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A chemical deviation to Beer's law may occur if the concentration of an absorbing species is affected by the position of an equilibrium reaction. Consider a weak acid, HA, for which \(K_{\mathrm{a}}\) is \(2 \times 10^{-5}\). Construct Beer's law calibration curves of absorbance versus the total concentration of weak acid \(\left(C_{\text {total }}=[\mathrm{HA}]+\left[\mathrm{A}^{-}\right]\right),\) using values for \(C_{\text {total }}\) of \(1.0 \times 10^{-5}, 3.0 \times 10^{-5}, 5.0 \times 10^{-5}, 7.0 \times 10^{-5}, 9.0 \times 10^{-5}, 11 \times 10^{-5}\), and \(13 \times 10^{-5} \mathrm{M}\) for the following sets of conditions and comment on your results: (a) \(\varepsilon_{\mathrm{HA}}=\varepsilon_{\mathrm{A}^{-}}=2000 \mathrm{M}^{-1} \mathrm{~cm}^{-1} ;\) unbuffered solution. (b) \(\varepsilon_{\mathrm{HA}}=2000 \mathrm{M}^{-1} \mathrm{~cm}^{-1} ; \varepsilon_{\mathrm{A}^{-}}=500 \mathrm{M}^{-1} \mathrm{~cm}^{-1} ;\) unbuffered solution. (c) \(\varepsilon_{\mathrm{HA}}=2000 \mathrm{M}^{-1} \mathrm{~cm}^{-1} ; \varepsilon_{\mathrm{A}^{-}}=500 \mathrm{M}^{-1} \mathrm{~cm}^{-1} ;\) solution buffered to a \(\mathrm{pH}\) of 4.5 Assume a constant pathlength of \(1.00 \mathrm{~cm}\) for all samples.

Short Answer

Expert verified
The calibration curves show varying slopes; buffering stabilizes deviations.

Step by step solution

01

Understanding the Equilibrium

For a weak acid HA, it dissociates into H+ and A- according to: \[\mathrm{HA} \rightleftharpoons \mathrm{H}^{+} + \mathrm{A}^{-}\] The equilibrium constant \(K_a\) is given as \(2 \times 10^{-5}\). This determines the concentrations of \(\mathrm{HA}, \mathrm{H}^{+},\) and \(\mathrm{A}^{-}\).
02

Calculate Concentrations for HA and A鈦

Use the expression for the equilibrium constant:\[K_a = \frac{[\mathrm{H}^{+}][\mathrm{A}^{-}]}{[\mathrm{HA}]}\]Assuming that \([\mathrm{H}^{+}] = x\), we have:\[K_a = \frac{x^2}{C_\mathrm{total} - x}\] Now, solve for \(x\) to get concentrations \([\mathrm{HA}] = C_\mathrm{total} - x\) and \([\mathrm{A}^{-}] = x\).
03

Calculate Absorbance for Unbuffered Solution with Same 蔚

For part (a), where \(\varepsilon_{\mathrm{HA}} = \varepsilon_{\mathrm{A}^{-}} = 2000\):The total absorbance \(A\) is:\[A = \varepsilon_{\mathrm{HA}} [\mathrm{HA}] + \varepsilon_{\mathrm{A}^{-}} [\mathrm{A}^{-}]\]Since \(\varepsilon_{\mathrm{HA}} = \varepsilon_{\mathrm{A}^{-}}\):\[A = 2000(C_{total})\]The absorbance is directly proportional to \(C_{total}\).
04

Calculate Absorbance with Different 蔚 Values

For part (b), where \(\varepsilon_{\mathrm{HA}} = 2000\) and \(\varepsilon_{\mathrm{A}^{-}} = 500\):\[A = 2000([\mathrm{HA}]) + 500([\mathrm{A}^{-}])\]Substitute \([\mathrm{HA}] = C_{total} - x\) and \([\mathrm{A}^{-}] = x\) from Step 2, to calculate the different absorbance values for each \(C_{total}\).
05

Calculate pH for Buffered Solution and Adjust Concentrations

For part (c), using Henderson-Hasselbalch equation:\[ \text{pH} = \text{pK}_a + \log \left(\frac{[\mathrm{A}^{-}]}{[\mathrm{HA}]}\right) = 4.5 \]Calculate \([\mathrm{HA}]\) and \([\mathrm{A}^{-}]\) using the pH value. Then check if equilibrium concentrations are significantly affected. If not, use \([\mathrm{HA}] = C_{total]\) and find absorbance as before: \[A = 2000([\mathrm{HA}]) + 500([\mathrm{A}^{-}])\]
06

Analyze and Compare Results for Each Scenario

Compare the slope of the calibration curves from each condition. (a) When \(\varepsilon_{\mathrm{HA}} = \varepsilon_{\mathrm{A}^{-}}\), the slope is constant. (b) When \(\varepsilon_{\mathrm{HA}} eq \varepsilon_{\mathrm{A}^{-}}\), the slope varies slightly due to the influence of weak acid dissociation. (c) Buffering minimizes deviations, making the calibration curve more consistent with Beer's law.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
In chemistry, equilibrium refers to the point where the concentrations of reactants and products remain constant over time in a reversible reaction. For a weak acid, such as HA, it dissociates into H鈦 ions and A鈦 ions. This dissociation reaches a chemical equilibrium, represented by the reaction \(\mathrm{HA} \rightleftharpoons \mathrm{H}^{+} + \mathrm{A}^{-}\). The equilibrium constant (\(K_a\)) for this process is a key factor. It quantifies the balance between the reactants and products at equilibrium.
The equilibrium constant \(K_a\) is expressed as:
\[K_a = \frac{[\mathrm{H}^{+}][\mathrm{A}^{-}]}{[\mathrm{HA}]}\]
Thus, knowing \(K_a\) helps determine the concentrations of HA, H鈦, and A鈦 in solution. In this exercise, \(K_a = 2 \times 10^{-5}\), indicating that the weak acid partially dissociates. Understanding chemical equilibrium is vital in predicting the behavior of weak acids in different conditions and in constructing accurate calibration curves.
Weak Acids
Weak acids are classified by their ability to partially dissociate into ions in solution, unlike strong acids which fully dissociate. The partial dissociation is represented by an equilibrium constant parameter \(K_a\).
Because of their incomplete dissociation, weak acids have both the undissociated acid (HA) and its ions (H鈦 and A鈦) present in the solution. This partial ionization is crucial for the calculation of species concentrations when dealing with absorbance and calibration curves.
Common examples of weak acids include acetic acid (CH鈧僀OOH) and formic acid (HCOOH). In scenarios like Beer's law exercises, understanding the weak acid鈥檚 dissociation allows for accurate calculations of pH and equilibrium concentrations. It also impacts the absorbance in spectrophotometric measurements, especially when the molar absorptivity of the acid and its conjugate base differ.
Absorbance Calculation
The absorbance of a solution indicates how much light is absorbed as it passes through the solution. According to Beer's Law, absorbance depends on the molar absorptivity (蔚), the path length of light through the solution (usually in cm), and the concentration of the absorbing species.
The formula is expressed as:
\[ A = \varepsilon l c \]
where:
  • \(A\) is absorbance
  • \(\varepsilon\) is molar absorptivity
  • \(l\) is the path length
  • \(c\) is the concentration of the absorbing species

In unbuffered solutions where \(\varepsilon_{\mathrm{HA}} = \varepsilon_{\mathrm{A}^{-}}\), the absorbance is directly proportional to concentration. However, when \(\varepsilon_{\mathrm{HA}} eq \varepsilon_{\mathrm{A}^{-}}\), the different absorptivities play a crucial role in the absorbance calculation, as seen in parts (b) and (c) of the exercise.
Calibration Curves
Calibration curves are graphical representations that show the relationship between the concentration of a substance and the absorbance of light at a specific wavelength. By plotting absorbance versus concentration, one can determine the concentration of an unknown sample based on its absorbance.
When plotting a calibration curve for a weak acid in water, different conditions such as buffering and variances in molar absorptivity need to be considered. In the exercise, three different conditions were explored:
  • When \(\varepsilon_{\mathrm{HA}} = \varepsilon_{\mathrm{A}^{-}}\), a direct relationship is maintained, providing a straight-line calibration curve.
  • If \(\varepsilon_{\mathrm{HA}} eq \varepsilon_{\mathrm{A}^{-}}\), the slope changes because of the varying contributions of HA and A鈦 to the absorbance.
  • A buffered solution at a given pH stabilizes equilibrium and results in a more predictable calibration curve, closer to ideal linearity.
Calibration curves are fundamental tools necessary for accurately quantitative analysis in laboratories, specifically when dealing with weak acids subjected to varying conditions.

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Most popular questions from this chapter

Selenium (IV) in natural waters is determined by complexing with ammonium pyrrolidine dithiocarbamate and extracting into \(\mathrm{CHCl}_{3}\). This step serves to concentrate the \(\mathrm{Se}(\mathrm{IV})\) and to separate it from \(\mathrm{Se}(\mathrm{VI})\). The \(\mathrm{Se}(\mathrm{IV})\) is then extracted back into an aqueous matrix using \(\mathrm{HNO}_{3} .\) After complexing with 2,3 -diaminonaphthalene, the complex is extracted into cyclohexane. Fluorescence is measured at \(520 \mathrm{nm}\) following its excitation at \(380 \mathrm{nm}\). Calibration is achieved by adding known amounts of \(\mathrm{Se}(\mathrm{IV})\) to the water sample before beginning the analysis. Given the following results what is the concentration of \(\mathrm{Se}(\mathrm{IV})\) in the sample. \begin{tabular}{cc} {\([\) Se (IV)] added (nM) } & emission intensity \\ \hline 0.00 & 323 \\ 2.00 & 597 \\ 4.00 & 862 \\ 6.00 & 1123 \end{tabular}

EDTA forms colored complexes with a variety of metal ions that may serve as the basis for a quantitative spectrophotometric method of analysis. The molar absorptivities of the EDTA complexes of \(\mathrm{Cu}^{2+}, \mathrm{Co}^{2+}\), and \(\mathrm{Ni}^{2+}\) at three wavelengths are summarized in the following table (all values of \(\varepsilon\) are in \(\left.\mathrm{M}^{-1} \mathrm{~cm}^{-1}\right).\) $$ \begin{array}{cccc} \text { metal } & \varepsilon_{462.9} & \varepsilon_{732.0} & \varepsilon_{378.7} \\ \hline \mathrm{Co}^{2+} & 15.8 & 2.11 & 3.11 \\ \mathrm{Cu}^{2+} & 2.32 & 95.2 & 7.73 \\ \mathrm{Ni}^{2+} & 1.79 & 3.03 & 13.5 \end{array} $$ Using this information determine the following: (a) The concentration of \(\mathrm{Cu}^{2+}\) in a solution that has an absorbance of 0.338 at a wavelength of \(732.0 \mathrm{nm}\). (b) The concentrations of \(\mathrm{Cu}^{2+}\) and \(\mathrm{Co}^{2+}\) in a solution that has an absorbance of 0.453 at a wavelength of \(732.0 \mathrm{nm}\) and 0.107 at a wavelength of \(462.9 \mathrm{nm}\) (c) The concentrations of \(\mathrm{Cu}^{2+}, \mathrm{Co}^{2+},\) and \(\mathrm{Ni}^{2+}\) in a sample that has an absorbance of 0.423 at a wavelength of \(732.0 \mathrm{nm}, 0.184\) at a wavelength of \(462.9 \mathrm{nm}\), and 0.291 at a wavelength of \(378.7 \mathrm{nm}\). The pathlength, \(b\), is \(1.00 \mathrm{~cm}\) for all measurements.

The concentration of acetylsalicylic acid, \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4},\) in aspirin tablets is determined by hydrolyzing it to the salicylate ion, \(\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{O}_{2}^{-},\) and determining its concentration spectrofluorometrically. A stock standard solution is prepared by weighing \(0.0774 \mathrm{~g}\) of salicylic acid, \(\mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}_{2}\), into a 1-L volumetric flask and diluting to volume. A set of calibration standards is prepared by pipeting \(0,2.00,4.00,6.00,8.00,\) and 10.00 \(\mathrm{mL}\) of the stock solution into separate \(100-\mathrm{mL}\) volumetric flasks that contain \(2.00 \mathrm{~mL}\) of \(4 \mathrm{M} \mathrm{NaOH}\) and diluting to volume. Fluorescence is measured at an emission wavelength of \(400 \mathrm{nm}\) using an excitation wavelength of \(310 \mathrm{nm}\) with results shown in the following table. $$ \begin{array}{cc} \text { mL of stock solution } & \text { emission intensity } \\ \hline 0.00 & 0.00 \\ 2.00 & 3.02 \\ 4.00 & 5.98 \\ 6.00 & 9.18 \\ 8.00 & 12.13 \\ 10.00 & 14.96 \end{array} $$ Several aspirin tablets are ground to a fine powder in a mortar and pestle. A 0.1013 -g portion of the powder is placed in a 1-L volumetric flask and diluted to volume with distilled water. A portion of this solution is filtered to remove insoluble binders and a 10.00 -mL aliquot transferred to a 100 -mL volumetric flask that contains \(2.00 \mathrm{~mL}\) of \(4 \mathrm{M}\) \(\mathrm{NaOH}\). After diluting to volume the fluorescence of the resulting solution is 8.69 . What is the \(\% \mathrm{w} / \mathrm{w}\) acetylsalicylic acid in the aspirin tablets?

In the DPD colorimetric method for the free chlorine residual, which is reported as \(\mathrm{mg} \mathrm{Cl}_{2} / \mathrm{L},\) the oxidizing power of free chlorine converts the colorless amine \(\mathrm{N}, \mathrm{N}\) -diethyl- \(p\) -phenylenediamine to a colored dye that absorbs strongly over the wavelength range of \(440-580 \mathrm{nm}\). Analysis of a set of calibration standards gave the following results. $$ \begin{array}{cc} \mathrm{mg} \mathrm{Cl}_{2} / \mathrm{L} & \text { absorbance } \\ \hline 0.00 & 0.000 \\ 0.50 & 0.270 \\ 1.00 & 0.543 \\ 1.50 & 0.813 \\ 2.00 & 1.084 \end{array} $$ A sample from a public water supply is analyzed to determine the free chlorine residual, giving an absorbance of \(0.113 .\) What is the free chlorine residual for the sample in \(\mathrm{mg} \mathrm{Cl}_{2} / \mathrm{L}\) ?

Saito describes a quantitative spectrophotometric procedure for iron based on a solid-phase extraction using bathophenanthroline in a poly(vinyl chloride) membrane. \({ }^{22}\) In the absence of \(\mathrm{Fe}^{2+}\) the membrane is colorless, but when immersed in a solution of \(\mathrm{Fe}^{2+}\) and \(\mathrm{I}^{-},\) the membrane develops a red color as a result of the formation of an \(\mathrm{Fe}^{2+}\) -bathophenanthroline complex. A calibration curve determined using a set of external standards with known concentrations of \(\mathrm{Fe}^{2+}\) gave a standardization relationship of $$ A=\left(8.60 \times 10^{3} \mathrm{M}^{-1}\right) \times\left[\mathrm{Fe}^{2+}\right] $$ What is the concentration of iron, in \(\mathrm{mg} \mathrm{Fe} / \mathrm{L},\) for a sample with an absorbance of 0.100 ?

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