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Ratana-ohpas and co-workers described a stripping analysis method for determining tin in canned fruit juices. \(^{26}\) Standards of \(50.0 \mathrm{ppb} \mathrm{Sn}^{4+}\) \(100.0 \mathrm{ppb} \mathrm{Sn}^{4+}\), and \(150.0 \mathrm{ppb} \mathrm{Sn}^{4+}\) were analyzed giving peak currents (arbitrary units) of \(83.0,171.6,\) and \(260.2,\) respectively. A 2.00 \(\mathrm{mL}\) sample of lychee juice is mixed with \(20.00 \mathrm{~mL}\) of \(1: 1 \mathrm{HCl} / \mathrm{HNO}_{3} .\) A \(0.500-\mathrm{mL}\) portion of this mixture is added to \(10 \mathrm{~mL}\) of \(6 \mathrm{M} \mathrm{HCl}\) and the volume adjusted to \(30.00 \mathrm{~mL}\). Analysis of this diluted sample gave a signal of 128.2 (arbitrary units). Report the parts-per-million \(\mathrm{Sn}^{4+}\) in the original sample of lychee juice.

Short Answer

Expert verified
The concentration of \(\mathrm{Sn}^{4+}\) in the original lychee juice is 4.524 ppm.

Step by step solution

01

Establish a Calibration Curve

First, we need to use the provided standards and their respective peak currents to establish a linear calibration curve. These standards are: \(50.0\, \mathrm{ppb} : 83.0\), \(100.0\, \mathrm{ppb} : 171.6\), and \(150.0\, \mathrm{ppb} : 260.2\). Plot these points on a graph with peak current (arbitrary units) on the y-axis and concentration (ppb) on the x-axis.
02

Determine the Equation of the Calibration Line

Using the linear relationship, calculate the equation in the form \( y = mx + c \) where \( y \) is the peak current, \( x \) is the concentration, \( m \) is the slope, and \( c \) is the y-intercept. Using two data points, calculate \( m \) and \( c \): \( m = \frac{171.6 - 83.0}{100 - 50} = 1.77,\)and substituting in one point to find \( c: \(171.6 = 1.77 \cdot 100 + c \, \Rightarrow \, c = -5.4.\) \).Thus, the equation is \( y = 1.77x - 5.4 \).
03

Find Concentration of Sample

Use the equation from the calibration curve to determine the tin concentration in the diluted sample using its peak current, 128.2: \(128.2 = 1.77x - 5.4 \).Solve for \( x \) to find: \( x = \frac{128.2 + 5.4}{1.77} \approx 75.4 \, \mathrm{ppb}.\)
04

Adjust for Dilution Factor

The 0.500 mL portion used for analysis was from an initial mixture where a 2.00 mL sample of juice was taken. Adjust for dilution by considering the ratio of total diluted solution to the original sample : \(\text{Concentration in juice} = 75.4 \, \mathrm{ppb} \times \frac{30.00 \mathrm{mL}}{0.500 \mathrm{mL}} = 4524 \, \mathrm{ppb}.\)
05

Convert to Parts-Per-Million

The concentration is currently in parts-per-billion (ppb). To convert to parts-per-million (ppm), divide by 1000: \(4524 \, \mathrm{ppb} = \frac{4524}{1000} = 4.524 \, \mathrm{ppm}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calibration Curve
To understand stripping analysis, one must first grasp the concept of a calibration curve. A calibration curve is a graphical method used to determine the concentration of a substance in a sample by comparing it to known standards. It consists of plotting a series of known concentrations of a substance against the measured response of a detection method, such as peak current in this case. For the exercise involving tin (Sn), these known concentrations are plotted against their corresponding peak currents, allowing us to depict a linear relationship that helps in quantitatively assessing unknown samples. Here you use standards of 50.0, 100.0, and 150.0 ppb, resulting in peak currents of 83, 171.6, and 260.2 arbitrary units, respectively. The visualization of this data as a curve enables straightforward determination of unknown concentrations using the line equation of the plot.
Dilution Factor
When analyzing samples, often they are not in a state that is ideal for direct analysis, and hence, a process of dilution is applied. The dilution factor describes the ratio by which the original sample's concentration has been reduced to achieve the desired concentration for analysis. In this exercise, you start with a 2.00 mL sample of lychee juice, dilute it first with 20.00 mL of an acid mixture, and then take 0.500 mL of this to dilute further up to a total volume of 30.00 mL. This step scales up the measurement sensitivity for a more accurate analysis. The total dilution factor can be calculated from the ratio of total solution volume to the original sample volume, helping you adjust the measured concentration back to its original concentration state.
Tin Concentration
The main aim of the exercise is to find out the tin concentration in lychee juice using the derived calibration curve. After obtaining the peak current for the sample - 128.2 arbitrary units - you can substitute this value into the line equation derived from the calibration curve to find out the corresponding concentration in parts-per-billion (ppb). This step is crucial because it translates the experimental readings into meaningful scientific data reflecting the concentration levels present in the original sample, before any dilution was applied.
Parts-Per-Billion
Parts-per-billion (ppb) is a unit expressing concentration, often used in contexts involving trace elements. It is defined as the number of units of mass of a contaminant per 1,000,000,000 units of total mass, which makes it extremely precise for small concentrations. In this exercise, after determining the concentration of tin using peak current readings, the data is initially expressed in ppb. This provides a detailed view of the tiny amounts of tin present, helping identify trace elements that might otherwise go unnoticed at higher concentrational scales. Converting this into parts-per-million (ppm) at a later stage helps when larger concentration scales are more meaningful or required.
Line Equation in Analytical Chemistry
The line equation is fundamental in analytical chemistry for determining unknown concentrations. With the calibration curve established, the relationship between known concentrations and their detected signals is mathematically expressed as a linear equation in the form of \[ y = mx + c \]. Here, \( y \) represents the peak current, \( x \) is the concentration, \( m \) is the slope of the line, indicating how much the signal changes per unit increase in concentration, and \( c \) is the y-intercept, which tells what the baseline signal is when there's no substance present. For the tin quantification exercise, calculating a slope \( m \) of 1.77 and a y-intercept \( c \) of -5.4, allows you to solve for unknowns based on intercepting known coordinates from the plotted standards. This equation gives power to convert experimental readings into precise chemical quantities.

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Most popular questions from this chapter

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