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Baldwin and co-workers report the following data from a cyclic voltammetry study of the electrochemical behavior of \(p\) -phenylenediamine in a \(\mathrm{pH} 7\) buffer \(^{32}\) All potentials are measured relative to an \(\mathrm{SCE}\). \begin{tabular}{rcccc} scan rate \((\mathrm{mV} / \mathrm{s})\) & \(E_{\mathrm{p}, \mathrm{a}}(\mathrm{V})\) & \(E_{\mathrm{p}, \mathrm{C}}(\mathrm{V})\) & \(i_{\mathrm{p}, \mathrm{a}}(\mathrm{mA})\) & \(i_{\mathrm{p}, \mathrm{C}}(\mathrm{mA})\) \\ \hline 2 & 0.148 & 0.104 & 0.34 & 0.30 \\ 5 & 0.149 & 0.098 & 0.56 & 0.53 \\ 10 & 0.152 & 0.095 & 1.00 & 0.94 \\ 20 & 0.161 & 0.095 & 1.44 & 1.44 \\ 50 & 0.167 & 0.082 & 2.12 & 1.81 \\ 100 & 0.180 & 0.063 & 2.50 & 2.19 \end{tabular} The initial scan is toward more positive potentials, leading to the oxidation reaction shown here. Use this data to show that the reaction is electrochemically irreversible. A reaction may show electrochemical irreversibility because of slow electron transfer kinetics or because the product of the oxidation reaction participates in a chemical reaction that produces an nonelectroactive species. Based on the data in this problem, what is the likely source of \(p\) -phenylenediamine's electrochemical irreversibility?

Short Answer

Expert verified
The reaction shows electrochemical irreversibility likely due to slow electron transfer kinetics, as indicated by peak separation and current ratio.

Step by step solution

01

Understanding Irreversibility in Cyclic Voltammetry

Electrochemical irreversibility in cyclic voltammetry often occurs when there are large differences in peak potentials ( E_{ ext{pa}} and E_{ ext{pc}} ) and unequal peak current intensities ( i_{ ext{pa}} and i_{ ext{pc}} ). Let's analyze the data to check for these indicators.
02

Analyzing Peak Potential Differences

Calculate the difference in peak potentials, E_{ ext{pa}} - E_{ ext{pc}} , for each scan rate. Large differences indicate irreversibility. For instance, at 2 mV/s, E_{ ext{pa}} - E_{ ext{pc}} = 0.148 - 0.104 = 0.044 ext{ V} . Repeat for other scan rates.
03

Comparing Peak Current Ratios

Evaluate the ratio of peak currents, i_{ ext{pc}}/i_{ ext{pa}} , for each scan rate. A ratio significantly different from 1 indicates irreversibility. For example, at 2 mV/s, i_{ ext{pc}}/i_{ ext{pa}} = 0.30/0.34 = 0.8824 . Continue this calculation for other scan rates.
04

Interpreting the Differences

Observe that both peak potential differences and peak current ratios suggest potential issues with reversibility. Since E_{ ext{pa}} - E_{ ext{pc}} increases with scan rate and i_{ ext{pc}}/i_{ ext{pa}} deviates from 1, this suggests the irreversibility is due to slow electron transfer or a related chemical reaction.
05

Identify the Source of Irreversibility

Based on the observed peak separation and current inequalities, the electrochemical irreversibility is likely caused by slow electron transfer kinetics rather than a subsequent chemical reaction, as the product species is not significantly altering the electroactivity between scans.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrochemical Irreversibility
Electrochemical irreversibility often occurs in electrochemical reactions when there is a noticeable deviation from ideal behavior observed in cyclic voltammetry. In a reversible system, the forward and reverse reactions occur at similar rates and are well-defined. However, in an electrochemically irreversible system, this balance is disrupted. This imbalance is usually characterized by large differences in peak potentials, denoted as \( E_{p,a} - E_{p,c} \), and by unequal peak current intensities, \( i_{p,a} \) and \( i_{p,c} \).
  • In a reversible reaction, the peak potential difference \( E_{p,a} - E_{p,c} \) should ideally be close to zero.
  • The ratio of peak currents \( i_{p,c}/i_{p,a} \) should be close to 1.

When either of these conditions is not met, it suggests that the reaction does not revert to its original state effectively, indicating irreversibility. For example, in the analysis of \( p \)-phenylenediamine, both observed peak separations and current ratios suggest that the reaction is not following ideal reversible electrochemical behavior.
Peak Potential Difference
The peak potential difference in cyclic voltammetry, \( E_{p,a} - E_{p,c} \), serves as a key indicator of reversibility or irreversibility of an electrochemical reaction. In a reversible system, the peaks occur at a close potential value, typically within a few millivolts, due to the symmetric nature of forward and reverse reactions. However, differences become pronounced in irreversible or quasi-reversible systems.

As we analyze the example of \( p \)-phenylenediamine, we observe:
  • At a scan rate of 2 mV/s, the peak potential difference is 0.044 V.
  • Increasing the scan rate to 100 mV/s raises this difference to 0.117 V.

These growing differences highlight the departure from ideality, signaling that we are encountering electrochemical irreversibility. The noticeable increase in difference with scan rate indicates the reaction kinetics might be slow, as the system does not allow sufficient time for electron transfer to reach completion at higher rates, leading to larger separations between the peaks.
Slow Electron Transfer Kinetics
In cyclic voltammetry, slow electron transfer kinetics often lead to a non-ideal behavior, suggesting electrochemical irreversibility. Electron transfer kinetics refer to the rate at which electrons are exchanged between the electrode and the species in solution during the electrochemical reaction.

When electron transfer kinetics are slow, the system cannot rapidly achieve equilibrium, resulting in peak potentials moving apart as the scan rate increases. This is evident in the study of \( p \)-phenylenediamine:
  • At 2 mV/s, the peak separation is 0.044 V.
  • At 100 mV/s, it is 0.117 V.
Such growing peak separations suggest that the system is struggling to maintain equilibrium quickly as the scan rate increases. The increasing differences in peak potential with scan rate and the deviation in peak current ratios are clear signs of an electron transfer process hindered by kinetic limitations.

Ultimately, these kinetic constraints manifest as electrochemical irreversibility, where the slowness in electron transfer rates prevents the establishment of true reversibility under the given experimental conditions.

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Most popular questions from this chapter

Sittampalam and Wilson described the preparation and use of an amperometric sensor for glucose. \(^{27}\) The sensor is calibrated by measuring the steady- state current when it is immersed in standard solutions of glucose. A typical set of calibration data is shown here. \begin{tabular}{cc} [glucose] \((\mathrm{mg} / 100 \mathrm{~mL})\) & current (arb. units) \\ \hline 2.0 & 17.2 \\ 4.0 & 32.9 \\ 6.0 & 52.1 \\ 8.0 & 68.0 \\ 10.0 & 85.8 \end{tabular} A \(2.00-\mathrm{mL}\) sample is diluted to \(10 \mathrm{~mL}\) in a volumetric flask and a steady-state current of 23.6 (arbitrary units) is measured. What is the concentration of glucose in the sample in \(\mathrm{mg} / 100 \mathrm{~mL}\) ?

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Explain why each of the following decreases the analysis time in controlled- potential coulometry: a larger surface area for the working electrode; a smaller volume of solution; and a faster stirring rate.

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The concentration of \(\mathrm{Cu}^{2+}\) in seawater is determined by anodic stripping voltammetry at a hanging mercury drop electrode after first releasing any copper bound to organic matter. To a \(20.00-\mathrm{mL}\) sample of seawater is added \(1 \mathrm{~mL}\) of \(0.05 \mathrm{M} \mathrm{HNO}_{3}\) and \(1 \mathrm{~mL}\) of \(0.1 \% \mathrm{H}_{2} \mathrm{O}_{2} .\) The sample is irradiated with UV light for \(8 \mathrm{hr}\) and then diluted to volume in a \(25-\mathrm{mL}\) volumetric flask. Deposition of \(\mathrm{Cu}^{2+}\) takes place at \(-0.3 \mathrm{~V}\) versus an SCE for 10 min, producing a peak current of 26.1 (arbitrary units). A second \(20.00-\mathrm{mL}\) sample of the seawater is treated identically, except that \(0.1 \mathrm{~mL}\) of a \(5.00 \mu \mathrm{M}\) solution of \(\mathrm{Cu}^{2+}\) is added, producing a peak current of 38.4 (arbitrary units). Report the concentration of \(\mathrm{Cu}^{2+}\) in the seawater in \(\mathrm{mg} / \mathrm{L}\)

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