mathrm{PbY}^{2-} \).
02

Analyzing Potential Reaction of PbY2- with Zn2+

Sporek's method may encounter problems with Zn2+ because \( \mathrm{Zn}^{2+} \) could form \( \mathrm{ZnY}^{2-} \), thus displacing Pb2+ from \( \mathrm{PbY}^{2-} \) complex. The complex formation constant for \( \mathrm{ZnY}^{2-} \) is \( K_f = 3.2 \times 10^{16} \), which is quite significant, though much lower than that for \( \mathrm{PbY}^{2-} \). This could lead to insufficient displacement of \( \mathrm{Y}^{4-} \) for accurate titration. This displacement is not an issue with \( \mathrm{Mg}^{2+} \), as its formation constant \( (4.9 \times 10^8) \) is lower, preventing significant competition for \( \mathrm{Y}^{4-} \).
03

Impact of Zn2+ Displacement Reaction on Sulfate Results

If \( \mathrm{Zn}^{2+} \) displaces \( \mathrm{Pb}^{2+} \) in the \( \mathrm{PbY}^{2-} \) complex, there would be fewer \( \mathrm{Y}^{4-} \) complexed with \( \mathrm{Pb}^{2+} \), leading to inaccurate measurements. More free \( \mathrm{Y}^{4-} \) would remain than expected, which would consume more titrant, suggesting a higher sulfate concentration than actual.
04

Calculating Molar Concentration of SO42-

Firstly, calculate the moles of EDTA used: \( n = C \times V = 0.05000\, \text{M} \times 0.05000\, \text{L} = 0.00250\, \text{mol}\). The moles of \( \mathrm{Mg}^{2+} \) titrant used is \( 0.1000\, \text{M} \times 0.01242\, \text{L} = 0.001242\, \text{mol}\). The moles of EDTA that were not used to complex sulfate ions: \( 0.00250 - 0.001242 = 0.001258\, \text{mol}\). Thus, moles of sulfate is \( 0.001258\, \text{mol} \), and the concentration in \( 0.02500\, \text{L} \): \( \frac{0.001258}{0.02500} = 0.05032\, \text{M} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sulfate Determination
Determining sulfate levels in various samples, such as natural waters and industrial effluents, is crucial for environmental and quality control. Sulfates, particularly in natural samples like seawater, can have significant impacts on the environment and human health. The method described by Prada involves an interesting indirect approach to sulfate determination. This method includes:
  • Precipitating sulfate as lead sulfate (\(\mathrm{PbSO}_4\)).
  • Dissolving this precipitate in an ammoniacal solution with excess ethylenediaminetetraacetic acid (EDTA), leading to the formation of a soluble lead-EDTA complex (\(\mathrm{PbY}^{2-}\)).
  • Finally, titrating the excess EDTA with a standardized magnesium solution.

This approach is robust because the initial precipitation step separates the sulfate ions, allowing for precise interaction with EDTA. The release of lead ions, once the insoluble lead sulfate is dissolved by EDTA, is a key step. It ensures that the sulfate ions are also released and quantified indirectly using the EDTA that is not bound by lead.
Complexometric Titration
Complexometric titration is a type of volumetric analysis widely used to determine the concentration of metal ions in solution. In the context of sulfate determination, EDTA plays a critical role due to its ability to form stable complexes with various metal ions. EDTA acts as a chelating agent, meaning it can bind tightly to metal ions, creating a ring-like structure. This property makes complexometric titration very effective for the measurement of sulfate when lead is involved.
During the process:
  • The dissolved \(\mathrm{PbSO}_4\) reacts with EDTA, forming the complex \(\mathrm{PbY}^{2-}\).
  • Unreacted EDTA is titrated against a \(\mathrm{Mg}^{2+}\) solution.
The advantage of using magnesium over other metals, like zinc, relates to their differing affinities for EDTA, highlighted through their formation constants. Low affinity of magnesium ensures it does not displace lead from \(\mathrm{PbY}^{2-}\), which is essential for maintaining the integrity of the analytical process.
Equilibrium Constants
Equilibrium constants are pivotal parameters in chemical reactions, indicating the extent to which reactants are converted to products. In sulfate determination via complexometric titration, two key equilibrium constants govern the process.
The solubility product constant (\(K_{sp}\)) and the formation constant (\(K_{f}\)) play critical roles:
  • \(K_{sp}\) of lead sulfate (\(\mathrm{PbSO}_4\)), valued at \(1.6 \times 10^{-8}\), suggests low solubility, making the precipitation step effective.
  • \(K_{f}\) of the \(\mathrm{PbY}^{2-}\) complex, at an extraordinary \(1.1 \times 10^{18}\), supports nearly complete chelation of \(\mathrm{Pb}^{2+}\) by EDTA.
Equilibrium constants essentially determine the reaction direction and completion. The notably high \(K_{f}\) for \(\mathrm{PbY}^{2-}\) indicates a strong "pull" driving the dissolution of \(\mathrm{PbSO}_4\) in the presence of EDTA. This efficiency relies on these constants directing the processes towards desirable outcomes, such as precise sulfate quantification.

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Most popular questions from this chapter

The concentration of \(\mathrm{SO}_{2}\) in air is determined by bubbling a sample of air through a trap that contains \(\mathrm{H}_{2} \mathrm{O}_{2} .\) Oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{H}_{2} \mathrm{O}_{2}\) results in the formation of \(\mathrm{H}_{2} \mathrm{SO}_{4}\), which is then determined by titrating with \(\mathrm{NaOH}\). In a typical analysis, a sample of air is passed through the peroxide trap at a rate of \(12.5 \mathrm{~L} / \mathrm{min}\) for \(60 \mathrm{~min}\) and required \(10.08 \mathrm{~mL}\) of \(0.0244 \mathrm{M} \mathrm{NaOH}\) to reach the phenolphthalein end point. Calculate the \(\mu \mathrm{L} / \mathrm{L} \mathrm{SO}_{2}\) in the sample of air. The density of \(\mathrm{SO}_{2}\) at the temperature of the air sample is \(2.86 \mathrm{mg} / \mathrm{mL}\).

Before the introduction of EDTA most complexation titrations used \(\mathrm{Ag}^{+}\) or \(\mathrm{CN}^{-}\) as the titrant. The analysis for \(\mathrm{Cd}^{2+},\) for example, was accomplished indirectly by adding an excess of \(\mathrm{KCN}\) to form \(\mathrm{Cd}(\mathrm{CN})_{4}^{2-}\), and back titrating the excess \(\mathrm{CN}^{-}\) with \(\mathrm{Ag}^{+},\) forming \(\mathrm{Ag}(\mathrm{CN})_{2}^{-} .\) In one such analysis a \(0.3000-\mathrm{g}\) sample of an ore is dissolved and treated with \(20.00 \mathrm{~mL}\) of \(0.5000 \mathrm{M} \mathrm{KCN}\). The excess \(\mathrm{CN}^{-}\) requires \(13.98 \mathrm{~mL}\) of \(0.1518 \mathrm{M} \mathrm{AgNO}_{3}\) to reach the end point. Determine the \(\% \mathrm{w} / \mathrm{w}\) Cd in the ore.

Explain why it is not possible for a sample of water to simultaneously have \(\mathrm{OH}^{-}\) and \(\mathrm{HCO}_{3}^{-}\) as sources of alkalinity.

Calculate or sketch titration curves for the following redox titration reactions at \(25^{\circ} \mathrm{C}\). Assume the analyte initially is present at a concentration of \(0.0100 \mathrm{M}\) and that a \(25.0-\mathrm{mL}\) sample is taken for analysis. The titrant, which is the underlined species in each reaction, has a concentration of \(0.0100 \mathrm{M}\). (a) \(\mathrm{V}^{2+}(a q)+\mathrm{Ce}^{4+}(a q) \longrightarrow \mathrm{V}^{3+}(a q)+\mathrm{Ce}^{3+}(a q)\) (b) \(\mathrm{Sn}^{2+}(a q)+2 \mathrm{Ce}^{4+}(a q) \longrightarrow \mathrm{Sn}^{4+}(a q)+2 \mathrm{Ce}^{3+}(a q)\) (c) \(5 \mathrm{Fe}^{2+}(a q)+\underline{\mathrm{MnO}_{4}^{-}(a q)}+8 \mathrm{H}^{+}(a q) \longrightarrow\) $$ 5 \mathrm{Fe}^{3+}(a q)+\mathrm{Mn}^{2+}(a q)+4 \mathrm{H}_{2} \mathrm{O}(\iota)(\text { at } \mathrm{pH}=1) $$

The concentration of \(\mathrm{CO}\) in air is determined by passing a known volume of air through a tube that contains \(\mathrm{I}_{2} \mathrm{O}_{5}\), forming \(\mathrm{CO}_{2}\) and \(\mathrm{I}_{2}\). The \(\mathrm{I}_{2}\) is removed from the tube by distilling it into a solution that contains an excess of \(\mathrm{KI}\), producing \(\mathrm{I}_{3}^{-}\). The \(\mathrm{I}_{3}^{-}\) is titrated with a standard solution of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\). In a typical analysis a 4.79 - \(\mathrm{L}\) sample of air is sampled as described here, requiring \(7.17 \mathrm{~mL}\) of \(0.00329 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) to reach the end point. If the air has a density of \(1.23 \times 10^{-3} \mathrm{~g} / \mathrm{mL},\) determine the parts per million CO in the air.

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