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Depending on the osmotic pressure of the medium in which it is placed, a red blood cell will experience crenation, hemolysis, or no change.

Because there is an equal flow of water in and out of a red blood cell in an isotonic solution, the cell preserves its volume. A solution and a $5\%(m/v)$glucose solution serve as isotonic solutions.

Water rushes into red blood cells when they are placed in a solution, causing them to inflate and burst. Hemolysis is the name for this process. The amount of solute in a hypotonic solution is lower.

Water leaves a red blood cell when it is added to the solution, leading it to shrink. Crenation is the term for this procedure. The amount of solute in a hypertonic solution is higher.

The form of a red blood cell in isotonic, hypotonic, and hypertonic solutions is depicted in the diagram below:

Isotonicity is defined as a $0.9\%(m/v)NaCl$solution. As a result, a red blood cell will remain unchanged. As a result, the diagram depicting the form of a red blood cell in a $0.9\%(m/v)NaCl$solution is

(b) In comparison to a $5\%(m/v)$glucose solution, a $10\%(m/v)$glucose solution has a larger solute concentration. As a result, a $10\%(m/v)$glucose solution is hypertonic. A red blood cell will crenate as a result.

As a result, the diagram depicting the form of a red blood cell in a$10\%(m/v)$glucose solution is.

(c) When contrasted to a $0.9\%(m/v)NaCl$solution, a $0.01\%(m/v)NaCl$answer has a lower osmotic pressure. As a result, a $NaCl$solution of $0.01\%(m/v)$is hypotonic. As a result, hemolysis occurs in a red blood cell.

Therefore, the diagram that represents the shape of a red blood cell when placed in a $0.01\%(m/v)NaCl$solution is

(d) A glucose solution containing $5\%(m/v)$glucose is isotonic. As a result, a red blood cell will stay unchanged.

As a corollary, the image showing the size of a red blood cell in a $5\%(m/v)$glucose solution is as follows:

(e) When opposed to a $5\%(m/v)$glucose solution, a $1\%(m/v)$sucrose solution has a lower osmotic pressure. A $1\%(m/v)$glucose solution is therefore hypotonic. As a result, hemolysis develops in a red blood cell.

As a result, the diagram illustrating the form of a red blood cell in a $1\%(m/v)$glucose solution is.