Q. 9.70 Will a red blood cell undergo cr... [FREE SOLUTION]

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Chapter 9: Q. 9.70 (page 313)

Will a red blood cell undergo crenation, hemolysis, or no change in each of the following solutions?
a. $1 % (m / v)$ glucose
b. $2 % (m / v) N a C l$
c. $5 % (m / v)$ glucose
d. $0.1 % (m / v) N a C l$

Short Answer

Expert verified

(part a) The following solution $1 % (m / v)$ glucose undergoes Hemolysis.

(part b) The following solution $2 % (m / v) N a C l$ ,The red blood cell will crenation.

(part c) The following solution $5 % (m / v)$ glucose. There is no change in this solution.

(part d) The following solution $0.1 % (m / v) N a C l$ . This solution leads to Hemolysis.

Step by step solution

Introduction (part a).

A red blood cell maintains its quantity in an electrolyte as there is an equal stream of fluid into and out of cell. Isotonic solutions have included a $0.9 % (m / v) N a C l$ solution and a $5 % (m / v)$ glucose solution.
When a red blood cell is submersed in a hypotonic, water enters the cell and causes it to expand and burst. This is known as hemolysis. The solute concentration in a hypotonic solution is lower.
When a red blood cell is positioned in a hypertonic solution, moisture escapes, causing the cell to shrink. This is known as crenation. A hypertonic has a higher concentration of solutes.

Given Information (part a).

Given:

$1 % (m / v)$ glucose.

Explanation (part a).

A $1 % (m / v)$ glucose solution does have a lower osmotic pressure than a $5 % (m / v)$ glucose solution. As just a result, a $1 % (m / v)$ glucose solution is hypotonic. As a result, a red blood cell will be hemolyzed.

Given Information (part b).

Given:

$2 % (m / v) N a C l$

Explanation (part b).

A $2 % (m / v) N a C l$ solution contains more solutes than a $0.9 % (m / v) N a C l$ solution. As a result, a $2 % (m / v) N a C l$ solution is hypertonic. As a result, a red blood cell would then crenate.

Given Information (part c).

Given:

5 % (m / v)

glucose.

Explanation (part c).

A $5 % (m / v)$ sucrose solution is isotonic. Therefore, a red blood cell will remain unchanged.

Given Information (part d).

Given:

0.1 % (m / v) N a C l

Explanation (part d).

A $0.1 % (m / v) N a C l$ solution contains less solute than a $0.9 % (m / v) N a C l$ solution. As a result, a $0.1 % (m / v) N a C l$ solution is hypotonic. As a result, a red blood cell will be hemolyzed.